docopt

How to prevent command line args from being interpreted by R vs. only by my script?

余生颓废 提交于 2019-12-22 05:12:01
问题 I'm using the docopt implementation for R. My script has a command line option where the short form is -g . When I run my script, it seems this argument is first interpreted by R and then by my script. Therefore I get a wrist slap about not specifying a value for the GUI. Can I prevent R from trying to work with these command line args? Example of a script: #!/usr/bin/Rscript suppressPackageStartupMessages(library(docopt)) "docopt practice script Usage: foo.R [-g <goodies>] Options: -g

Docopt: options after repeating elements are interpeted as repeating elements

廉价感情. 提交于 2019-12-13 11:42:16
问题 I am using docopt in my simple Python program: #!/usr/bin/env python """ Farmers market Usage: farmersmarket.py buy -i <item> -q <quantity> [<quantity>] [-p <price>] [-dvh] farmersmarket.py -d | --debug farmersmarket.py -v | --version farmersmarket.py -h | --help Options: -i --item Item. -q --quantity Quantity. -p --price Price. -d --debug Show debug messages. -h --help Show this screen. -v --version Show version. """ from docopt import docopt print docopt(__doc__) If I run: farmersmarket.py

Why are defaults not appearing in my command-line argument dictionary from docopt?

◇◆丶佛笑我妖孽 提交于 2019-12-05 10:08:23
I've been trying to use docopt to make a simple CLI, but for some reason my default parameters are not appearing. Below is my test code. I am using the latest version of docopt.py from the github repository. """ Usage: scrappy <path> ... [options] -a --auto Automatically scrape and rename without user interaction. -l --lang Specify language code [default: en]. --scan-individual Evaluate series information individually for each file. -c --cfg User alternate config file [default: ../scrappy.conf] -t --test Test run. Do not modify files. -v --verbose Print verbose output """ from docopt import

How to prevent command line args from being interpreted by R vs. only by my script?

♀尐吖头ヾ 提交于 2019-12-05 05:24:15
I'm using the docopt implementation for R. My script has a command line option where the short form is -g . When I run my script, it seems this argument is first interpreted by R and then by my script. Therefore I get a wrist slap about not specifying a value for the GUI. Can I prevent R from trying to work with these command line args? Example of a script: #!/usr/bin/Rscript suppressPackageStartupMessages(library(docopt)) "docopt practice script Usage: foo.R [-g <goodies>] Options: -g <goodies>, --goodies=<goodies> Goodies " -> doc opts <- docopt(doc) cat(sprintf("goodies = %s\n", opts

Why doesn't my docopt option have its default value?

谁说胖子不能爱 提交于 2019-12-04 08:58:30
问题 I'm using docopt in an example for a module I'm working on, and all the option default values are working except one. I've modified all the code containing and surrounding the option trying to identify the problem, but it won't take a default value! My options block looks like this: Options: --help Show this message and exit --version Show version info and exit -w WIDTH --width=WIDTH The out to out width of the deck (feet) [default: 73] -g GIRDERS --girders=GIRDERS The number of girders

Python - Difference between docopt and argparse

浪尽此生 提交于 2019-12-03 22:30:21
I have to write a command-line interface and I've seen I can use docopt and argparse . I would like to know what are the main differences between the two so that I can make an enlightened choice. Please stick to the facts. I don't want Wow. docopt. So beautiful. Very useful. reindeer Docopt parses a doc string, whereas argparse constructs its parsing by creating an object instance and adding behaviour to it by function calls. Example for argparse: parser = argparse.ArgumentParser() parser.add_argument("operation", help="mathematical operation that will be performed", choices=['add', 'subtract'

Why doesn't my docopt option have its default value?

不问归期 提交于 2019-12-03 01:32:10
I'm using docopt in an example for a module I'm working on, and all the option default values are working except one. I've modified all the code containing and surrounding the option trying to identify the problem, but it won't take a default value! My options block looks like this: Options: --help Show this message and exit --version Show version info and exit -w WIDTH --width=WIDTH The out to out width of the deck (feet) [default: 73] -g GIRDERS --girders=GIRDERS The number of girders [default: 8] -h HEIGHT --height=HEIGHT The height of the girders (inches) [default: 56] -t THICK --thick

mutually_exclusive_group with optional and positional argument

Deadly 提交于 2019-12-02 04:24:12
问题 I created an cli specification with docopt which works great, however for some reason I have to rewrite it to argparse Usage: update_store_products <store_name>... update_store_products --all Options: -a --all Updates all stores configured in config How to do that? What is important I don't want to have something like this: update_store_products [--all] <store_name>... I think it would be rather something like this: update_store_products (--all | <store_name>...) I tried to use add_mutually

Better solution than if __name__ == '__main__' twice in Python script

六眼飞鱼酱① 提交于 2019-12-01 10:51:15
I have multiple Python scripts which use docopt. My issue is that the available options for the two scripts differ slightly - one option is present in one script, but not the other. I've included a minimum working example below. If I run: python main.py --num=7 --name=John the script does not run, as --name=John is also passed to module1.py, where it is not a valid option. With my actual script, I have several imports after docopt parses the arguments, and so I cannot simply move the docopt call to the bottom of the script ( if __name__ == '__main__': ). If I do this, the imports in the

Better solution than if __name__ == '__main__' twice in Python script

落花浮王杯 提交于 2019-12-01 08:10:56
问题 I have multiple Python scripts which use docopt. My issue is that the available options for the two scripts differ slightly - one option is present in one script, but not the other. I've included a minimum working example below. If I run: python main.py --num=7 --name=John the script does not run, as --name=John is also passed to module1.py, where it is not a valid option. With my actual script, I have several imports after docopt parses the arguments, and so I cannot simply move the docopt