django-views

问题 I am trying to get data in a particular format but i'm not able to get the desired output. My Model: class Category(models.Model): name = models.CharField(max_length=40) class Expense(models.Model): category = models.ForeignKey(Category, on_delete=models.CASCADE, related_name="category_name") description = models.CharField(max_length=200) total_amount = models.IntegerField() class Expense_Details(models.Model): expense = models.ForeignKey(Expense, on_delete=models.CASCADE, related_name=

问题 I have pored over several similar posts (and Calling a class-based view of an app from another app in same project seemed promising, but does not work), but some are older and none quite work for me. Here's my setup (using Django==2.0.6, djangorestframework==3.8.2) I have a basic model (simplified here): from django.db import models class Resource(models.Model): name = models.CharField(max_length=100, null=False) I have a basic endpoint where I can list and create Resource instances: from

问题 I have given {% csrf_token %} inside the form. Do I have to give another {% csrf_token %} inside the AJAX $.ajax({ .......... )} ? <form method="post" data-validate-username-url="{% url 'validate_username' %}"> {% csrf_token %} {{ form.as_p }} <button type="submit">Sign up</button> </form> <script src="https://code.jquery.com/jquery-3.1.0.min.js"></script> <script> $("#id_username").change(function () { console.log($(this).val()); var form = $(this).closest("form"); $.ajax({ url: form.attr(

问题 This question already has an answer here : Django-Filter Package: How To Filter Objects To Create Stats And Not Lists (1 answer) Closed 4 days ago . Below is the views.py to my stats page. This page has a bunch of calculations based on my model objects. Works great. However when I apply django-filter to the data it does not change. Example filtering for only "short" trades or in the "last 7 days". I know that get_context_data is basically hardcoding the results and it will not be affected by

问题 ;TLDR - After some solutions discovered, my final question is how can I, if at all, access models related to models related to the main detailview model? I'm trying to use a generic detailview to return an object and it's related object. In this example, a company like mcdonalds would have any sites (or locations). What I want the detailview to be able to show is the company detail, and the site detail related to the company. I'm stuck though. Dispite my efforts in not asking for help, I have

问题 ;TLDR - After some solutions discovered, my final question is how can I, if at all, access models related to models related to the main detailview model? I'm trying to use a generic detailview to return an object and it's related object. In this example, a company like mcdonalds would have any sites (or locations). What I want the detailview to be able to show is the company detail, and the site detail related to the company. I'm stuck though. Dispite my efforts in not asking for help, I have

问题 I have been trying to add friend system in which the user can add and remove friends (other users), after finishing with the code, I found an error that when the logedin user tries to add a friend from other user's profile, the add friend button redirects to the logedin user profile making it imposible to add a new friend, it can just add himself as a friend. I personally think the error is on the views.py profile view. views.py (profile shows user's profile and change_friend is the one that

问题 Here's what I'm trying to do. I'm wondering if someone can suggest a good approach: models.py: class Color(models.Model): name = models.CharField(... class Speed(models.Model): name = models.CharField(... class Dog(models.Model): name = models.CharField(... color = models.ForeignKey(Color... speed = models.ForeignKey(Speed... class DogRequest(models.Model): dog = models.ForeignKey(Dog... request_time = models.DateTimeField() Now I want to have a page where a user can enter or edit a

问题 In django how to check whether any entry exists for a query sc=scorm.objects.filter(Header__id=qp.id) This was how it was done in php if(mysql_num_rows($resultn)) { // True condition } else { // False condition } 回答1: Use count(): sc=scorm.objects.filter(Header__id=qp.id) if sc.count() > 0: ... The advantage over e.g. len() is, that the QuerySet is not yet evaluated: count() performs a SELECT COUNT(*) behind the scenes, so you should always use count() rather than loading all of the record

问题 In django how to check whether any entry exists for a query sc=scorm.objects.filter(Header__id=qp.id) This was how it was done in php if(mysql_num_rows($resultn)) { // True condition } else { // False condition } 回答1: Use count(): sc=scorm.objects.filter(Header__id=qp.id) if sc.count() > 0: ... The advantage over e.g. len() is, that the QuerySet is not yet evaluated: count() performs a SELECT COUNT(*) behind the scenes, so you should always use count() rather than loading all of the record