django-views

ViewSets have automatic methods to list, retrieve, create, update, delete, ... I would like to disable some of those, and the solution I came up with is probably not a good one, since OPTIONS still states those as allowed. Any idea on how to do this the right way? class SampleViewSet(viewsets.ModelViewSet): queryset = api_models.Sample.objects.all() serializer_class = api_serializers.SampleSerializer def list(self, request): return Response(status=status.HTTP_405_METHOD_NOT_ALLOWED) def create(self, request): return Response(status=status.HTTP_405_METHOD_NOT_ALLOWED) The definition of

I have a rank.html which is a publicly sharing template for many other templates through {% include rank.html %} method. This template will display the 48 hours hot news base on the click number. Here is the view.py: def rank(self, request): hot_news_48h = h_mostViewed(48, News, '-pv') return render(request, "rank.html", { 'hot_news_48h': hot_news_48h,}) h_mostViewed(48, News, '-pv') is a function,that can fetch most viewed(clicked) post within 48 hours.It works. Here is the rank.html: <ul> {% for hot_view in hot_news_48h %} <li> <a href="{% url 'news:news_detail' hot_view.pk %}" > <img src="{

I created a formset that has maximum of 5 images to be attached; 1 - but I want the Validation to run only when the user has not attached any image (ValidationError('atleast 1 image is required')) , 2- This program is also not allowing the User to save when 1, or 2, or 3 images are attached, which I really need. So if there is 1 image or 2, that should be allowed to save. 3 - I also need to make the 1 radio-button to be selected by default, to make the selected image to be the one dispalyed in the template template <form enctype="multipart/form-data" action="" method="post"> {% csrf_token %} {

i am trying to develop a website whith Django 2.1.3 and python 3.7.1 When i go to the homepage i get this error: TypeError at / __init__() takes 1 positional argument but 2 were given Here some details about the code i write: Trceback Environment: Request Method: GET Request URL: http://127.0.0.1:8000/ Django Version: 2.1.3 Python Version: 3.7.1 Installed Applications: ['django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'core', 'crispy_forms'] Installed Middleware: ['django.middleware

I have a model named Domain which looks like this: class Domain(models.Model): """ Model for storing the company domains """ user = models.ForeignKey( User ) host = models.CharField( null=False, verbose_name="Host", max_length=128, unique=True ) I'd like to use Django's generic views for doing CRUD operations on this. There is one field in this model that needs user input but the foreign key field doesn't need any user input. How can I exclude that field from the form that my generic view generates but assign it the value of the current authenticated user. Thanks. Have a look at Russel's

I want to create a model form with a one-to-one relation with another model. i.e Model1 has a one-to-one relation with Model2. I want my form to show all the fields from Model1 as well as Model2. Also what is the best way to show this in a view. You don't need to create the single form for two models. Use two django forms and place them inside the single <form> tag: class Model1Form(forms.ModelForm): class Meta: model = Model1 class Model2Form(forms.ModelForm): class Meta: model = Model2 exclude = ('model1_one_to_one_field', ) def create_models(request): if request.method == 'POST': form1 =