django-views

Implementing page not found in django and have looked at the documentation 404 I do not get a page not found error as yet what ami doing here In my code in urls i have done the following, url(r'^$', 'site_config.views.pagenotfound') from django.http import Http404 def pagenotfound(request): return render_to_response('polls/pagenotfound.html', {}) The way you handle 404 and 500 in django is: by default, in the templates directory, create a 404.html If you need a custom handler, just add these to urls.py handler404 = 'views.page_not_found_custom' handler500 = 'views.page_error_found_custom'

I have a form with a new init method, which allow to display various choices according to a parameter : class Isochrone_Set_Parameters(forms.Form): Grid_Choices = Grids_Selection.Grid_Choices def __init__(self, Grid_Type, *args, **kwargs): super(Isochrone_Set_Parameters, self).__init__(*args, **kwargs) if Grid_Type == Grids_Selection.Grid_Values[0]: Choices = (('0.0','0.0'),('0.1','0.1'),('0.3','0.3'),('0.5','0.5'),('0.6','0.6'),('0.7','0.7'), \ ('0.8','0.8'),('0.9','0.9'),('0.95','0.95')) self.fields['Rotation_Rate'] = forms.ChoiceField(choices=Choices) elif Grid_Type == Grids_Selection.Grid

can i add the ajax code with django? i have created a simple registraion form that have 5 fields . i wish to disply the each fields in different pages but in a single window . it means by using next button 5 pages want to disply in a single window. same time all content of each page i want add to my database. is this possible in django with ajax.. my codes are as follows : #view from django.shortcuts import render_to_response from registration.models import UserDetails from forms import UserForm from django import forms from django.template import RequestContext from django.http import

I have a list of countries, they all have there own url www.example.com/al/ for example. There is a list of cities for every country but the object_list is empty My View: class CityOverview(generic.ListView): template_name = 'shisha/pages/country_index.html' model = City def get_queryset(self, *args, **kwargs): country_id = self.kwargs.get('country_id') return City.objects.filter(country__name=country_id) My Model: class Country(models.Model): COUNTRY_CHOICES = ( ('al', 'Albania'), ('ad', 'Andorra'), #etc. etc. ) name = models.CharField(max_length=255, choices=COUNTRY_CHOICES, default='nl')

I am using the Group module in Django. I've created views GroupCreateView and GroupUpdateView in which I can update permissions and group name, but I also want to add users to the groups. Right now I have to update each user object and set to which groups it belongs. I want to do it the other way around where I create groups and add users to this group. How is this obtained? I guess it's something like group.user_set.add(user) I am assuming you want to add a newly created user to an existing group automatically . Correct me if I am wrong since this is not stated in your question. Here is what

I'm trying to create a submenu for a sports site. Each sport would need its own submenu. The problem I'm having is I need the namespace itself to be dynamic in someway. SportListView returns the sport so I can then filter the news articles by the sport. Views: class SportListView(ListView): template_name="sports/sport-home.html" context_object_name='sport_list' def get_context_data(self, **kwargs): context = super(SportListView, self).get_context_data(**kwargs) context['sport_menu'] = get_object_or_404(Sport, sport_slug=self.kwargs['sport_slug']) return context Template: <nav class="navbar

I am trying to make a url field in my detail view by passing two primary key in it... This is what I have done in urls.py: url(r'^company/(?P<pk1>\d+)/groupdetail/(?P<pk2>\d+)/$',views.group1DetailView.as_view(),name='groupdetail'), And in my views: def get_object(self): pk1 = self.kwargs['pk1'] pk2 = self.kwargs['pk2'] company = get_object_or_404(company, pk=pk1) group1 = get_object_or_404(group1, pk=pk2) return group1 I am getting error in this line: company = get_object_or_404(company, pk=pk1) And in my group1 list view I have done this: <a href="{% url 'accounting_double_entry:groupdetail'

I am trying to limit the choices of a foreign field to those other objects who look like the object self. I've tried this: class Model1(models.Model): entry = models.ForeignKey(Model2, limit_choices_to='get_limit_choices_to') number = IntegerField() def get_limit_choices_to(self): return Model2.objects.filter(expenditure_type=self.expenditure_type) class Model2(models.Model): number = IntegerField() but I get the error _filter_or_exclude() argument after ** must be a mapping, not str I don't know if limit_choices_to is the right way to do this. Maybe I should choose the queryset in a or the