django-views

If you have 2 views, the first uses modelform that takes inputted information from the user (date of birth, name, phonenumber, etc), and the second uses this information to create a table. How would you pass the created object in the first view to the next view so you can use it in the second view's template I'd appreciate any help you can share One approach is to put the object into a session in your first view, which you could then retrieve from the request.session in the second view. def first_view(request): my_thing = {'foo' : 'bar'} request.session['my_thing'] = my_thing return render

I'm trying to use raspberry pi capture the image from USB camera and stream it with Django framework I have tried to use StreamingHttpResponse to stream the frame from Opencv2. However, it just shows 1 frame and not replacing the image. How can I replace the image in real time? Here is my code. from django.shortcuts import render from django.http import HttpResponse,StreamingHttpResponse import cv2 import time class VideoCamera(object): def __init__(self): self.video = cv2.VideoCapture(0) def __del__(self): self.video.release() def get_frame(self): ret,image = self.video.read() ret,jpeg = cv2

I've got Django Channels 2.1.2 set up in my Django app by following a tutorial and now need to set up a notification system for new messages. I want to do this in the simplest way possible. I can do it via browser push notifications, but I don't want to do it like that. I want it to be like Stack Overflow, where there is a red number representing the instance of a new message. One answer on here said For notifications you only need two models: User and Notification . On connect set the scope to the currently authenticated user. Set up a post_save signal on your Notification model to trigger a

There are apparently two different ways to return a 404 error in Django: by returning a HttpResponseNotFound object or by raising an Http404 exception. While I'm using the former in my project, it seems that Django's internal views are mostly using the latter. Apart from the "Exception is exceptional" mantra, what's the difference between both ways and which should I be using? An HttpResponseNotFound is just like a normal HttpResponse except it sends error code 404. So it's up to you to render an appropriate 404 page in that view, otherwise the browser will display its own default. Raising an

How do you cache a paginated Django queryset, specifically in a ListView? I noticed one query was taking a long time to run, so I'm attempting to cache it. The queryset is huge (over 100k records), so I'm attempting to only cache paginated subsections of it. I can't cache the entire view or template because there are sections that are user/session specific and need to change constantly. ListView has a couple standard methods for retrieving the queryset, get_queryset() , which returns the non-paginated data, and paginate_queryset() , which filters it by the current page. I first tried caching

I want to display custom 404 error page when end user enters wrong url,I have tried but i am getting only Django default 404 page.I am using Python(2.7.5),Django(1.5.4) My Code urls.py from django.conf.urls import patterns, include, url from mysite import views handler404 = views.error404 urlpatterns = patterns('', url(r'^$', 'mysite.views.home', name='home'), ) views.py from django.http import HttpResponse from django.shortcuts import render from django.template import Context, loader def home(request): return HttpResponse("welcome to my world") def error404(request): template = loader.get

I am trying to allow registration (using this django-registration register view) to one of my applications from a modal dialog. Since this form is in a modal box, I'd like to get an json reponse on success (instead of the default redirection) How can I use this view ( django-registration register ) to manage the registration and send back a json response on success ? I know how to make ajax/json responses, the question is how to use the django-registration view without the redirection behavior or wrap it into an other view to manage the response. First you need to change the urls.py to wrap