django-class-based-views

post method in generic class based view is not called upon form submission in Django?

久未见 提交于 2019-12-02 05:40:48
I have a written a mixin that overrides the POST and get_from_kwargs of CreateView . I am doing AJAX submission of my form. I see that get_from_kwargs is called by printing on the console. But none of the other methods such as post , form_valid or form_invalid is being called. I have placed print statements in these methods but none of them is being called. Here is my mixin: class PendFormMixin(object): form_hash_name = 'form_hash' pend_button_name = 'pend' def get_form_kwargs(self): """ Returns a dictionary of arguments to pass into the form instantiation. If resuming a pended form, this will

Django: Include Media (css/js) in Class-Based Views

会有一股神秘感。 提交于 2019-12-02 04:24:32
I am updating old django code from method-based views to class-based views. I know how to include media (css/js) in forms via the Media class How can I use the media class if my class based view does not contain any forms? CSS/JS are usually managed in the template itself and not in the view. See https://docs.djangoproject.com/en/1.10/howto/static-files/ For example, use base.html: <!DOCTYPE html> <html> <head> <title> {% block page_title %}{{ page_title }}{% endblock %} </title> {% block css %} {% endblock %} </head> <body> {% block main %} {% endblock %} {% block scripts %} {% endblock %} <

Django reverse class based views by function name do not work

不想你离开。 提交于 2019-12-01 17:40:44
According to the django docs, viewname is either the function name or the url pattern name. But reversing an url like this 'reverse(MyView.as_view())' turns into a NoReverseMatch exception. Is there any way to reverse class based view by function name? You can either used named url patterns or you can do something like the following (in your views.py ) my_function = MyView.as_view() now reverse will work: reverse('myviews.my_function') 来源: https://stackoverflow.com/questions/13193350/django-reverse-class-based-views-by-function-name-do-not-work

Django reverse url with parameters to a class based view

不问归期 提交于 2019-12-01 17:02:03
I just started learning python and django and I have a question. I got the assignment to turn function views into class based views. But my links wont work now. these are from urls.py: url(r'^$', ContactIndex.as_view()), url(r'^add$', ContactAdd.as_view()), url(r'^([0-9]+)/update$', ContactUpdate.as_view()), url(r'^([0-9]+)/view$', ContactView.as_view()), This is my link : {% url rtr_contact.views.ContactView contact.id %} but this doesnt work it says: Caught NoReverseMatch while rendering: Reverse for 'rtr_contact.views.ContactView' with arguments '(20L,)' and keyword arguments '{}' not found

Simple example of how to use a class based view and django-filter?

别说谁变了你拦得住时间么 提交于 2019-12-01 16:52:04
问题 The example in the documentation, https://django-filter.readthedocs.org/en/latest/usage.html, is I think for a function based view. I am currently researching how to do this with a class based view. def product_list(request): f = ProductFilter(request.GET, queryset=Product.objects.all()) return render_to_response('my_app/template.html', {'filter': f}) 回答1: A bit more digging and I have managed to answer it. I have used the code from here https://github.com/rasca/django-enhanced-cbv. I added

Django reverse class based views by function name do not work

橙三吉。 提交于 2019-12-01 15:53:02
问题 According to the django docs, viewname is either the function name or the url pattern name. But reversing an url like this 'reverse(MyView.as_view())' turns into a NoReverseMatch exception. Is there any way to reverse class based view by function name? 回答1: You can either used named url patterns or you can do something like the following (in your views.py ) my_function = MyView.as_view() now reverse will work: reverse('myviews.my_function') 来源: https://stackoverflow.com/questions/13193350

Django reverse url with parameters to a class based view

非 Y 不嫁゛ 提交于 2019-12-01 15:16:49
问题 I just started learning python and django and I have a question. I got the assignment to turn function views into class based views. But my links wont work now. these are from urls.py: url(r'^$', ContactIndex.as_view()), url(r'^add$', ContactAdd.as_view()), url(r'^([0-9]+)/update$', ContactUpdate.as_view()), url(r'^([0-9]+)/view$', ContactView.as_view()), This is my link : {% url rtr_contact.views.ContactView contact.id %} but this doesnt work it says: Caught NoReverseMatch while rendering:

Is it possible to have a form in a ListView template?

限于喜欢 提交于 2019-12-01 13:38:30
I built a listview which works fine and gives me exactly what I want. In the template of this ListView I declared a form that points to a CreateView. The form is like so, {% if user.is_authenticated %} <form action="{% url 'post_wall' %}" method="POST"> {% csrf_token %} <input type='text' name='body' /> <input type='hidden' name='from_user' value='{{ user.id }}' /> <input type='hidden' name='to_user' value='{{ to_user }}' /> <input type='submit' value='POST'/> </form> {% endif %} the post_wall url corresponds to url(r'accounts/post_wall', WallCreate.as_view(), name='post_wall'), The url which

Is it possible to have a form in a ListView template?

半世苍凉 提交于 2019-12-01 11:39:00
问题 I built a listview which works fine and gives me exactly what I want. In the template of this ListView I declared a form that points to a CreateView. The form is like so, {% if user.is_authenticated %} <form action="{% url 'post_wall' %}" method="POST"> {% csrf_token %} <input type='text' name='body' /> <input type='hidden' name='from_user' value='{{ user.id }}' /> <input type='hidden' name='to_user' value='{{ to_user }}' /> <input type='submit' value='POST'/> </form> {% endif %} the post

Django: Only update fields that have been changed in UpdateView

自古美人都是妖i 提交于 2019-11-30 23:22:04
I'm using an UpdateView to update a series of fields. However, I only want fields that have been modified to be saved to the database. If a value was not provided for a field during update process, I want the previous value to be used as the default. If a new value was provided for a field then only that field should be updated. How do I go about accomplishing this? #views.py class AccountUpdate(UpdateView): """ Updates an account; unchanged fields will not be updated.""" context_object_name = 'account' form_class = UpdateForm template_name = 'accounts/update_account.html' success_url = '