directory-structure

问题 ( Probably a noob question, but I didn't find a solution after googling for 20 minutes. ) I created a new pure Python project with PyCharm which yielded the following folder structure myproject └── venv ├── bin │ ├── activate │ ├── activate.csh │ ├── activate.fish │ ├── easy_install │ ├── easy_install-3.5 │ ├── pip │ ├── pip3 │ ├── pip3.5 │ ├── python │ ├── python3 │ └── python3.5 ├── include ├── lib │ └── python3.5 ├── lib64 -> lib └── pyvenv.cfg Where do I put myproject.py or the myproject

问题 I'm currently working on my own PHP Framework, and I need some help figuring out if I'm going in the right direction or not... The framework is both for my own use and to generally advance my PHP skills further. I've encountered numerous problems that by overcoming them I have learned a great deal, and love being able to create something from nothing, so I'd rather not see answers like "Just use Zend"! ;) I have read a bunch of articles both on Stack Overflow and a bunch of other sites, but

问题 I am working on a C++ library. Ultimately, I would like to make it publicly available for multiple platforms (Linux and Windows at least), along with some examples and Python bindings. Work is progressing nicely, but at the moment the project is quite messy, built solely in and for Visual C++ and not multi-platform at all. Therefore, I feel a cleanup is in order. The first thing I'd like to improve is the project's directory structure. I'd like to create a structure that is suitable for the

问题 I see a lot of Vue.js projects using this structure: ├── main.js ├── api │ └── index.js │ └── services #containing files with api-calls │ ├── global.js │ ├── cart.js │ └── messages.js ├── components │ ├── Home.vue │ ├── Cart.vue │ ├── Messages.vue │ └── ... └── store ├── store.js ├── actions.js #actions to update vuex stores ├── types.js └── modules ├── global.js ├── cart.js └── ... (An example with this structure is 'Jackblog'.) So, for example, Cart.vue wants to update the inCart data in

问题 I see a lot of Vue.js projects using this structure: ├── main.js ├── api │ └── index.js │ └── services #containing files with api-calls │ ├── global.js │ ├── cart.js │ └── messages.js ├── components │ ├── Home.vue │ ├── Cart.vue │ ├── Messages.vue │ └── ... └── store ├── store.js ├── actions.js #actions to update vuex stores ├── types.js └── modules ├── global.js ├── cart.js └── ... (An example with this structure is 'Jackblog'.) So, for example, Cart.vue wants to update the inCart data in

问题 I need to process all files in a directory tree recursively, but with a limited depth. That means for example to look for files in the current directory and the first two subdirectory levels, but not any further. In that case, I must process e.g. ./subdir1/subdir2/file , but not ./subdir1/subdir2/subdir3/file . How would I do this best in Python 3? Currently I use os.walk to process all files up to infinite depth in a loop like this: for root, dirnames, filenames in os.walk(args.directory):

问题 The use case is simple. I got the source files that were created using Eclipse. So, there is a deep directory structure, where any Java class could be referring to another Java class in the same, child, sibling or parent folder. How do I compile this whole thing from the terminal using javac ? 回答1: You have to know all the directories, or be able to use wildcard .. javac dir1/*.java dir2/*.java dir3/dir4/*.java dir3/dir5/*.java dir6/*src/*.java 回答2: With Bash 4, you can just enable globstar

问题 I'm really enjoying Rails (even though I'm generally RESTless), and I enjoy Ruby being very OO. Still, the tendency to make huge ActiveRecord subclasses and huge controllers is quite natural (even if you do use a controller per resource). If you were to create deeper object worlds, where would you put the classes (and modules, I suppose)? I'm asking about views (in the Helpers themselves?), controllers and models. Lib is okay, and I've found some solutions to get it to reload in a dev

问题 Total Python newb here. I have a images directory and I need to return the names and urls of those files to a django template that I can loop through for links. I know it will be the server path, but I can modify it via JS. I've tried os.walk, but I keep getting empty results. 回答1: If your images are in one directory import os root="/my" Path=os.path.join(root,"path","images") os.chdir(Path) for files in os.listdir("."): if files[-3:].lower() in ["gif","png","jpg","bmp"] : print "image file:

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 6 years ago . Why can't Java figure it out based on the folder structure? It seems that the mapping to packages is already specified by the root source folder plus the path to that particular file. It is completely coupled, and doing a refactor without an IDE is absolutely tedious -