directory-structure

How do I recursively compare two directories (comparison should be based only on file name) and print out files/folders only in one or the other directory? I'm using Python 3.3. I've seen the filecmp module, however, it doesn't seem to quite do what I need. Most importantly, it compares files based on more than just the filename. Here's what I've got so far: import filecmp dcmp = filecmp.dircmp('./dir1', './dir2') dcmp.report_full_closure() dir1 looks like this: dir1 - atextfile.txt - anotherfile.xml - afolder - testscript.py - anotherfolder - file.txt - athirdfolder And dir2 looks like this:

as weSuppose that I am creating a Java project with the following classes com.bharani.ClassOne com.bharani.ClassTwo com.bharani.helper.HelperOne com.bharani.helper.support.HelperTwo with files put immediately under the folder 'src' src/ClassOne.java src/ClassTwo.java src/HelperOne.java src/HelperTwo.java and compile them using the command $ javac -d classes src/*.java (assuming that classes directory exists) The compiler compiles these files and put the class files in appropriate sub-directories inside the 'classes' directory like this classes/com/bharani/ClassOne.class classes/com/bharani

So say I have a string like so of a path $path = '/path/to/../../up/something.txt'; Is there a way built into PHP to parse it and come up with a URL without the directory ups (../) ? E.g. $path = parsePath('/path/to/../../up/something.txt'); // /up/something.txt realpath($path); Docs PHP's realpath() is cool, but what if you want to figure it out without accessing the filesystem? I've written this function that can return a path with ../ and the like calculated to a real path. It probably doesn't handle all path commands, so let me know if you think I should implement another. public function

I am trying to create a bunch of directories and sub directories at a specific location in my PC. My process is something like this: Check if there's any directory with the same directory name. Skip if so. If not, create the directory and the pre-defined sub directories under that directory. This is the code I came up with using os module: def Test(): main_dir = ["FolderA", "FolderB"] common_dir = ["SubFolder1", "SubFolder2", "SubFolder3"] for dir1 in main_dir: if not os.path.isdir(dir1): for dir2 in common_dir: os.makedirs("%s/%s" %(dir1,dir2)) I am wondering if there's any better way to do

Here is a app contorller directory from Rails project doing a self study for rails, but from what I understand if I create a directory in the app folder then I have to do the complete the routes files with a match that route like: match "/editor/usynkdataeditor/saveusynkeditor" , Question to the community is there a better way that I can define different directory structure for a specific workflow or is it safe to define all the controllers in parent controllers directory. If you create additional directory in controllers directory, you are effectively namespacing your controllers. So this

I need to copy entire directory to some location. What is the best way to do so ? File::Copy copies only file by file as I saw it. By the way I work under Windows. Thanks for help. unwind Maybe look into File::Copy::Recursive . Adam Luchjenbroers A quick google search for "perl copy directory file::" finds File::Copy::Recursive Looks what you're after. 来源： https://stackoverflow.com/questions/1865883/how-can-i-copy-an-entire-directory-in-perl

I've followed the Writing Web Applications tutorial on the Go website and I'm starting to write my own web app. I've also read the beginning of How to Write Go Code and am trying to organise my code with the same workspace structure. I'm writing a simple web app named mygosite that handles all requests by rendering a single template. After running go install github.com/wesleym/mygosite , my directory structure now looks like this: go +-src | +-github.com | +-wesleym | +-mygosite | +-mygosite.go | +-templates | +- index.html | +-.git +-bin +-mygosite In my code, I'm referring to the template