dimensions

1、定义元组 元组使用圆括号来标识。定义元组后，就可以使用索引来访问其元素，就像访问列表元素一样。 dimensions = (100,200) print(dimensions[0]) print(dimensions[1]) 访问元组元素的方法与访问列表元素的方法是一样的，运行结果： 100 200 需要注意的是元组中的元素时不能修改的，当你尝试修改元组中的元素时，python会报错。 2、遍历元组中的所有值 我们一样可以使用for循环来遍历元组中的所有值： dimensions = (100,200) for dimension in dimensions: print(dimension) 跟遍历列表一样，Python会返回元组中所有的元素： 100 200 虽然我们不能修改元组中的元素，但是我们可以给元组重新赋值。相比于列表，元组是更简单的数据结构。如果需要存储的一组值在程序的整个生命周期内都不变，可使用元组。 来源： https://blog.csdn.net/weixin_43882744/article/details/99677743

The Android Documentation says that there is two sizes for a view, the measured dimensions and the drawing dimensions . The measured dimension is the one computed in the measure pass (the onMeasure method), while the drawing dimensions are the actual size on screen. Particularly, the documentation says that: These values may, but do not have to, be different from the measured width and height. So, my question is: what could make the drawing dimension be different of the measured dimension? If the onMeasure(int,int) method respects the layout requirements (given as the parameters

I'm new to the CUDA paradigm. My question is in determining the number of threads per block, and blocks per grid. Does a bit of art and trial play into this? What I've found is that many examples have seemingly arbitrary number chosen for these things. I'm considering a problem where I would be able to pass matrices - of any size - to a method for multiplication. So that, each element of C (as in C = A * B) would be calculated by a single thread. How would you determine the threads/block, blocks/grid in this case? In general you want to size your blocks/grid to match your data and

This question already has an answer here: How to get the width and height of an android.widget.ImageView? 10 answers What is the best way to retrieve the dimensions of the Drawable in an ImageView? My ImageView has an Init-Method where i create the ImageView: private void init() { coverImg = new ImageView(context); coverImg.setScaleType(ScaleType.FIT_START); coverImg.setImageDrawable(getResources().getDrawable(R.drawable.store_blind_cover)); addView(coverImg); } At some point during the layout oder measure process i need the exact dimensions of the Drawable to adjust the rest of my Components

I'm currently trying to learn Numpy and Python. Given the following array: import numpy as np a = np.array([[1,2],[1,2]]) Is there a function that returns the dimensions of a (e.g.a is a 2 by 2 array)? size() returns 4 and that doesn't help very much. It is .shape : ndarray. shape Tuple of array dimensions. Thus: >>> a.shape (2, 2) First: By convention, in Python world, the shortcut for numpy is np , so: In [1]: import numpy as np In [2]: a = np.array([[1,2],[3,4]]) Second： In Numpy, dimension , axis/axes , shape are related and sometimes similar concepts: dimension In Mathematics/Physics ,