difference

问题 I have one svg but it looks differently on Chrome and Firefox: http://codepen.io/anon/pen/OParwx. svg { fill: black; stroke: black; width: 40px; height: 40px; } <svg xmlns="http://www.w3.org/2000/svg" viewBox="0,0,48.266,51.827"> <g> <path d="M16.69 41.827c-2.763 0-4.975 2.237-4.975 5s2.212 5 4.975 5c2.763 0 5-2.237 5-5s-2.237-5-5-5"/> <path d="M40.19 41.827c-2.763 0-4.975 2.237-4.975 5s2.212 5 4.975 5c2.763 0 5-2.237 5-5s-2.237-5-5-5"/> <path d="M26.768 20v-20 20z" stroke-width="5" stroke

问题 I have a table with consecutive times and dates for an agenda. ID date begin_time end_time 1 05-02-15 19:00:00 19:05:00 2 05-02-15 19:05:00 19:10:00 3 05-02-15 19:10:00 19:15:00 4 05-02-15 19:15:00 19:20:00 5 05-02-15 19:20:00 19:25:00 6 05-02-15 19:25:00 19:30:00 7 05-02-15 19:30:00 19:35:00 8 05-02-15 19:35:00 19:40:00 9 06-02-15 19:00:00 19:05:00 10 06-02-15 19:05:00 19:10:00 11 06-02-15 19:10:00 19:15:00 12 13 14 06-02-15 19:25:00 19:30:00 15 06-02-15 19:30:00 19:35:00 16 06-02-15 19:35

问题 I am a beginner for Spotfire. I have a problem about the difference calculation for the some column value. I have opened a similar question for the date difference calculation, see:calculate the time difference for same column in Spotfire how can i calculate the difference for the same column, is there any related function like DateDiff() here? for example: id times state 1 12 1 2 7 0 3 10 1 4 11 0 5 6 1 6 9 0 7 7 1 the result could be : id times state diffence 3 10 1 -2 5 6 1 -4 7 7 1 1 For

问题 I have a pandas Series with monthly data ( df.sales ). I needed to subtract the data 12 months earlier to fit a time series, so I ran this command: sales_new = df.sales.diff(periods=12) I then fit an ARMA model, and predicted the future: model = ARMA(sales_new, order=(2,0)).fit() model.predict('2015-01-01', '2017-01-01') Because I had diffed the sales data, when I use the model to predict, it predicts forward diffs. If this was diff of period 1, I would just use an np.cumsum() , but because

问题 I have two strings: 1387050870 and 2012-12-15 How can i calculate the difference between these two dates in weeks (52)? I tried Math.round(1387050870-(Math.round(new Date('2012-12-15').getTime()/1000))/604800) , but that doesn't seem to work. 回答1: The JavaScript Date object accepts milliseconds as its constructor, so convert first then try: var a = new Date(1387050870 * 1000); var b = new Date("2012-12-15"); var weeks = Math.round((a-b)/ 604800000); Which makes weeks 2239, which sounds close,

问题 This question already has answers here : Difference between two dates in years, months, days in JavaScript (21 answers) Closed 5 years ago . well, I found a lot of questions like that here trying to obtain the difference between 2 dates in years, month and days... But no answers that complete my requirement. So i wrote something to calculate, it seems to work, but maybe some expert's here can make corrections or help to make this more simple. 回答1: You can use moment.js to simplify this:

问题 I would like to perform two different calculations across consecutive columns in a pandas or pyspark dataframe. Columns are weeks and the metrics are displayed as rows. I want to calculate the actual and percentage differences across the columns. The input/output tables incl. the calculations used in Excel are displayed in the following image. I want to replicate these calculations on a pandas or pyspark dataframe. Raw Data Attached: Metrics Week20 Week21 Week22 Week23 Week24 Week25 Week26

问题 I am creating an update to my companies system that will be running on several clients and I have two config files, the old config file and the newer version. Is there any way that I can compare the both files and check the differences to add to the older file what I have new in the first one? Keep in mind that the files may have different info and the only thing that I need to add/change is the keys. For example, if a key is different change the older to that new "version", if a key doesn’t

问题 I have one question regarding MySQL date / time functions. For now, I have query which looks like this: SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(sum))) FROM workingtime WHERE user='magdalena' AND type='work' AND start BETWEEN '2014-03-01' AND '2014-03-12' AND completed=1 So in my database there are 2 columns with timestamps, first one is "start", second one is "end". What I would like to execute in sigle query is this: I would like to have returned how much is the time difference between start and

问题 i could not find the working algorithm of the above two ,so can anyone provide me on how GDIFF and BSDIFF works? 来源： https://stackoverflow.com/questions/29184826/gdiff-and-bsdiff-algorithm-needed