depth

#include <iostream> #include <cstdio> #include <vector> #include <cstring> using namespace std; const int maxn=5e5+10; int depth[maxn],fa[maxn][22],lg[maxn]; int tot; int head[maxn<<1],e[maxn<<1],nex[maxn<<1]; void add(int x,int y) { e[++tot]=y; nex[tot]=head[x]; head[x]=tot; } void dfs(int cur,int fath) { depth[cur]=depth[fath]+1; fa[cur][0]=fath; for(int i=1; (1<<i)<=depth[cur]; i++) { fa[cur][i]=fa[fa[cur][i-1]][i-1]; } for(int i=head[cur]; i!=-1; i=nex[i]) { if(e[i]==fath) continue; dfs(e[i],cur); } } int lca(int x,int y) { if(depth[x]<depth[y]) swap(x,y); while(depth[x]>depth[y]) x=fa[x]

[USACO10HOL]牛的政治Cow Politics 题目链接： [USACO10HOL]牛的政治Cow Politics 题目大意 给你 \(n\) 个关系，再给你一共有多少个群落，每个关系包含两个内容，在哪个群落以及当前 \(i\) 节点的父亲节点是谁。然后让你求每个群落距离最远的两个点的距离是多大 题目题解 刚开始想的是树的直径，但看了下样例发现都是在一棵树上进行的，搜肯定不怎么好搜，想想其他的办法。然后又想到LCA可以求两点的距离，那么可以考虑用LCA求两点距离，这里我们通过题意理解可以知道，如果选择一个深度最深的点作为其中一个点，那么其定会有一种与其他点的距离方案是我们的答案（简单的贪心），那么我们先确定一点的位置，然后再通过遍历和计算直接计算最大的距离不就OK了吗，然后就... AC了 代码如下 //#define fre yes #include <cstdio> #include <cstring> #include <iostream> const int N = 200005; int head[N << 1], to[N << 1], ver[N << 1]; int maxx[N], color[N], ans[N]; int depth[N], f[N][22], lg[N]; int n, m, root; int tot; void addedge

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7] , 3 / \ 9 20 / \ 15 7 return its depth = 3. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public boolean isBalanced(TreeNode root) { if(root == null) return true; int l = depth(root.left); int r = depth(root.right); return

I am doing a project in opencv to detect obstacle in the path of a blind person using stereo calibration. I have calculated the disparity map correctly. Now to find the distance of obstacle from the camera, I want its 3D coordinates [X,Y,Z] , which I am guessing can be found by reprojectImageTo3D(), but I dont have the Q matrix to use in this function because the Q matrix I am getting from stereoRectify() is coming null probably because I used pre calibrated images. Although I do have the inrinsic and extrinsic parameters of my camera. So my question is that how can I manually create the Q

As the title says I want to calculate the surface normals of a given depth image by using the cross product of neighboring pixels. I would like to use Opencv for that and avoid using PCL however, I do not really understand the procedure, since my knowledge is quite limited in the subject. Therefore, I would be grateful is someone could provide some hints. To mention here that I do not have any other information except the depth image and the corresponding rgb image, so no K camera matrix information. Thus, lets say that we have the following depth image: and I want to find the normal vector at

I'm learning WebGL, done that with the help of WebGLFundamentals page, which helped me pretty much to understand how buffers, shaders and all that stuff works. But now I want to achieve a certain effect which I saw here: https://tympanus.net/Tutorials/HeatDistortionEffect/index3.html I know how to make the heat distortion effect, the effect I want to achieve is the DEPTH on the image. This demo has a tutorial but it doesnt really explain how to do it, it says I must have a grayscale map, in which the white parts are the closest ones and the black parts the farest. But I really cant understand

I have a pair of GLSL shaders that give me the depth map of the objects in my scene. What I get now is the distance from each pixel to the camera. What I need is to get the distance from the pixel to the camera plane. Let me illustrate with a little drawing * |--* / | / | C-----* C-----* \ | \ | * |--* The 3 asterisks are pixels and the C is the camera. The lines from the asterisks are the "depth". In the first case, I get the distance from the pixel to the camera. In the second, I wish to get the distance from each pixel to the plane. There must be a way to do this by using some projection

I want to create a depth first search which I have been somewhat successful in. Here is my code so far (Except my constructor, note the Vertex and Edge classes only contain properties, nothing important to post here): private Stack<Vertex> workerStack = new Stack<Vertex>(); private List<Vertex> vertices = new List<Vertex>(); private List<Edge> edges = new List<Edge>(); private int numberOfVertices; private int numberOfClosedVertices; private int visitNumber = 1; private void StartSearch() { // Make sure to visit all vertices while (numberOfClosedVertices < numberOfVertices && workerStack.Count

1 #include <cstdio> 2 #include <iostream> 3 #include <algorithm> 4 #include <cstring> 5 using namespace std; 6 const int maxn = 1e6 + 5; 7 struct node 8 { 9 int u , v , next; 10 }G[maxn]; 11 int tail , head[maxn]; 12 int n , m , s; 13 int depth[maxn] , father[maxn][25] , lg[maxn]; 14 void add(int u , int v) 15 { 16 tail++; 17 G[tail].u = u , G[tail].v = v , G[tail].next = head[u]; 18 head[u] = tail; 19 } 20 void dfs(int p , int fa) 21 { 22 depth[p] = depth[fa] + 1; 23 father[p][0] = fa; 24 for(int i = 1; (1 << i) <= depth[p]; i++) 25 father[p][i] = father[father[p][i - 1]][i - 1]; 26 for(int i