depth-first-search

I have a directed graph with vertexes 123456. Using a depth first search, if I wanted to be able to find the number of unique routes from 1-4 (for example), how would I go about doing it? Here is my current DFS. private final Map<Character, Node> mNodes; private final List<Edge> mEdges; private List<Node> mVisited = new ArrayList<>(); int weight; int numberOfPaths; public DepthFirstSearch(Graph graph){ mNodes = graph.getNodes(); mEdges = new ArrayList<>(graph.getEdges()); for(Node node : mNodes.values()){ node.setVisited(false); } } public void depthFirstSearch(Node source){ source.setVisited

I've recently (4 days) started to learn C++ coming from C / Java background. In order to learn a new language I ussualy start by re-implementing different classical algorithms, as language specific as I can. I've come to this code, its a DFS - Depth First Search in an unoriented graph. Still from what I read it's best to pass parameters by references in C++. Unfortunately I can't quite grasp the concept of reference. Every time I need a reference, I get confused and I think in terms of pointers. In my current code, i use pass by value . Here is the code (probably isn't Cppthonic as it should):

I am trying to implement DFS in JavaScript but I am having a little problem. Here is my Algorithm class: "use strict"; define([], function () { return function () { var that = this; this.search = function (searchFor, node) { if (searchFor === node.getValue()) { return node; } var i, children = node.getChildren(), child, found; for (i = 0; i < children.length; i += 1) { child = children[i]; found = that.search(searchFor, child); if (found) { return found; } } }; }; }); My Node class which represents a single node in the graph: "use strict"; define([], function () { return function (theValue) {

I have to develop an O(|V|+|E|) algorithm related to topological sort which, in a directed acyclic graph (DAG), determines the number of paths from each vertex of the graph to t (t is a node with out-degree 0). I have developed a modification of DFS as follow: DFS(G,t): for each vertex u ∈ V do color(u) = WHITE paths_to_t(u) = 0 for each vertex u ∈ V do if color(u) == WHITE then DFS-Visit(u,t) DFS-Visit(u,t): color(u) = GREY for each v ∈ neighbors(u) do if v == t then paths_to_t(u) = paths_to_t(u) + 1 else then if color(v) == WHITE then DFS-Visit(v) paths_to_t(u) = paths_to_t(u) + paths_to_t(v

It seems to me like Pre-order traversal and DFS are same as in both the cases we traverse till the leaf node in a depth wise fashion. Could anyone please correct me if I am wrong? Thanks in advance! Pre-order is one type of DFS. There are three types of depth-first traversal: pre-order, in-order, and post-order. Check out here for more info. It probably depends on the definition and implementation of the depth-first algorithm. The DefaultMutableTreeNode class of the Java Swing's JTree component has the following enumeration methods used for tree traversal: depthFirstEnumeration()

According to the book (Intro to Algorithm), in dfs, edges are classified as 4 kinds: Tree Edge, if in edge (u,v), v is first discovered, then (u, v) is a tree edge. Back Edge, if ......, v is discovered already and v is an ancestor, then it's a back edge. Forward Edge, if ......, v is discovered already and v is a descendant of u, forward edge it is. Cross Edge, all edges except for the above three. My question is how can I identify whether v is u's ancestor or descendant when I'm trying to figure out if (u, v) is a back or forward edge? If you really need it, you can check it by maintaining