defaults

How to change the default version of python in a linux machine ?(not just symlink) [closed]

不问归期 提交于 2019-11-27 23:59:07
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . I have multiple versions of python installed in ubuntu (precise) for various reasons and uses. I have python 2.7 and python 2.6. I need to make python 2.6 the default and not python 2.7. I updated python symlink to point to python2.6. That will only give me commandline access straight to python2.6. but when I

AttributeError: 'module' object has no attribute 'RAND_LIMIT_swigconstant

不想你离开。 提交于 2019-11-27 22:51:38
好久没有来yy了。 最近在耍openAI,安装些组件的时候出了点问题,也不算是大问题,在https://github.com/openai/gym/issues/100找到了解决方案的,我这里算是记录一下。 jonasschneider 说 One of the only references to this issue that I could dig up is http://lists.alioth.debian.org/pipermail/pkg-exppsy-pymvpa/2015q3.txt (grep for swigconstant ). For them, SWIG 3.0.6 is failing , while SWIG 3.0.2 is working . 我当时按照的时候这个小组建已经是3.0.10版本了,报了一样的错误,于是果断的把版本调到3.0.2 过程如下(用$标记的是输入的命令行): $ conda uninstall swig $ conda search swig Fetching package metadata ............... swig 2.0 . 10 py27_0 defaults 2.0 . 10 1 defaults 3.0 . 2 0 defaults 3.0 . 8 0 defaults 3.0 . 8 1

Default Values for function parameters in Python [duplicate]

偶尔善良 提交于 2019-11-27 17:57:16
Possible Duplicate: default value of parameter as result of instance method While it is possible to set default values to function parameters in python: def my_function(param_one='default') ... It seems not to be possible to access the current instance (self): class MyClass(..): def my_function(self, param_one=self.one_of_the_vars): ... My question(s): Is this true that I cannot access the current instance to set the default parameter in functions? If it is not possble: what are the reasons and is it imaginable that this will be possible in future versions of python? It's written as: def my

change matplotlib's default font

陌路散爱 提交于 2019-11-27 13:34:05
问题 I'm trying to change matplotlib's default font to Helvetica Neue. On my Mac with EPD/Canopy everything worked fine some time ago. Trying to do the same on ubuntu now and it's not working. This is what I did: Installed Helvetica Neue $ fc-match 'Helvetica Neue':Light HelveticaNeue-Light.otf: "Helvetica Neue" "細體" Converted the odt/dfont into ttf: fondu -show HelveticaNeue.dfont changed matplotlibrc to $ cat ~/.config/matplotlib/matplotlibrc ... font.family: Helvetica Neue I also tried with:

yaml 锚点&和别名*

两盒软妹~` 提交于 2019-11-27 10:29:11
& 用来建立锚点( defaults ), << 表示合并到当前数据, * 用来引用锚点。 例子: defaults: &defaults adapter: postgres host: localhost development: database: myapp_development <<: *defaults test: database: myapp_test <<: *defaults - &showell Steve - Clark - Brian - Oren - *showell    实际使用: 学习链接:http://www.ruanyifeng.com/blog/2016/07/yaml.html?f=tt   来源: https://www.cnblogs.com/erinchen/p/10619172.html

Setting Function Defaults R on a Project Specific Basis

牧云@^-^@ 提交于 2019-11-27 01:09:25
Commonly, I use the same function settings. I'm wondering if there is a method, other than having a new object in the path that is essentially a wrapper for the function, to set default arguments. For example: paste() has it's sep argument set to a space =" " , I'm tired of writing ,sep="" over and over. So is there a way to "temporarily" replace the function with my chosen defaults? paste(...,sep="") Can I accomplish this through packaging? I've sometimes noticed that, some packages force other equally named functions to be masked in the global environment. Ideally, I'd like something that

Default Values for function parameters in Python [duplicate]

随声附和 提交于 2019-11-26 19:10:45
问题 Possible Duplicate: default value of parameter as result of instance method While it is possible to set default values to function parameters in python: def my_function(param_one='default') ... It seems not to be possible to access the current instance (self): class MyClass(..): def my_function(self, param_one=self.one_of_the_vars): ... My question(s): Is this true that I cannot access the current instance to set the default parameter in functions? If it is not possble: what are the reasons

How to load packages in R automatically?

两盒软妹~` 提交于 2019-11-26 18:26:00
Could you suggest me a way for loading packages in R automatically? I mean, I want to start a session in R without needing to use library('package name') several times. Suppose I downloaded all packages I'll want to use the next time I start R. Put library(foo) in your .Rprofile file or set R_DEFAULT_PACKAGES : see ?Rprofile ... In particular (because ?Rprofile is long and potentially intimidating): If you want a different set of packages than the default ones when you start, insert a call to ‘options’ in the ‘.Rprofile’ or ‘Rprofile.site’ file. For example, ‘options(defaultPackages =

Setting Function Defaults R on a Project Specific Basis

守給你的承諾、 提交于 2019-11-26 17:28:09
问题 Commonly, I use the same function settings. I'm wondering if there is a method, other than having a new object in the path that is essentially a wrapper for the function, to set default arguments. For example: paste() has it's sep argument set to a space =" " , I'm tired of writing ,sep="" over and over. So is there a way to "temporarily" replace the function with my chosen defaults? paste(...,sep="") Can I accomplish this through packaging? I've sometimes noticed that, some packages force

jquery记录

馋奶兔 提交于 2019-11-26 17:26:19
1:插件写法 (1)对HTML标记或页面元素进行扩展,使用这种插件的扩展方式,在使用此插件时,需要首先引用经过JQuery包装的页面元素,如:$("#tableId").Method()。 (function($){ //扩展这个方法到jquery $.fn.extend({ //插件名称 one:function(options){//参数 var defaults = {//默认参数 animatePadding:"30px", defaultPadding:"0px", hoverColor:"red" } options = $.extend(defaults,options);//合并参数 return this.each(function(){//遍历匹配的每个对象 //...要执行的js var me = $("li",this); $(me).hover(function(){ $(this).css("color",defaults.hoverColor); $(this).animate({"paddingLeft":defaults.animatePadding},{queue:false,duration:200}); },function(){ $(this).css("color",""); $(this).animate({"paddingLeft"