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I have the following select statement, to grab the next scheduled item for a stream. If there is no matching row, I want it to return a default value. Here's the line I'm using: SELECT `file` FROM `show`, `schedule` WHERE `channel` = 1 AND `start_time` <= UNIX_TIMESTAMP() AND `start_time` > UNIX_TIMESTAMP()-1800 AND `show`.`id` = `schedule`.`file` ORDER BY `start_time` DESC LIMIT 1 That should grab the most recently scheduled item, but not if it's older than 30 minutes before the query. However, if the user doesn't schedule anything, I want a default value, so that something actually plays on

Most of us know the following syntax: function funcName($param='value'){ echo $param; } funcName(); Result: "value" We were wondering how to pass default values for the 'not last' paramater? I know this terminology is way off, but a simple example would be: function funcName($param1='value1',$param2='value2'){ echo $param1."\n"; echo $param2."\n"; } How do we accomplsh the following: funcName(---default value of param1---,'non default'); Result: value1 not default Hope this makes sense, we want to basically assume default values for the paramaters which are not last. Thanks. PHP doesn't

While there might be valid cases where such method overloadings could become ambiguous, why does the compiler disallow code which is neither ambiguous at compile time nor at run time? Example: // This fails: def foo(a: String)(b: Int = 42) = a + b def foo(a: Int) (b: Int = 42) = a + b // This fails, too. Even if there is no position in the argument list, // where the types are the same. def foo(a: Int) (b: Int = 42) = a + b def foo(a: String)(b: String = "Foo") = a + b // This is OK: def foo(a: String)(b: Int) = a + b def foo(a: Int) (b: Int = 42) = a + b // Even this is OK. def foo(a: Int)(b: