decimal

问题 Thats my jquery code. And the variable "procenti" always return like 92.3076923076923 % long decimal number. I would like that number to be without the decimals, only 92%. I tried .toFixed() method but it doesnt works. When the equation is like procenti=(3/10)*100; == 30%, the number in html looks just what i want without decimals. for(var i=1; i<14; i++){ var zmage=parseFloat($('#zm'+i).text()); var odigrane=parseFloat($('#od'+i).text()); var procenti=0; if(zmage == 0){ $('#pr'+(i)).html(0 +

问题 How can I convert a decimal representation of a day in the year to a timestamp with all the parts, both the full date and the time? For example, my first decimal is 22.968530853511766 and I want it in a nice timestamp format. 回答1: Use a timedelta() object with your value as the days parameter; add it to midnight December 31st of the previous year: from datetime import datetime, timedelta epoch = datetime(datetime.now().year - 1, 12, 31) result = epoch + timedelta(days=your_decimal) Demo: >>>

问题 How do I allow jmeter to generate 2 seperate decimal values and use it in 2 parameters in http requests? 回答1: You can generate a random float value using either any of JSR223 Test Elements and Groovy language or __groovy() function, the relevant code would be something like: org.apache.commons.lang3.RandomUtils.nextFloat(0.0f, 100f) in case of _groovy() function you need to escape the comma like: ${__groovy(org.apache.commons.lang3.RandomUtils.nextFloat(0.0f\, 100f),)} it will return a random

问题 I'm trying to write a function in Common Lisp to convert a base 10 number into a base 8 number, represented as a list, recursively. Here's what I have so far: (defun base8(n) (cond ((zerop (truncate n 8)) (cons n nil)) ((t) (cons (mod n 8) (base8 (truncate n 8)))))) This function works fine when I input numbers < 8 and > -8, but the recursive case is giving me a lot of trouble. When I try 8 as an argument (which should return (1 0) ), I get an error Undefined operator T in form (T) . Thanks

问题 I have a vector container. There are a number from 0 to 255. The data bytes are top (of the container). On the fourth day begins mantissa and it may consist of several numbers, for example. Mantissa consists of <120, 111, 200>. That is, it is the number of machine: <0x78, 0x6F, 0xC8>. Total turn mantissa: 0x786FC8 . I can convert because of the method: Set the number of 120, 111, 200 in hexadecimal.(0x78, 0x6F, 0xC8) Put the numbers in line.("78" "6F" "C8") Fold the line.("786FC8") Move back

问题 I'm having trouble with a particular homework assignment of mine. It almost seems impossible. The question goes like this... "In the future, you may work with other programming languages that do not have a type like decimal which supports precise monetary calculations. In those languages, you should perform such calculations using integers. Modify the application to use only integers to calculate the compound interest. Treat all monetary amounts as integral numbers of pennies. Then break the

问题 #include <stdlib.h> #include <stdio.h> #define SIZE 25 int main (void) { int d, b, c; printf(" Enter an integer and press 'enter':\n"); scanf("%d" , &d); printf(" Enter the desired base and press 'enter':\n"); scanf("%d" , &b); if (b < 2) { printf(" Your base is to low! \n") } else { while (d != 0) { int radix; radix = d % b; d = d / b; char basechars[] = "0123456789ABCDEF"; printf("%c" , basechards[radix]); } } return 0; } This Program prompts the user for a decimal and a base to convert

问题 What is the event I should subscribe to in order to get TextBox 's Text in the event args? I've tried PreviewTextInput , but if input string is, for example, "122." the box's (see code) text is without the dot but eventArgs.Text is "." and the input string validating successfully and TextBox.Text is "122..". What I want to do is to validate if the input string is decimal by calling decimal.TryParse . private void OnPreviewTextInput(object sender, TextCompositionEventArgs eventArgs) { var box

问题 So I am an absolute beginner in C and I have to make a decimal to hexadecimal converter. So I guess I would need to make a loop that loops until the result is 0. But how do I make it remember all the remainders? The number is going to be input with scanf so I can't tailor the code to it. Now I would want to do something like this while(number(n)!=0) { number0 / 16 = number1 number0 % 16 = remainder0 number1 / 16 = number2 number1 % 16 = remainder1 ..... number(n-1) / 16 = 0 number(n-1) % 16 =

问题 I'm working on a program that can convert number to its binary form. With help, I was able to get this, and it seems to work but I just don't understand how. I guess the best way to do this is to try to explain how I think this is working and someone can correct me. I have a function that has an if statement that says if n divided by 2 isn't equal to 0 then divide n by 2. Then it prints the remainder if n /2 so either 1 or 0. The main function just runs the function with whatever number I