days

How can I find the number of days between two Dates?

℡╲_俬逩灬. 提交于 2019-12-17 14:08:29
问题 I have two Date s. How can I tell the difference between these two dates in days? I have heard of SimpleDateFormat , but I don't know how to use it. I tried this: String fromdate = "Apr 10 2011"; SimpleDateFormat sdf; sdf = new SimpleDateFormat("MMM DD YYYY"); sdf.parse(fromdate); Calendar cal = Calendar.getInstance(); cal.setTime(sdf); I also tried this: String date1 = "APR 11 2011"; String date2 = "JUN 02 2011"; String format = "MMM DD YYYY"; SimpleDateFormat sdf = new SimpleDateFormat

Calculate days between two dates in Java 8

孤街浪徒 提交于 2019-12-17 02:58:39
问题 I know there are lots of questions on SO about how to get, but I want and example using new Java 8 Date api. I also know JodaTime library, but I want a work way without external libraries. Function needs to complain with these restrictions: Prevent errors from date savetime Input are two Date's objects (without time, I know localdatetime, but I need to do with date instances) 回答1: If you want logical calendar days , use DAYS.between() method from java.time.temporal.ChronoUnit: LocalDate

Google Protobuf在Netty中的使用

元气小坏坏 提交于 2019-12-16 00:23:54
[toc] Google Protobuf在Netty中的使用 程序代码来自于《Netty权威指南》第8章,已经加了注释,不过需要注意的是,使用的proto源代码是在 Google Protobuf入门与使用 中生成的,关于protobuf代码自动生成工具的使用可以参考这篇文章。 例子中,通过××× ProtobufVarint32FrameDecoder 和编码器 ProtobufVarint32LengthFieldPrepender 的使用已经解决了半包问题,测试时可以把其注释掉,这样就可以演示Netty中使用Protobuf出现的TCP粘包问题。 同时,通过protobuf的使用,也可以深刻感受到,其在Netty中的使用确实非常简单,编解码、半包问题,只需要添加相关的处理器即可,而且它可以方便地实现跨语言的远程服务调用。(protobuf本身提供了对不同语言的支持) 但其实在使用时会发现有一个问题,就是编解码的对象是需要使用其生成的特定的proto对象来进行操作的,也就是说,需要编写.proto文件,再通过protoc来生成相应语言的代码文件,显然这样做还是会有些麻烦(虽然其实也还好,不算麻烦),有没有方便点的方法呢?后面通过protostuff的使用即可解决这个问题。 服务端 SubReqServer.java package cn.xpleaf.subscribe;

LeetCode 568. Maximum Vacation Days

有些话、适合烂在心里 提交于 2019-12-15 11:03:25
原题链接在这里: https://leetcode.com/problems/maximum-vacation-days/ 题目: LeetCode wants to give one of its best employees the option to travel among N cities to collect algorithm problems. But all work and no play makes Jack a dull boy, you could take vacations in some particular cities and weeks. Your job is to schedule the traveling to maximize the number of vacation days you could take, but there are certain rules and restrictions you need to follow. Rules and restrictions: You can only travel among N cities, represented by indexes from 0 to N-1. Initially, you are in the city indexed 0 on Monday.

为JavaScript日期添加天数

谁说胖子不能爱 提交于 2019-12-14 19:58:35
如何使用 JavaScript 将天添加到当前 Date 。 JavaScript是否具有诸如.Net的 AddDay 类的内置函数? #1楼 尝试 var someDate = new Date(); var duration = 2; //In Days someDate.setTime(someDate.getTime() + (duration * 24 * 60 * 60 * 1000)); 使用setDate()添加日期不会解决您的问题,请尝试在2月增加几天,如果尝试向其添加新日期,则不会达到预期的效果。 #2楼 感谢Jason的回答能按预期工作,这是您的代码和AnthonyWJones方便的格式的结合: Date.prototype.addDays = function(days){ var ms = new Date().getTime() + (86400000 * days); var added = new Date(ms); return added; } #3楼 setDate()的Mozilla文档未指示它将处理月末情况。 参见 https://developer.mozilla.org/zh-CN/docs/JavaScript/Reference/Global_Objects/Date 设置日期() 根据当地时间设置指定日期的月份(1-31)。

MYSQL中的日期时间转换

為{幸葍}努か 提交于 2019-12-14 10:35:50
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 对于每个类型拥有的值范围以及并且指定日期何时间值的有效格式的描述见7.3.6 日期和时间类型。 这里是一个使用日期函数的例子。下面的查询选择了所有记录,其date_col的值是在最后30天以内: mysql> SELECT something FROM table WHERE TO_DAYS(NOW()) - TO_DAYS(date_col) <= 30; DAYOFWEEK(date) 返回日期date的星期索引(1=星期天,2=星期一, ……7=星期六)。这些索引值对应于ODBC标准。 mysql> select DAYOFWEEK('1998-02-03'); -> 3 WEEKDAY(date) 返回date的星期索引(0=星期一,1=星期二, ……6= 星期天)。 mysql> select WEEKDAY('1997-10-04 22:23:00'); -> 5 mysql> select WEEKDAY('1997-11-05'); -> 2 DAYOFMONTH(date) 返回date的月份中日期,在1到31范围内。 mysql> select DAYOFMONTH('1998-02-03'); -> 3 DAYOFYEAR(date) 返回date在一年中的日数, 在1到366范围内。

How to get days and months number from a given days

这一生的挚爱 提交于 2019-12-13 06:46:13
问题 I'm going to write a function to print a number of days left between two dates. I would like it to tell the months and days left. For example: 45 days = 1month, 15 days 65 days = 2months, 5 days 10 days = 10 days So I tried: <? $days=50; if($days>"31"){ $time=$days/30; } echo $time;//1.67 month ?> According to the code above. I expect the result to be like: 1 month, 20 days Could you guys please suggest. 回答1: Try: $days = 50; if ($days > 31){ $month = floor($days/30); // return lowest whole

Angular Material Date Picker Set Only a Particular Day of Week Selectable (Eg: Monday)

走远了吗. 提交于 2019-12-13 02:11:59
问题 I wonder is there any filtering mechanism for the Angular Material Date Picker, So that I can set only Mondays are selectable from the Date Picker. Thanks in Advance. Regards... 回答1: Yes. There is an attribut called md-date-filter which you can use to specify the day you want to be selected by user. In the below example as you are returing return day === 1; It will allow to select mondays only. you can change it from o to 7 as required. html view file <md-datepicker ng-model="myDate" md

PHP getting month dates and placing into array

给你一囗甜甜゛ 提交于 2019-12-12 03:09:09
问题 Today I found this function that says how many days were in a month cal_days_in_month() . But what I am wanting to do is list all the days into array, something like this. $days = array( "2012-11-01","2012-12-01","2012-13-01"...etc ) Could someone point me into the right direction? Kind regards Frank! 回答1: $start = new DateTime('first day of this month'); $end = new DateTime('first day of next month'); $interval = DateInterval::createFromDateString('1 day'); $period = new DatePeriod($start,

聚宽源码41

﹥>﹥吖頭↗ 提交于 2019-12-12 02:47:17
原文策略源码如下: #价值投资策略 from kuanke.wizard import * from jqdata import * import numpy as np import pandas as pd import talib import datetime 初始化函数,设定要操作的股票、基准等等 def initialize(context): # 设定基准 set_benchmark(‘000300.XSHG’) # 设定滑点 set_slippage(FixedSlippage(0.02)) # True为开启动态复权模式,使用真实价格交易 set_option(‘use_real_price’, True) # 设定成交量比例 set_option(‘order_volume_ratio’, 1) # 股票类交易手续费是:买入时佣金万分之三,卖出时佣金万分之三加千分之一印花税, 每笔交易佣金最低扣5块钱 set_order_cost(OrderCost(open_tax=0, close_tax=0.001, open_commission=0.00015, close_commission=0.00015, min_commission=5), type=‘stock’) # 个股最大持仓比重 g.security_max_proportion = 1 #