days | 易学教程

Calculate number of days remaining [duplicate]

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问题 This question already has answers here : Finding the number of days between two dates (30 answers) Closed last month . I would like to calculate the number of days remaining before a date. In my database I have a timestamp corresponding to the end date. For example Friday 30. I would like to say something like that : 7 days remaining... 6, 5, 4, etc Can you help me please ? 回答1: $future = strtotime('21 July 2012'); //Future date. $timefromdb = //source time $timeleft = $future-$timefromdb;

Kaggle教程特征工程3 Feature Generation

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《Kaggle教程特征工程》系列课程目录 Kaggle教程特征工程1 Baseline-Model Kaggle教程特征工程2 Categorical Encodings Kaggle教程特征工程3 Feature Generation Kaggle教程特征工程4 Feature Selection 1. 介绍从原始数据创建新特性是改进模型的最佳方法之一。例如，您可以计算最后一周的项目总数和筹款周期的持续时间。您创建的功能对于每个数据集都是不同的，因此需要一点创造力和实验。我们在这里有点受限，因为我们只处理一个表。通常，您可以访问多个具有相关数据的表，您可以使用这些数据来创建新特性。但是您仍然可以看到如何使用分类特性创建新特性，以及一些生成数值特性的示例。下面是加载数据并执行您已经看到的功能工程的代码。 % matplotlib inline import matplotlib . pyplot as plt import numpy as np import pandas as pd from pandas . plotting import register_matplotlib_converters register_matplotlib_converters ( ) from sklearn . preprocessing import

Get number of weekdays in a given month

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问题 I want to calculate the number of weekdays days in a give month and year. Weekdays means monday to friday. How do i do it ? 回答1: Some basic code: $month = 12; $weekdays = array(); $d = 1; do { $mk = mktime(0, 0, 0, $month, $d, date("Y")); @$weekdays[date("w", $mk)]++; $d++; } while (date("m", $mk) == $month); print_r($weekdays); Remove the @ if your PHP error warning doesn't show notices. 回答2: You don't need to count every day in the month. You already know the first 28 days contain 20

Usaco. Friday the thirteen. What is wrong with my code?

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问题 I've made a program for the USACO task and now I just can't figure out why I'm getting the bad answer, I've been thinking why for a long time and still didn't figure it out. What could be wrong? The task is to count the number of times the 13th falls on Saturday, Sunday, Monday, Tuesday, ..., Friday. The year from when to test is 1900 and the last year is given in the txt file. Instead of this answer: 36 33 34 33 35 35 34 I'm getting: 34 33 33 33 36 36 35 Thank you very very very much for you

Usaco. Friday the thirteen. What is wrong with my code?

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Number of Days Conversion in Java

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问题 I need to use the modulo operand to convert an inputted number of days to its equivalent number of year/s, month/s, week/s, and days. We just started discussion yesterday so I'm still a bit rusty but this is the program I made: import java.util.Scanner; public class DaysConvert { public static void main(String[] args) { Scanner input = new Scanner(System.in); int noOfDays, year, month, week, days; System.out.print("Enter Number of Days: "); noOfDays = input.nextInt(); year = noOfDays/365;

Creating a tenure column in Days in R

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问题 *Edited I am trying to create a column in a df that shows me the day number in a client's tenure. Here is the code to create a mock df for this:- Date<-c("20/07/2018", "21/07/2018", "25/07/2018", "02/08/2018", "05/08/2018", "10/08/2018") ClientId<-c("aaa", "bbb", "ccc", "aaa", "bbb", "ccc") EventId<-c("klk109", "rrt234", "hjk786", "yyu777", "tyw909", "nnl991") dateclient<-cbind(Date, ClientId) LoginDates<-cbind(dateclient, EventId) View(LoginDates) which should give you something like this:-

finding numbers of days between two date to make a dynamic columns

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问题 Dear all, I have a select query that currently produces the following results: DoctorName Team 1 2 3 4 5 6 7 ... 31 Visited dr. As A x x ... 2 times dr. Sc A x ... 1 times dr. Gh B x ... 1 times dr. Nd C ... x 1 times Using the following query: DECLARE @startDate = '1/1/2010', @enddate = '1/31/2010' SELECT d.doctorname, t.teamname, MAX(CASE WHEN ca.visitdate = 1 THEN 'x' ELSE NULL END) AS 1, MAX(CASE WHEN ca.visitdate = 2 THEN 'x' ELSE NULL END) AS 2, MAX(CASE WHEN ca.visitdate = 3 THEN 'x'

JoinQuant策略代码示例

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总体回测前 ''' ================================================================================ 总体回测前 ================================================================================ ''' #总体回测前要做的事情 def initialize(context): set_params() #1设置策参数 set_variables() #2设置中间变量 set_backtest() #3设置回测条件 #1 #设置策略参数 def set_params(): g.tc=15 # 调仓频率 g.N=4 #持仓数目 g.security = ["000001.XSHE","000002.XSHE","000006.XSHE","000007.XSHE","000009.XSHE"]#设置股票池 #2 #设置中间变量 def set_variables(): return #3 #设置回测条件 def set_backtest(): set_option('use_real_price', True) #用真实价格交易 log.set_level('order', 'error') 每天开盘前 ''' ========

How do I get the number of days for a duration where the number of hours exceeds 24 in google sheets?

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问题 I am using google sheets where there is a duration value of 69:41:00 where it's 69 hours, 41 minutes, 0 secs. There doesn't seem to be a function to convert this to days, hours and minutes so I did some searching and some had suggested a custom function. Not sure exactly how it works but made some changes from the original to fit what I needed. The code below: /** * Format Duration to Days,Hours,Minutes * * @param {duration} input value. * @return Days,Hours,Minutes. * @customfunction */