days

Increase days to php current Date()

巧了我就是萌 提交于 2019-11-27 18:20:01
How do I add a certain number of days to the current date in PHP? I already got the current date with: $today = date('y:m:d'); Just need to add x number of days to it php supports c style date functions. You can add or substract date-periods with English-language style phrases via the strtotime function. examples... $Today=date('y:m:d'); // add 3 days to date $NewDate=Date('y:m:d', strtotime("+3 days")); // subtract 3 days from date $NewDate=Date('y:m:d', strtotime("-3 days")); // PHP returns last sunday's date $NewDate=Date('y:m:d', strtotime("Last Sunday")); // One week from last sunday

Joda time - all mondays between two dates

陌路散爱 提交于 2019-11-27 16:31:37
问题 I am using Joda time api in a Spring 3.0 project for the very first time. Now I have a start and end date and I want to get the date for all mondays between these two dates. How can I do this ? I have no idea where to start, can someone please advise. I looked at theis post Joda Time: How to get dates of weekdays on some date interval? and it offered some sort of guidance but its still somewhat vague due to little experience with joda. 回答1: LocalDate startDate = new LocalDate(2011, 11, 8);

Get number of weekdays in a given month

狂风中的少年 提交于 2019-11-27 15:41:44
I want to calculate the number of weekdays days in a give month and year. Weekdays means monday to friday. How do i do it ? Some basic code: $month = 12; $weekdays = array(); $d = 1; do { $mk = mktime(0, 0, 0, $month, $d, date("Y")); @$weekdays[date("w", $mk)]++; $d++; } while (date("m", $mk) == $month); print_r($weekdays); Remove the @ if your PHP error warning doesn't show notices. You don't need to count every day in the month. You already know the first 28 days contain 20 weekdays no matter what. All you have to do is determine the last few days. Change the start value to 29. Then add 20

Algorithm to add or subtract days from a date?

拜拜、爱过 提交于 2019-11-27 08:52:35
I'm trying to write a Date class in an attempt to learn C++. I'm trying to find an algorithm to add or subtract days to a date, where Day starts from 1 and Month starts from 1. It's proving to be very complex, and google doesn't turn up much, Does anyone know of an algorithm which does this? The easiest way is to actually write two functions, one which converts the day to a number of days from a given start date, then another which converts back to a date. Once the date is expressed as a number of days, it's trivial to add or subtract to it. You can find the algorithms here: http://alcor

How can I calculate the number of days between two dates in Perl?

耗尽温柔 提交于 2019-11-27 04:34:13
问题 Heylo, I want to calculate (using the default Perl installation only) the number of days between two dates. The format of both the dates are like so 04-MAY-09. (DD-MMM-YY) I couldn't find any tutorials that discussed that date format. Should I be building a custom date checker for this format? Further reading of the Date::Calc on CPAN it looks unlikely that this format is supported. Thanks. 回答1: If you care about accuracy, keep in mind that not all days have 86400 seconds. Any solution based

How can I compare two dates, return a number of days

倾然丶 夕夏残阳落幕 提交于 2019-11-27 04:27:54
问题 how can I compare two dates return number of days. Ex: Missing X days of the Cup. look my code. NSDateFormatter *df = [[NSDateFormatter alloc]init]; [df setDateFormat:@"d MMMM,yyyy"]; NSDate *date1 = [df dateFromString:@"11-05-2010"]; NSDate *date2 = [df dateFromString:@"11-06-2010"]; NSTimeInterval interval = [date2 timeIntervalSinceDate:date1]; //int days = (int)interval / 30; //int months = (interval - (months/30)) / 30; NSString *timeDiff = [NSString stringWithFormat:@"%dMissing%d days of

JavaScript format number to day with always 3 digits [duplicate]

本小妞迷上赌 提交于 2019-11-26 23:21:45
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: How can I create a Zerofilled value using JavaScript? I have to output a day number that must always have 3 digits. Instead of 3 it must write 003 , instead of 12 it must write 012 . If it is greater than 100 output it without formatting. I wonder if there's a regex that I could use or some quick in-line script, or I must create a function that should do that and return the result. Thanks! 回答1: How about:

Increase days to php current Date()

喜夏-厌秋 提交于 2019-11-26 22:40:50
问题 How do I add a certain number of days to the current date in PHP? I already got the current date with: $today = date('y:m:d'); Just need to add x number of days to it 回答1: php supports c style date functions. You can add or substract date-periods with English-language style phrases via the strtotime function. examples... $Today=date('y:m:d'); // add 3 days to date $NewDate=Date('y:m:d', strtotime("+3 days")); // subtract 3 days from date $NewDate=Date('y:m:d', strtotime("-3 days")); // PHP

Grouping records hour by hour or day by day and filling gaps with zero or null

柔情痞子 提交于 2019-11-26 21:27:32
问题 I have written a query that counts records hour by hour: select TO_CHAR(copied_timestamp, 'YYYY-MM-DD HH24'),count(*) from req group by TO_CHAR(copied_timestamp, 'YYYY-MM-DD HH24'); the result is: 2012-02-22 13 2280 2012-02-22 15 1250 2012-02-22 16 1245 2012-02-22 19 1258 But I need a result like this: 2012-02-22 13 2280 2012-02-22 14 0 2012-02-22 15 1250 2012-02-22 16 1245 2012-02-22 17 0 2012-02-22 18 0 2012-02-22 19 1258 Also I have these queries that group by day and month too! select TO

制作日历组件,点击出来一个弹窗

末鹿安然 提交于 2019-11-26 19:50:07
实现效果如下图:点击弹出弹窗(弹窗用iview的modal组件),在输入框填写并存储(用了一下localstorage来存储),这个组件参考了条链接, 原文存储的功能链接 ,还有以为博主的日历实现后续找到补上。按需选取吧代码部分。 代码贴上 CSS 1 .calender { 2 text-align: center; 3 min-width: 280px; 4 /* height: 400px; */ 5 overflow: hidden; 6 } 7 .calender-title-wrapper { 8 height: 30px; 9 line-height: 30px; 10 } 11 12 .calender-title { 13 display: -moz-box; 14 display: -webkit-box; 15 display: -ms-flexbox; 16 display: -webkit-flex; 17 display: flex; 18 display: flex; 19 margin: 0 auto; 20 width: 280px; 21 } 22 23 .calender-arrow-item { 24 flex: 0 0 30px; 25 cursor: pointer; 26 } 27 .calender-arrow-item.left1,