days

#include <stdio.h> int main() { int days; printf("输入一个整数: \n"); scanf("%d",&days); if(days<=5&&days>=1) printf("学习\n"); else if(days==7||days==6) printf("休息\n"); else printf("Ooops, not in 1~7\n"); return 0; } 来源： https://www.cnblogs.com/ras123/p/11688277.html

#include<stdio.h> int main() { int days; printf("please input:\n"); scanf("%d",&days); if(days>=1||days<=5) printf("workdays,fighting\n"); else if(days==6||days==7) printf("weekend,relax~\n"); else printf("Oops,not in 1~7\n"); getchar(); return 0; } 来源： https://www.cnblogs.com/faspk/p/11684295.html

python语言中的datetime模块可以利用其中的方法获取不同的日期，比如获取当前日期、明天、昨天、上个月、下个月和明年。下面利用几个实例说明这些日期的获取方法，操作如下： 第一步，利用datetime模块获取当前日期 datetime.date.today(); 如下图所示： 第二步，获取当前日期前一天日期，利用当前日期减去一天，如下图所示： 第三步，获取当前日期后一天日期，利用当前日期加上一天，如下图所示： 第四步，获取当前日期下一个月日期，利用当前日期加上30天，如下图所示： 第五步，获取当前日期上一个月的日期，利用当前日期减去30天，如下图所示： 第六步，获取当前日期返回明年今天的日期，利用当前日期加上365天，如下图所示： # -*- coding: utf-8 -*- #----------------------------------------------------------------------------------- import datetime #获取366天前的日期 day=(datetime.date.today() - datetime.timedelta(days=366)).strftime('%Y-%m-%d') print(day) #获取366天后的日期 day=(datetime.date.today() + datetime

Description： Polycarp analyzes the prices of the new berPhone. At his disposal are the prices for n last days: a1,a2,…,an, where ai is the price of berPhone on the day i. Polycarp considers the price on the day i to be bad if later (that is, a day with a greater number) berPhone was sold at a lower price. For example, if n=6 and a=[3,9,4,6,7,5], then the number of days with a bad price is 3 — these are days 2 (a2=9), 4 (a4=6) and 5 (a5=7). Print the number of days with a bad price. You have to answer t independent data sets. Input： The first line contains an integer t (1≤t≤10000) — the number

1. 概述 Specify the number of days of snapshots to choose from ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Entering the number of days (n) will result in the most recent (n) days of snapshots being listed. Pressing <return> without specifying a number lists all completed snapshots. Enter value for num_days: 2 Listing the last 2 days of Completed Snapshots Snap Instance DB Name Snap Id Snap Started Level ------------ ------------ --------- ------------------ ----- orcl ORCL 4759 29 Mar 2028 17:04 1 现象：查看snapshot生成历史，发现很长一段时间都没有生成snapshot 这是一个开发数据库，经过和开发沟通，由于业务测试经常修改操作服务器系统时间。 原因分析

package com.industry.base.util; import java.text.SimpleDateFormat; import java.util.Calendar; import java.util.Date; import java.util.Locale; /** * 以友好的方式展示时间 * * @author z * @date 2018/3/31 13:53 */ public class TimeFriendlyUtil { private final static ThreadLocal<SimpleDateFormat> dateFormater2 = new ThreadLocal<SimpleDateFormat>() { @Override protected SimpleDateFormat initialValue() { return new SimpleDateFormat("yyyy-MM-dd"); } }; private static final int SEC = 1000; private static final int MIN = 60000; private static final int HOUR = 3600000; private static final int DAY = 86400000; /**

//显示所有容器 一个容器只管理一个服务 即使容器挂掉也不会影响其他容器的服务 做到业务之间不影响root@river-NUC8i7HNK:/# docker ps CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES e8cfcbe6a280 etl-online:1.0 "java -Djava.securit…" About an hour ago Up About an hour 0.0.0.0:8070->8070/tcp etl-online_etl-online_1 377db9b29f0f web:3.0 "java -Djava.securit…" 11 days ago Up 11 days 0.0.0.0:30003->30003/tcp web_power_1 cf44fc608372 power:2.0 "java -Djava.securit…" 11 days ago Up 11 days 0.0.0.0:8000->30001/tcp power_power_1 4f951b13e170 etl:2.0 "java -Djava.securit…" 2 weeks ago Up 2 weeks 0.0.0.0:8090->8090/tcp etl_power_1 524d7d7ae738

var myDate = new Date(); var year = myDate.getFullYear(); //年 var month = myDate.getMonth() + 1; //月 var day = myDate.getDate(); //日 var days = myDate.getDay(); switch (days) { case 1: days = '星期一'; break; case 2: days = '星期二'; break; case 3: days = '星期三'; break; case 4: days = '星期四'; break; case 5: days = '星期五'; break; case 6: days = '星期六'; break; case 0: days = '星期日'; break; } console.log(year + "年" + month + "月" + day + "日 " + days) 来源： https://www.cnblogs.com/xiaoxiao2017/p/11648269.html