days

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Following in the spirit of this answer , I attempted the following to convert a DataFrame column of datetimes to a column of seconds since the epoch. df['date'] = (df['date']+datetime.timedelta(hours=2)-datetime.datetime(1970,1,1)) df['date'].map(lambda td:td.total_seconds()) The second command causes the following error which I do not understand. Any thoughts on what might be going on here? I replaced map with apply and that didn't help matters. --------------------------------------------------------------------------- AttributeError

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm Trying to get the current date plus 7 days to display. Example: Today is August 16, 2012, so this php snippet would output August 23, 2012. $date = strtotime ( $date ); $date = strtotime ( "+7 day" , $date ); echo date ( 'M d, Y' , $date ); Right now, I'm getting: Jan 08, 1970. What am I missing? 回答1: strtotime will automatically use the current unix timestamp to base your string annotation off of. Just do: $date = strtotime ( "+7 day" ); echo date ( 'M d, Y' , $date ); Added Info For Future Visitors: If you need to pass a

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How is it possible to make the code below convert days in hours? $timestart = date_create('02/11/2011' . $row->timestart); //$row->timestart returns time in 00:00:00 format $timestop = date_create('02/11/2011' . $row->timestop); //$row->timestop returns time in 00:00:00 format date_add($timestop, date_interval_create_from_date_string('2 days')); //add 2 days $date_diff = date_diff($timestart, $timestop); echo "Timespan: "; echo $date_diff->format('%h hours'); echo "<br />"; How can I get the hours:minutes:seconds elapsed? I'm trying to stay

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to get the birthdays in the upcoming 20 days, given the below Person model: class Person(models.Model): dob = models.DateField() # date of birth There are similar questions on SO already ( here and here ), but these do not cover my use case, as I'm storing a date of birth instead of the next birthday or a timefield. I've tried to do some things like the following: from datetime import timedelta, date today = date.today() next_20_days = today+timedelta(days=20) Person.objects.filter(dob__month=today.month, dob__day__range=[today

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to calculate price for number of days from 1-21 based on date. HomeController $Sql = ' SELECT DISTINCT a.property_id, a.date, a.minimum_stay, a.maximum_stay,a.quantity, a.arrival_allowed,a.departure_allowed, p.duration, p.persons, p.amount, p.extra_person_price, p.minimum_stay AS price_minimum_stay, p.maximum_stay AS price_maximum_stay, p.weekdays, p.period_till, p.period_from, datediff(p.period_till, p.period_from) AS number_of_days FROM availabilities AS a JOIN prices AS p ON a.property_id=p.property_id WHERE a.minimum_stay >0

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to get the birthdays in the upcoming 20 days, given the below Person model: class Person(models.Model): dob = models.DateField() # date of birth There are similar questions on SO already ( here and here ), but these do not cover my use case, as I'm storing a date of birth instead of the next birthday or a timefield. I've tried to do some things like the following: from datetime import timedelta, date today = date.today() next_20_days = today+timedelta(days=20) Person.objects.filter(dob__month=today.month, dob__day__range=[today

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: good morning together, i developing an android app and i get crazy! since a few days, i try to get the difference days between 2 dates. i realize it with joda time - this seems to work. DatePicker datepicker = (DatePicker) findViewById(R.id.Picker); Calendar cal = Calendar.getInstance(); cal.set(Calendar.YEAR, datepicker.getYear()); cal.set(Calendar.MONTH, datepicker.getMonth()); cal.set(Calendar.DATE, datepicker.getDayOfMonth()); cal.set(Calendar.HOUR_OF_DAY, 0); cal.set(Calendar.MINUTE, 0); cal.set(Calendar.SECOND, 0); long sqlDate = cal

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an array with n strings in format of YYYY-MM-DD (Example, "2010-10-31"). How do I compare a date to the strings in this array? For example, delete the strings more than 30 day ago? 回答1: use strict; use warnings; use DateTime (); use DateTime::Duration (); use DateTime::Format::Natural (); my $parser = DateTime::Format::Natural->new; my $now = DateTime->now; my $delta = DateTime::Duration->new( days => 30 ); my $cutoff = $now->subtract_duration( $delta ); my @new_dates = map { $_->[1] } grep { -1 == $_->[0] } map { chomp; [ DateTime-

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an array with n strings in format of YYYY-MM-DD (Example, "2010-10-31"). How do I compare a date to the strings in this array? For example, delete the strings more than 30 day ago? 回答1: use strict; use warnings; use DateTime (); use DateTime::Duration (); use DateTime::Format::Natural (); my $parser = DateTime::Format::Natural->new; my $now = DateTime->now; my $delta = DateTime::Duration->new( days => 30 ); my $cutoff = $now->subtract_duration( $delta ); my @new_dates = map { $_->[1] } grep { -1 == $_->[0] } map { chomp; [ DateTime-

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I really need some help with the specific assignment. The user inputs birth data (YYYY MM DD) and the program tells you how old you are in days : The outprint in console would be You are for example born 1981 11 06 You are 7068 days old. I've rewritten my code maybe 20 times without success, and any help would be so much appreciated, i'm kinda new so everything will be helpful! thanks a lot in advance, Sebastian. // the code ... :) EDITED .. I RE-WROTED THE CODE, since it didnt work anyhow i twisted and turned it so i changed it completly,