dayofweek

How can I order the mysql result by varchar column that contains day of week name? Note that MONDAY should goes first, not SUNDAY. Glen Solsberry Either redesign the column as suggested by Williham Totland, or do some string parsing to get a date representation. If the column only contains the day of week, then you could do this: ORDER BY FIELD(<fieldname>, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY'); Joseph Manganelli Why not this? ORDER BY ( CASE DAYOFWEEK(dateField) WHEN 1 THEN 7 ELSE DAYOFWEEK(dateField) END ) I believe this orders Monday to Sunday... I'm

The simplest way: String[] namesOfDays = new String[7] { "SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT" }; This method does not use Locale. Therefore, if the system's language is not English, this method does not work properly. Using Joda time, we can do like this: String[] namesOfDays = new String[7]; LocalDate now = new LocalDate(); for (int i=0; i<7; i++) { /* DateTimeConstants.MONDAY = 1, TUESDAY = 2, ..., SUNDAY = 7 */ namesOfDays[i] = now.withDayOfWeek((DateTimeConstants.SUNDAY + i - 1) % 7 + 1) .dayOfWeek().getAsShortText(); } However, this method uses today's date and calendar

How to find a speciefic nearest day of the week in PHP if initially I have a date string like: 07.05.2010 ? For example, I want to find the nearest Sunday (or any day of the week). How can I implement this? Thanks This should do: echo date('d.m.Y', strtotime('next Sunday', strtotime('07.05.2010'))); Just in case you wanted the nearest day rather than the next one, here is a way to do that. $target = "Sunday"; $date = "07.05.2010"; // Old-school DateTime::createFromFormat list($dom, $mon, $year) = sscanf($date, "%02d.%02d.%04d"); $date = new DateTime("$year/$mon/$dom -4 days"); // Skip ahead to

Suppose my date is 02-01-2013 and it is stored in a variable like: String strDate = "02-01-2013"; then how should I get the day of this date (i.e TUESDAY)? Use Calendar class from java api. Calendar calendar = new GregorianCalendar(2008, 01, 01); // Note that Month value is 0-based. e.g., 0 for January. int reslut = calendar.get(Calendar.DAY_OF_WEEK); switch (result) { case Calendar.MONDAY: System.out.println("It's Monday !"); break; } You could also use SimpleDateFormater and Date for parsing dates Date date = new Date(); SimpleDateFormat date_format = new SimpleDateFormat("yyyy-MM-dd"); try

I am running SQL Server 2008 on a machine with regional settings that have Monday as the first day of the week. If I create a computed column in a table to compute the day of week for a date field then I get 2 for a Monday date instead of 1. Is there some property for the table or database or server that I need to set ? The first day of the week is based on your language settings of the server. The default setting for us_english is 7 (Sunday) You can find the current first day of the week by using SELECT @@DATEFIRST However, you can use DATEFIRST for this. Just put it at the top of your query

How do I get the day of a week in integer format? I know ToString will return only a string. DateTime ClockInfoFromSystem = DateTime.Now; int day1; string day2; day1= ClockInfoFromSystem.DayOfWeek.ToString(); /// it is not working day2= ClockInfoFromSystem.DayOfWeek.ToString(); /// it gives me string Use day1 = (int)ClockInfoFromSystem.DayOfWeek; int day = (int)DateTime.Now.DayOfWeek; First day of the week: Sunday (with a value of zero) If you want to set first day of the week to Monday with integer value 1 and Sunday with integer value 7 int day = ((int)DateTime.Now.DayOfWeek == 0) ? 7 : (int