datetime-format

问题 I am trying to convert this time format - 1480550400000+0000 in Y/m/d date format using php date('Y/m/d',1480550400000+0000) ; but its not working. How can I make it work? 回答1: You timestamp has microseconds, so first remove it. <?php $timestamp = 1480550400000+0000; $timestamp = intval($timestamp/1000); $date = date("Y/m/d", $timestamp); echo $date; output: Check the live demo . ei@localhost:~$ php test.php 2016/12/01 回答2: $dig_date= 1480550400000+0000; $date = DateTime::createFromFormat(

问题 objTour.tourStartDate = Convert.ToDateTime( DateTime.ParseExact(txtTourStartDate.Text, "dd/MM/yyyy", null) .ToString("MM/dd/yyyy")); where txtTourStartDate.Text="16/08/2012" . I have searched and read all posts related to this. 回答1: In a custom date format string, / denotes the culture-specific date separator, not the literal character / . Thus, the result of your code depends on the user's (or the server's) localization settings. To make your code independent of culture-specific settings,

问题 I need to subtract minutes from the calculated time var calculatedTime=11.30;// hours var subtractTime=40;//minutes var diff=calculatedTime - subtractTime;// How to do this ?? How to do this in javascript Thanks 回答1: Try this: function converToMinutes(s) { var c = s.split('.'); return parseInt(c[0]) * 60 + parseInt(c[1]); } function parseTime(s) { return Math.floor(parseInt(s) / 60) + "." + parseInt(s) % 60 } //var minutes = parseTime(EndTIme) - parseTime(StartTime); var timeToSubtract = 40;

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: How do I calculate relative time? How to display “12 minutes ago” etc in a PHP webpage? I have date formats like this: 2011-09-10 12:00:00 2011-09-12 11:02:05 2011-09-12 I want to create a function that will get a date and will output something like this ? 5 minutes ago 2 hours ago today yesterday and show date if date is far away. Is there any related function in php or any free already written library. Thanks

问题 in a powerpoint vba application I want to format a date according to the current spell-check language (which may or may not be the same as the system locale language). e.g. Locale is German(Austria) but the document is in English for an english customer, hence the date format should be "1st January 2015" and not "01. Jänner 2015" I found a solution for excel on this site: How to change the locale of a formatted date? trying the same technique in powerpoint vba does not appear to work: debug

问题 I'm trying to insert date in dd-MM-yyyy format in c#. Query for inserting is SqlCommand cmd_cust = new SqlCommand(@"insert into custdetail values ('" + txtInvoiceNo.Text + "','" + txtCustomerName.Text + "','" + txt_contact.Text + "', '" + txtAddress.Text + "', '" + txt_total_amt.Text + "', '" + dt_date.Value.ToString("dd-MM-yyyy") + "')", con_create); con_create.Open(); cmd_cust.ExecuteNonQuery(); con_create.Close(); I have created table with column name date has datatype date . After

问题 How can I convert a DataFrame column of strings (in dd/mm/yyyy format) to datetimes? 回答1: The easiest way is to use to_datetime: df['col'] = pd.to_datetime(df['col']) It also offers a dayfirst argument for European times (but beware this isn't strict). Here it is in action: In [11]: pd.to_datetime(pd.Series(['05/23/2005'])) Out[11]: 0 2005-05-23 00:00:00 dtype: datetime64[ns] You can pass a specific format: In [12]: pd.to_datetime(pd.Series(['05/23/2005']), format="%m/%d/%Y") Out[12]: 0 2005

问题 How to convert the below in character to Date format? YYYY.MM I am facing an issue dealing with zeroes after decimal points for month 10. Say 2012.10 appears in my input source data as 2012.1 with the zero post decimal missing. How do I bring this back in the Date format? 回答1: Since you have only year and month , you need to assign some value for day before you convert to date. In the example below, the day has arbitrarily been chosen as 15 . IF THE INPUT IS CHARACTER dates = c("2012.10",

问题 I'm working with a software that uses a lot of DateTimeFormat parsing, in order to minimize the errors, I wonder if I can present the date String in a certain way that it can be parsed by any DateTimeFormat pattern. Ideally it should work as follows: String date = "...." DateTimeFormatter format = DateTimeFormat.forPattern(any pattern I want); DateTime result = format.parseDateTime(date); Or does the date have to follow the pattern? Thanks for your help 回答1: No, you can not get one size fits

问题 Im trying to make a website using Spring + Angular JS and my current problem is i used POSTMAN to post a JSON statement as below: { "id": 12345, "checkin" : "2017-03-01", "checkout" : "2017-03-05" } and then this error pops up: enter image description here "Type definition error: [simple type, class java.time.LocalDate]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of java.time.LocalDate (no Creators, like default construct,