datediff

how can I subtract time from time for time remaining?

由 。_饼干妹妹 提交于 2019-12-05 22:53:16
Using JavaScript, How can I subtract from HH:MM:SS? For example, I have 12:54:45 and I want to subtract 11:35:53 for remaining time in 4732 seconds var first = (new Date('Jan 01, 2000 12:54:45')).getTime(); var second = (new Date('Jan 01, 2000 11:35:53')).getTime(); var differenceInSeconds = (second - first) / 1000; // 4732 I chose 2000-01-01 as the date, as it does not matter as long it is the same. We only want to calculate the difference. This works (Date.parse('January 1, 1970 12:54:45') - Date.parse('January 1, 1970 11:35:53')) / 1000 Output is 4732 There are libraries that makes possible

DATEDIFF in SPARK SQl

由 冷暖自知 提交于 2019-12-05 21:32:52
问题 I am new to Spark SQL. We are migrating data from SQL server to Databricks. I am using SPARK SQL . Can you please suggest how to achieve below functionality in SPARK sql for the below datefunctions. I can see datediff gives only days in spark sql. DATEDIFF(YEAR,StartDate,EndDate) DATEDIFF(Month,StartDate,EndDate) DATEDIFF(Quarter,StartDate,EndDate) 回答1: As you have mentioned SparkSQL does support DATEDIFF but for days only. I would also be careful as it seems the parameters are the opposite

How to get current date/time as a date object in PHP

由 不打扰是莪最后的温柔 提交于 2019-12-05 10:48:00
问题 How do you get today's date, as a date object? I'm trying to compute the difference between some start date and today. The following will not work, because getdate() returns an array and not a date object: $today = getdate(); $start = date_create('06/20/2012'); $diff = date_diff($start, $today); echo($today . '<br/>' . $start . '<br/>' . $diff); Output: Array ( [seconds] => 8 [minutes] => 1 [hours] => 16 [mday] => 11 [wday] => 1 [mon] => 6 [year] => 2012 [yday] => 162 [weekday] => Monday

Oracle equivalent to SQL Server/Sybase DateDiff

由 一笑奈何 提交于 2019-12-05 10:46:42
We are now using NHibernate to connect to different database base on where our software is installed. So I am porting many SQL Procedures to Oracle. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. Date parts examples are day, week, month, year, etc. . . What is the Oracle equivalent? I have not found one do I have to create my own version of it? (update by Mark Harrison) there are several nice answers that explain Oracle date arithmetic. If you need an Oracle datediff() see Einstein's answer. (I need this to keep spme SQL scripts compatible

Is timestampdiff() in MySQL equivalent to datediff() in SQL Server?

由 雨燕双飞 提交于 2019-12-05 06:45:46
I am working on migrating functions from SQL Server 2000 to MySQL. The following statement executed in SQL Server 2000, gives the output as 109. SELECT DATEDIFF(wk,'2012-09-01','2014-10-01') AS NoOfWeekends1 The equivalent query of in mysql uses timestampdiff() instead of datediff and gives the output as 108. SELECT TIMESTAMPDIFF(WEEK, '2012-09-01', '2014-10-01') AS NoOfWeekends1 I need the output to match when executed in MySQL, so it returns 109. I think this could be caused by one of 2 things: What is classified as the first day of the week between your SQL Server and MySQL instances. How

date_diff() expects parameter 1 to be DateTimeInterface, string given

由 ▼魔方 西西 提交于 2019-12-04 18:43:48
问题 i got this problem and i don't know what to do... they have thesame format $date_expire = '2014-08-06 00:00:00'; $date1 = date("Y-m-d G:i:s"); $date2 = date_create($date_expire); $diff = date_diff($date1, $date2); //this line makes error.. 回答1: Because you are passing string whereas date_diff expects datetime object, $date_expire = '2014-08-06 00:00:00'; $date = new DateTime($date_expire); $now = new DateTime(); echo $date->diff($now)->format("%d days, %h hours and %i minuts"); DEMO. 来源：

How do I calculate % of task's completion given start date, end date, and TODAY()

由 丶灬走出姿态 提交于 2019-12-04 08:27:12
I have a gant with start date, end date, and % complete columns. By manually entering a number in the % column the bar representing the task gets shaded. What I want to do is instead of representing % completed, I want to show how much time is left before the end date from today. Start End % Time remaining from TODAY() i.e. 12/01/2014 03/15/2015 (End date has not yet occurred) 12/29/2014 12/29/2014 (Task was started and finished this day) Assuming your end date is in column B: =IF(TODAY()>=B2,"Done",CONCATENATE(B2-TODAY(),"")) This will show you the number of days remaining. If you want the

One hour difference, but only for some dates

由 江枫思渺然 提交于 2019-12-04 06:51:15
问题 Why between those dates I get 5,9.... and if I use another year I get 6 ???? It only happens with March and 2008... why is there an hour difference ??? <?php $from = '2008-03-04'; $to = '2008-03-10'; echo datediff($from,$to); $from = '2010-03-04'; $to = '2010-03-10'; echo datediff($from,$to); function datediff($from,$to) { $diff = strtotime($to) - strtotime($from); $diff = $diff/(60*60*24); return $diff; } ?> 回答1: Daylight Saving Time. 来源： https://stackoverflow.com/questions/2233666/one-hour

How to make a sql loop query to check difference between values?

由 拥有回忆 提交于 2019-12-04 06:14:02
问题 first of all, I'm not a native english speaker and this is a hard to explain issue. If you have any doubts, please let me know. We're using a GPS vehicle tracking device, which is programmed to send and store in a DB the position of the vehicle every 5 min when not moving, and every 100 meters when moving. This DB has a table called "vehicle_gps" that stores the data, with values such as speed, position, datetime, vehicle_gps_id. I need some kind of query that will show the different

PHP convert date interval diff to decimal

由 若如初见. 提交于 2019-12-04 04:06:13
问题 I'm trying to convert the difference between two dates into a total year count, right now I'm using this: $datetime1 = new DateTime('2009-10-11'); $datetime2 = new DateTime('2010-10-10'); $interval = $datetime1->diff($datetime2); return $interval->format('%y'); This returns me an int (Like 0 for < than a year, 2 for two years, etc.) I need the result to be decimal as following: 0.9 - 9 months 1.2 - 1 year and two months 3.5 - 3 years and five months and so on.. Thanks! 回答1: If you don't care
订阅 datediff