datediff

I am trying to express the difference of two given dates in days, hours, and minutes (like 1 day, 6 hours, 17 minutes.) as SQLite query output. I have entryin and entryout as datetime fields in a SQLitedatabase. I tried all combinations of julianday and strftime but still running into rough weather. I tried strftime('%d %H:%M', julianday(entryout)-julianday(entryin)) . For a row the values are 2011-11-10 11:46 , and 2011-11-09 09:00 . but the output is 25 14:46 instead of 01 02:46 . Can some one help me with this, or point me correct logic for this? Thanks in advance. You can try something

I'm attempting to fulfill a rather difficult reporting request from a client, and I need to find away to get the difference between two DateTime columns in minutes. I've attempted to use trunc and round with various formats and can't seem to come up with a combination that makes sense. Is there an elegant way to do this? If not, is there any way to do this? SELECT date1 - date2 FROM some_table returns a difference in days. Multiply by 24 to get a difference in hours and 24*60 to get minutes. So SELECT (date1 - date2) * 24 * 60 difference_in_minutes FROM some_table should be what you're looking

I need to calculate the difference between two timestamps in milliseconds. Unfortunately, the DateDiff-function of VBA does not offer this precision. Are there any workarounds? You could use the method described here as follows:- Create a new class module called StopWatch Put the following code in the StopWatch class module: Private mlngStart As Long Private Declare Function GetTickCount Lib "kernel32" () As Long Public Sub StartTimer() mlngStart = GetTickCount End Sub Public Function EndTimer() As Long EndTimer = (GetTickCount - mlngStart) End Function You use the code as follows: Dim sw as

Possible Duplicate: Best way to find the months between two dates (in python) I would like to know how I can have the exact number of months for this difference: date1 = datetime.strptime(str('2011-08-15 12:00:00'), '%Y-%m-%d %H:%M:%S') date2 = datetime.strptime(str('2012-02-15'), '%Y-%m-%d') date2-date1 results in datetime.timedelta(183, 43200) I would like to know the exact number of months, in this case it should return 5 and not 6 (because of the hour) Using calendar module to find out how many days each month has, you can simply count the months. from calendar import monthrange from

I need to use Oracle but DATEDIFF function doesn't work in Oracle DB. How to write the following code in Oracle? I saw some examples using INTERVAL or TRUNC. SELECT DATEDIFF ('2000-01-01','2000-01-02') AS DateDiff; In Oracle, you can simply subtract two dates and get the difference in days . Also note that unlike SQL Server or MySQL, in Oracle you cannot perform a select statement without a from clause. One way around this is to use the builtin dummy table, dual : SELECT TO_DATE('2000-01-02', 'YYYY-MM-DD') - TO_DATE('2000-01-01', 'YYYY-MM-DD') AS DateDiff FROM dual Just subtract the two dates:

I have a select query that has DURATION column to calculate number of Minutes . I want to convert those minutes to hh:mm format. Duration has values like 60, 120,150 For example: 60 becomes 01:00 hours 120 becomes 02:00 hours 150 becomes 02:30 hours Also, this is how I retrieve DURATION ( Minutes ) DATEDIFF(minute, FirstDate,LastDate) as 'Duration (Minutes)' You can convert the duration to a date and then format it: DECLARE @FirstDate datetime, @LastDate datetime SELECT @FirstDate = '2000-01-01 09:00:00', @LastDate = '2000-01-01 11:30:00' SELECT CONVERT(varchar(12), DATEADD(minute, DATEDIFF