date

问题 Let's say we have a table (table1) in which we store 4 values (user_id, name, start_date, end_date) table1 ------------------------------------------------ id user_id name start_date end_date ------------------------------------------------ 1 1 john 2016-04-02 2016-04-03 2 2 steve 2016-04-06 2016-04-06 3 3 sarah 2016-04-03 2016-04-03 4 1 john 2016-04-12 2016-04-15 I then enter a start_date of 2016-04-03 and end_date of 2016-04-03 to see if any of the users are available to be scheduled for a

问题 I have the following R matrix: Date MyVal 2016 1 2017 2 2018 3 .... 2026 10 What I want to do is "blow it up" so that it goes like this (where monthly values are linearly interpolated): Date MyVal 01/01/2016 1 02/01/2016 .. .... 01/01/2017 2 .... 01/01/2026 10 I realize I can easily generate the sequence using: DateVec <- seq(as.Date(paste(minYear,"/01/01", sep = "")), as.Date(paste(maxYear, "/01/01", sep = "")), by = "month") And I can use that to make a large matrix and then fill things in

问题 I understand that in Java, it is possible to use a ScheduledExecutorService to perform a specific task after a certain delay. This post shows how to execute the task at a specific date, but not with a SimpleDateFormat . For example, I have a format initialized like below: dateFormatter = new SimpleDateFormat("MM-dd-yyyy hh:mm aa"); Additionally, I want to execute a particular task declared under an else if statement in an ActionListener , such as below: foo.addActionListener(e -> { if

问题 I have a date column in my dataframe and want to add a column called location. The value of location in each row should depend on which date range it falls under. For example, the date 13th November falls between 12th November and 16th November & therefore the location should be Seattle. The date 17th November falls between 17th November and 18th November and must be New York. Below is an example of the data frame I want to achieve Dates | Location (column I want to add) .....................

问题 I have a date column in my dataframe and want to add a column called location. The value of location in each row should depend on which date range it falls under. For example, the date 13th November falls between 12th November and 16th November & therefore the location should be Seattle. The date 17th November falls between 17th November and 18th November and must be New York. Below is an example of the data frame I want to achieve Dates | Location (column I want to add) .....................

问题 I have the following data, with which I'm trying to make a pretty simple line plot with dots. For some reason, the first three points of 2015 get placed with a value above 1600 when their value is around 1300. dput(data) structure(list(y_value = c(1143L, 1133L, 1148L, 1155L, 1149L, 1144L, 1181L, 1164L, 1178L, 1173L, 1176L, 1209L, 1284L, 1286L, 1283L, 1288L, 1362L, 1396L, 1599L, 1583L, 1606L, 1645L, 1653L, 1662L), Date = c("2014-1", "2014-2", "2014-3", "2014-4", "2014-5", "2014-6", "2014-7",

问题 I need to parse a date string with timezone to Date object. The input date string pattern is: "MM/dd/yyyy hh:mm a z" (eg: 04/30/2018 06:00 PM IST). I have used below given code. But it returns incorrect date as output. new SimpleDateFormat("MM/dd/yyyy hh:mm a z").parse("04/30/2018 06:00 PM IST") Current Output: "Mon Apr 30 09:00:00 PDT 2018" . Expected Output: "Mon Apr 30 05:30:00 PDT 2018 . 回答1: That's because timezone's abbreviations such as IST are ambiguous. IST is used in India, Israel

问题 I need to parse a date string with timezone to Date object. The input date string pattern is: "MM/dd/yyyy hh:mm a z" (eg: 04/30/2018 06:00 PM IST). I have used below given code. But it returns incorrect date as output. new SimpleDateFormat("MM/dd/yyyy hh:mm a z").parse("04/30/2018 06:00 PM IST") Current Output: "Mon Apr 30 09:00:00 PDT 2018" . Expected Output: "Mon Apr 30 05:30:00 PDT 2018 . 回答1: That's because timezone's abbreviations such as IST are ambiguous. IST is used in India, Israel

问题 I need to parse a date string with timezone to Date object. The input date string pattern is: "MM/dd/yyyy hh:mm a z" (eg: 04/30/2018 06:00 PM IST). I have used below given code. But it returns incorrect date as output. new SimpleDateFormat("MM/dd/yyyy hh:mm a z").parse("04/30/2018 06:00 PM IST") Current Output: "Mon Apr 30 09:00:00 PDT 2018" . Expected Output: "Mon Apr 30 05:30:00 PDT 2018 . 回答1: That's because timezone's abbreviations such as IST are ambiguous. IST is used in India, Israel

问题 My current date: Date utc: 2018-06-06T16:30:00Z (ISO 8601 in UTC) OR Date iso: 2018-06-06T11:30:00-05:00 (ISO 8601) OR Date epoch: 1528302600000 (Epoch/Unix Timestamp) I wish to convert the above DateTime to some another time zone areas (like GMT+5:30). And I'm not sure which time format I'll receive from above three. So can I've a generic method which can convert above to some another time zone returning java.util.Date in Java 8? I did Something like this, But it didn't worked out public