date

问题 I need to filter Col A based on a PARTIAL STRING. The user needs to be able to filter for YEAR only ... or YEAR & MONTH ... or YEAR & MONTH & DAY YEAR ONLY : 20 YEAR & MONTH : 2002 YEAR & MONTH & DAY : 200206 The following will filter the year or the year & month .... it fails to filter for year / month / day. Thank you for looking. Sub FiltDate() Dim strName As String Dim range_to_filter As Range On Error Resume Next Set range_to_filter = Range("A2:A500000") 'Sheet4. Dim ret As String Dim

问题 I am using date-fns to format dates If I pass a date that ends in Z, it knows that it is UTC, and I can format(date, "yyyy-MM-dd") and it will be in local computer time. If the date I want to express in local computer time is originally CST, is there something to add at the end instead of the Z, that will be understood by the format function as a CST date? Sorry if this is a bad question Edit: is there a way to do zonedTimeToUtc(myDate, 'UTC-6') in date-fns? (instead of using a time zone name

问题 In my database, I have 3 columns: Date(PrimaryKey, TEXT) , FlightNumber(PrimaryKey, INTEGER) , and LoadEstimate(INTEGER) . What I would like to do is put all the values from database into a hashmap. I have to make sure that all the datatypes are correct in order to load them into it and would like to filter the LoadEstimate data by user input (a date and the flight number) and then return the predicted number for LoadEstimate and if none return -1 . Here is my database: 回答1: Text Combine your

问题 After isolating the problem in my current project .... I think something is not working currently with the Date object in javascript. But I don't want to be arrogant because maybe I am doing something wrong, is it a bug? or am I doning something wrong? I want to convert a date to diffrent time zone in javascript, I made this function: function ConvertToTimeZone(date, timezone) { let convertedTimeString = date.toLocaleString("en-US", {hour12: false, timeZone: timezone}) return new Date

问题 I have a sample data, i want to get the Difference in month over month data 'Lag' column for only row B 回答1: If there always is just one row per month and id , then just use lag() . You can wrap this in a case expression so it only applies to id 'B' . select id, date, data, case when id = 'B' then data - lag(data) over(partition by id order by date) end lag_diff from mytable 来源： https://stackoverflow.com/questions/62160736/running-difference-month-over-month

问题 I have this Entry data class @Entity(tableName = "entry") @Typeconverters(DateConverter::class) data class Entry( @PrimaryKey(autoGenerate = false) var id : String, var username : String, var type : String, var description : String, var category : String, var amount : Double, var date : String, var lastUpdate : String, var isDeleted : Boolean) } The date field contains a string that represents a date in the "yyyy-MM-dd" format, while the lastUpdate contains a string that represents a date in

问题 This question already has answers here : Deprecation warning in Moment.js - Not in a recognized ISO format (9 answers) Closed 1 year ago . I am getting date as input from an external source and it is a string, const a = '08-01-2019'; And required format for me is 'MM-DD-YYYY', const outputDateFormat = 'MM-DD-YYYY'; And I am using moment.js and doing below manipulations on that date like adding a year and decreasing a day, //adding a year const a = moment(a).add(1, 'years').add(-1, 'days')

问题 I have this Entry data class @Entity(tableName = "entry") @Typeconverters(DateConverter::class) data class Entry( @PrimaryKey(autoGenerate = false) var id : String, var username : String, var type : String, var description : String, var category : String, var amount : Double, var date : String, var lastUpdate : String, var isDeleted : Boolean) } The date field contains a string that represents a date in the "yyyy-MM-dd" format, while the lastUpdate contains a string that represents a date in

问题 For example, in the case of 03/27/2016 to 04/02/2016, the dates fall in different months. var curr = new Date; // get current date var first = curr.getDate() - curr.getDay(); var last = first + 6; // last day is the first day + 6 var firstday = new Date(curr.setDate(first)).toUTCString(); var lastday = new Date(curr.setDate(last)).toUTCString(); 回答1: The getDay method returns the number of the day in the week, with Sunday as 0 and Saturday as 6. So if your week starts on Sunday, just subtract

问题 Say I have a data.frame as follows, each month has one entry of data: df <- read.table(text="date,gmsl 2009-01-17,58.4 2009-02-17,59.1 2009-04-16,60.9 2009-06-16,62.3 2009-09-16,64.6 2009-12-16,68.3",sep=",",header=TRUE) ## > df ## date gmsl ## 1 2009-01-17 58.4 ## 2 2009-02-17 59.1 ## 3 2009-04-16 60.9 ## 4 2009-06-16 62.3 ## 5 2009-09-16 64.6 ## 6 2009-12-16 68.3 Just wondering how could I fill missing month with gmsl as NaN for date range from 2009-01 to 2009-12 ? I have extracted year and