date

问题 I'm running a query using Cypher in Neo4J where I have to compare a createdAt property of a node against a given time unit in Epoch milliseconds. This createdAt property is a string in the DateTime format, which is defined as - DateTime date with a precision of miliseconds, encoded as a string with the following format: yyyy-mm-ddTHH:MM:ss.sss+0000, where yyyy is a four-digit integer representing the year, the year, mm is a two-digit integer representing the month and dd is a two-digit

问题 I am parsing dates (got from server) in Java using this pattern: "yyyy-MM-dd'T'HH:mm:ss.SSS" . Incoming strings may be of these types: 2015-01-01T00:00:00.561 2015-01-01T00:00:00.5 My question is about milliseconds fraction. I am having trouble figuring out whether the .5 in the second string is 5 or 500 ms. Because when I parse it using my pattern I get 500 ms. Seems OK, but need to double check if there is any common contract to trim those zeros on server side. I would not ask if server

问题 I have the following dataset: import datetime import pandas as pd df = pd.DataFrame({'PORTFOLIO': ['A', 'A', 'A', 'A','A', 'A', 'A', 'A','A', 'A','A', 'A', 'A', 'A'], 'DATE': ['28-02-2018','31-03-2018','30-04-2018','31-05-2018','30-06-2018','31-07-2018','31-08-2018', '30-09-2018','31-10-2018','30-11-2018','31-12-2018','31-01-2019','28-02-2019','05-03-2019'], 'IRR': [.7, .8, .9, .4, .2, .3, .4, .9, .7, .8, .9, .4,.7, .8], }) df PORTFOLIO DATE IRR 0 A 2018-02-28 0.7 1 A 2018-03-31 0.8 2 A 2018

问题 Below is the data from an excel which I am trying to convert to JSON using pandas read_excel and to_json functions. The JSON date has the field "Date" as 1449446400000 (without quotes). I am wondering why the date is displayed as a big number instead of 12/7/2015 . ID Date Name Lat Long Pick Success Failure Drop Amount =========================================================================== 5 12/7/2015 PSG 11.0231335 77.0016396 31 21 10 44 5192 Please let me know how to convert it into a

问题 This question already has answers here : Add space after every 4th digit in input (2 answers) Angular 2 : add hyphen after every 4 digit in input , card number input (2 answers) Closed 2 years ago . How can i get automatic hyphens in input type date, while typing date? e.g. i want output something like this... If i want to type date 2018-06-18, while typing after 2018, "-" should be automatically shown and append to 2018 and binding on variable on .ts should be 2018-, same after 06, 2018-06-.

问题 This question already has answers here : Add space after every 4th digit in input (2 answers) Angular 2 : add hyphen after every 4 digit in input , card number input (2 answers) Closed 2 years ago . How can i get automatic hyphens in input type date, while typing date? e.g. i want output something like this... If i want to type date 2018-06-18, while typing after 2018, "-" should be automatically shown and append to 2018 and binding on variable on .ts should be 2018-, same after 06, 2018-06-.

问题 I have the following example data frame: Date_from <- c("2013-01-01","2013-01-10","2013-01-16","2013-01-19") Date_to <- c("2013-01-07","2013-01-12","2013-01-18","2013-01-25") y <- data.frame(Date_from,Date_to) y$concentration <- c("1.5","2.5","1.5","3.5") y$Date_from <- as.Date(y$Date_from) y$Date_to <- as.Date(y$Date_to) y$concentration <- as.numeric(y$concentration) These are measurend concentrations of heavy metals for a specific date range. However, the date ranges are not consecutive as

问题 I have a date converter function like: public static LocalDate getLocalDateFromString(String dateString) { DecimalStyle defaultDecimalStyle = DateTimeFormatter.ISO_LOCAL_DATE.getDecimalStyle(); DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ISO_LOCAL_DATE.withDecimalStyle(defaultDecimalStyle.withZeroDigit('\u0660')); LocalDate date = LocalDate.parse(dateString, dateTimeFormatter); return date; } It works fine for Arabic dates like ٢٠١٩-٠٤-١٥ , but when I pass a normal date like 2019

问题 I have a date converter function like: public static LocalDate getLocalDateFromString(String dateString) { DecimalStyle defaultDecimalStyle = DateTimeFormatter.ISO_LOCAL_DATE.getDecimalStyle(); DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ISO_LOCAL_DATE.withDecimalStyle(defaultDecimalStyle.withZeroDigit('\u0660')); LocalDate date = LocalDate.parse(dateString, dateTimeFormatter); return date; } It works fine for Arabic dates like ٢٠١٩-٠٤-١٥ , but when I pass a normal date like 2019

问题 I'm attempting to create a simple python function which will return the same value as javascript new Date().getTime() method. As written here, javascript getTime() method returns number of milliseconds from 1/1/1970 So I simply wrote this python function: def jsGetTime(dtime): diff = datetime.datetime(1970,1,1) return (dtime-diff).total_seconds()*1000 while the parameter dtime is a python datetime object. yet I get wrong result. what is the problem with my calculation? 回答1: One thing I feel