date

问题 Right now I have a working bit of code that formats to my specification when my time series begin at the start of a decade (i.e. 1990, 2000, 2010,etc.), but I don't know how to adapt my code to have the correct formatting when my time series begins at a year that isn't even (i.e. 1993). import pandas as pd import matplotlib.pyplot as plt from matplotlib import dates def format_xaxis(fig): years = dates.YearLocator(10,month=1,day=1) years1=dates.YearLocator(2,month=1,day=1) dfmt = dates

问题 This question already has answers here : Android: how to get the current day of the week (Monday, etc…) in the user's language? (11 answers) Closed 4 years ago . I need to get a day string with only a day of week integer (example : 1 = monday, 5 = friday...), I don't have any date. I know that I can define an array of string but I think there is a better solution by using a date format. Is it possible without having a date ? 回答1: You can use the DayOfWeek enum to get a day by its number:

问题 This question already has answers here : Android: how to get the current day of the week (Monday, etc…) in the user's language? (11 answers) Closed 4 years ago . I need to get a day string with only a day of week integer (example : 1 = monday, 5 = friday...), I don't have any date. I know that I can define an array of string but I think there is a better solution by using a date format. Is it possible without having a date ? 回答1: You can use the DayOfWeek enum to get a day by its number:

问题 I need to convert a date in yyyy-mm-dd like 2011-12-30 to UTC using only javascript. How? 回答1: var utc = new Date('2011-12-30').toUTCString(); jsFiddle. 回答2: If you're having problems getting the other listed solution to work in firefox or safari you can use: http://www.datejs.com/ myDate = new Date.parse("2011-12-30") myUTCDate = Date.UTC(myDate.getFullYear(), myDate.getMonth(), myDate.getDate(), myDate.getHours(), myDate.getMinutes(), myDate.getSeconds(), myDate.getMilliseconds()); Voila!!

问题 I need to convert a date in yyyy-mm-dd like 2011-12-30 to UTC using only javascript. How? 回答1: var utc = new Date('2011-12-30').toUTCString(); jsFiddle. 回答2: If you're having problems getting the other listed solution to work in firefox or safari you can use: http://www.datejs.com/ myDate = new Date.parse("2011-12-30") myUTCDate = Date.UTC(myDate.getFullYear(), myDate.getMonth(), myDate.getDate(), myDate.getHours(), myDate.getMinutes(), myDate.getSeconds(), myDate.getMilliseconds()); Voila!!

问题 I am looking to convert datetime to date for a pandas datetime series. I have listed the code below: df = pd.DataFrame() df = pandas.io.parsers.read_csv("TestData.csv", low_memory=False) df['PUDATE'] = pd.Series([pd.to_datetime(date) for date in df['DATE_TIME']]) df['PUDATE2'] = datetime.datetime.date(df['PUDATE']) #Does not work Can anyone guide me in right direction? 回答1: You can access the datetime methods of a Pandas series by using the .dt methods (in a aimilar way to how you would

问题 I am looking to convert datetime to date for a pandas datetime series. I have listed the code below: df = pd.DataFrame() df = pandas.io.parsers.read_csv("TestData.csv", low_memory=False) df['PUDATE'] = pd.Series([pd.to_datetime(date) for date in df['DATE_TIME']]) df['PUDATE2'] = datetime.datetime.date(df['PUDATE']) #Does not work Can anyone guide me in right direction? 回答1: You can access the datetime methods of a Pandas series by using the .dt methods (in a aimilar way to how you would

问题 I am looking to convert datetime to date for a pandas datetime series. I have listed the code below: df = pd.DataFrame() df = pandas.io.parsers.read_csv("TestData.csv", low_memory=False) df['PUDATE'] = pd.Series([pd.to_datetime(date) for date in df['DATE_TIME']]) df['PUDATE2'] = datetime.datetime.date(df['PUDATE']) #Does not work Can anyone guide me in right direction? 回答1: You can access the datetime methods of a Pandas series by using the .dt methods (in a aimilar way to how you would

问题 How can I print the date of the last Tuesday of each month for next year using Python. For example the first line outputted would be: 30/Jan/2018 I do not want to have the full name of the month only the first 3 characters! Currently I have figured out how to get the next year: import datetime now = datetime.datetime.now() next_year = now.year + 1 Can anyone please help? 回答1: The calendar module is perfect for this: You can use calendar.month_abbr which is an array of abbreviated months just

问题 I can receive files where date can be in one of the two formats: "mm/dd/yyyy" or "yyyy-mm-dd". They are factors to start with. Irrespective of the date format i receive it in, i want to be able to convert them to 'Date' data type of format "yyyy-mm-dd". I have tried using df_1$Date <- as.Date(as.character(df_1$Date), format = "%Y-%m-%d") This works with the format "yyyy-mm-dd" but gives NA when input values are of format "mm/dd/yyyy". Similarly, other methods i have tried works for only one