date-parsing

When parsing a YYYYMMdd date, e.g. 20120405 for 5th April 2012, what is the fastest method? int year = Integer.parseInt(dateString.substring(0, 4)); int month = Integer.parseInt(dateString.substring(4, 6)); int day = Integer.parseInt(dateString.substring(6)); vs. int date = Integer.parseInt(dateString) year = date / 10000; month = (date % 10000) / 100; day = date % 100; mod 10000 for month would be because mod 10000 results in MMdd and the result / 100 is MM In the first example we do 3 String operations and 3 "parse to int", in the second example we do many things via modulo. What is faster?

I am getting the following string from a server in my iOS app: 20140621-061250 How can I convert it to the local time? How can I define my date formatter? Is this correct? dateFormatter.dateFormat = @"YYYYMMd-HHmmss"; The question doesn't specify the nature of what you mean by converting, exactly, but the first thing you should do, regardless of the final goal, is to correctly parse the server response using a properly configured NSDateFormatter . This requires specification of the correct format string, and the time zone must be explicitly set on the formatter or it will infer it from the

I've been struggling for a while with this piece of code for an Android app and I can't get the hang of it. I've read and tried every solution I found on stackoverflow and other places, but still no luck. What I want to do is have a function to convert a string like "17.08.2012 05:35:19:7600000" to a UTC date and a function that takes an UTC date and converts it to a string like that. String value = "17.08.2012 05:35:19:7600000"; DateFormat df = new SimpleDateFormat("dd.MM.yyyy HH:mm:ss:SSSSSSS"); try { Date today = df.parse(value); System.out.println("Today = " + df.format(today) + " " +

i'm managing a date that comes from an Alfresco Properties and is in the specified (Tue Jul 13 00:00:00 CEST 2010) and i need to convert it to a Java date...i've looked around and found millions of posts for various string to date conversion form and also this page and so i tried something like this: private static final DateFormat alfrescoDateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy"); Date dataRispostaDate = alfrescoDateFormat.parse(dataRisposta); But it throws an exception.(The exception is (SSollevata un'eccezione durante la gestione della data: java.text.ParseException:

Consider a historic date string of format: Thu Jan 9 12:35:34 2014 I want to parse such a string into some kind of C++ date representation, then calculate the amount of time that has passed since then. From the resulting duration I need access to the numbers of seconds, minutes, hours and days. Can this be done with the new C++11 std::chrono namespace? If not, how should I go about this today? I'm using g++-4.8.1 though presumably an answer should just target the C++11 spec. Simple std::tm tm = {}; std::stringstream ss("Jan 9 2014 12:35:34"); ss >> std::get_time(&tm, "%b %d %Y %H:%M:%S"); auto