date-format

dd/mm/yyyy vs dd/MM/yyyy?

别说谁变了你拦得住时间么 提交于 2019-11-30 05:01:14
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy"); String date = sdf.format(new Date()); System.out.println(date); Result is todays date i.e 23/03/2014 But when i do SimpleDateFormat sdf = new SimpleDateFormat("dd/mm/yyyy"); result can be 23/05/2014, 23/05/2014, 23/06/2014 and son with each run of prgram. Why so? As we can see from the documentation , it's because mm is for minutes, not months. 1. d/D: day without 0 prefix on single digit. 2. dd/DD: day with 0 prefix if single digit. 3. M: Month without 0 prefix on single digit. 4. MM: Month with 0 prefix if single digit. 5. yy/YY:

Android format date to MM-DD-YYYY from Datepicker

梦想的初衷 提交于 2019-11-30 00:45:48
问题 I have a datepicker. My app is pushing a notification. I want to display the date in 01-07-2013 MM-dd-yyyy format. Please check my code below: //---Button view--- Button btnOpen = ( Button ) findViewById( R.id.btEventDone ); btnOpen.setOnClickListener( new View.OnClickListener() { public void onClick(View v) { String strT = title.getText().toString(); String strDes = description.getText().toString(); // check if user did not input anything if( strT.isEmpty() || strDes.isEmpty() ){ Toast

ASP.Net MVC model binding - how to change date format?

不羁岁月 提交于 2019-11-29 19:35:17
问题 I have this application, and the default date format must be dd/MM/yyyy (the language is Brazilian Portuguese). I already had set culture and UI culture to pt-BR and now myDate.ToShortDateString() returns the dates as I want. I have no trouble displaying them. The problem is, when the user fills an input field with a date such as 17/08/2011 and submits the form the DateTime parameter to my action becomes null. If I supply a date in the format 08/17/2011 , it works fine. How can I make the ASP

Error when converting date format to another

自古美人都是妖i 提交于 2019-11-29 18:04:08
I have a String in format " YYYY-MM-dd " and i want convert this into " MMM dd, yyyy " format. I used bellow code to do this; But when i convert " 2014 -11-18" the output is this "Sun Dec 29 00:00:00 IST 2013 " How can I solve this? DateFormat target=new SimpleDateFormat("MMM dd, yyyy"); String P_date="2014-11-18" Date test1 = new SimpleDateFormat("YYYY-MM-dd").parse(P_date); String converted_date=target.format(test1); Date test=target.parse(converted_date); The y (lowercase Y) format means "year". Y (uppercase Y) you were using means "WeekYear". Just use y and you should be OK: DateFormat

Wrong DateFormat with Jquery Datepicker

♀尐吖头ヾ 提交于 2019-11-29 17:29:27
I want to exclude the time part in the DateTime Textbox, but I can't make it work the way I want. This is how I set up the field : @Html.TextBoxFor(m => m.DateFrom, "{0:dd/MM/yyyy}", new { @class = "datefrom" }) @Html.TextBoxFor(m => m.DateTo, "{0:dd/MM/yyyy}", new { @class = "dateto" }) Jquery script: $(function () { $(".datefrom").datepicker({ defaultDate: "+1w", changeMonth: true, numberOfMonths: 1, dateFormat: "dd/mm/yy", onClose: function (selectedDate) { $("#to").datepicker("option", "minDate", selectedDate); } }); $(".dateto").datepicker({ defaultDate: "+1w", changeMonth: true,

Convert date field to Quarter in R

这一生的挚爱 提交于 2019-11-29 17:17:17
I have data frame which has the date column in format 08/21/2000(m/d/Y) . Now I want to add new column which display the date in Quarter format that is 2000-Q3 . I install zoo package and used following command. but it is giving NA value. library(zoo) mydf$var9=as.yearqtr("mydf$Order.Date","%m/%d/%Y"). The zoo library has created a set of functions to handle year-quarter vectors: library(zoo) mydf$var9=as.yearqtr(as.Date( mydf$Order.Date, "%m/%d/%Y" ). 来源: https://stackoverflow.com/questions/18349910/convert-date-field-to-quarter-in-r

Alignment date parts in JTable column formatted in propotional font

此生再无相见时 提交于 2019-11-29 16:42:48
I need to make the date parts (dd, MMMM, yyyy) to be vertically aligned. I asked a question at Fixed length of month and day in date format? to insert padding letters, but I found that it doesn't help in case of proportional font (the width of the letters are different). For example, with Lucida Fax font: Making different labels for different date parts is considering but it's too manual. It's hard to make the text wrapped if the column width is small.... Thanks note as for all Renderers (excluding preparedRenderer)you have to/be sure that you have to call that after any column/row changes in

how to insert current date into a DATE field in dd/mm/yyyy format in oracle

和自甴很熟 提交于 2019-11-29 15:54:29
I have a field in my table with datatype as DATE in Oracle. I want to insert the current date into that field, in format DD/MM/YYYY format. I tried the below query: select to_date(to_char(sysdate,'dd/mm/yyyy'),'dd/mm/yyyy') from dual But it gives 1/8/2011 12:00:00 AM. I want it to insert and show as 08/01/2011 12:00:00 AM. Can anyone help me in this please ? DATE is a built-in type in Oracle, which is represented in a fixed way and you have no control over it. So: I want it to insert [...] as 08/01/2011 12:00:00 AM The above is nonsensical. You don't insert a string, you insert a date. Format

Simple Oracle query: literal does not match format string

为君一笑 提交于 2019-11-29 15:47:59
I want to execute a simple function in Oracle. The signature is defined as follows: CREATE OR REPLACE FUNCTION NewCaseListForValidation ( p_fromDate in DATE, p_toDate in DATE, p_rowCount in INT ) RETURN SYS_REFCURSOR IS return_value SYS_REFCURSOR; ... I should be able to execute it with: var rc refcursor exec :rc := newcaselistforvalidation('2010-01-01','2011-01-01',100); print :rc But when typing "newcaselistforvalidation('2010-01-01','2011-01-01',100)", I get: ERROR at line 1: ORA-01861: literal does not match format string ORA-06512: at line 1 I googled a bit and it seems I can't figure out

SimpleDateFormat and parsing: parse doesn't fail with wrong input string date

允我心安 提交于 2019-11-29 15:43:50
I'm using java.util.Date date; SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy"); try { date = sdf.parse(inputString); } catch (ParseException e) { e.printStackTrace(); } where inputString is a string in the dd/MM/yyyy format. If the inputString is, for example, 40/02/2013, I would to obtain an error, instead the parse method returns the Date 12 March 2013 (12/03/2013). What I'm wronging? Adam Matan Set the Leniency bit : public void setLenient(boolean lenient) Specify whether or not date/time parsing is to be lenient. With lenient parsing, the parser may use heuristics to interpret