date-format

I'm doing something like this: SELECT date_format(mydate, '%d/%m/%Y') FROM xyz; When mydate is NULL, date_format returns 00/00/0000. This is correct, but how can I make it so that it returns NULL when the input is NULL? SELECT IF(mydate,date_format(mydate, '%d/%m/%Y'),NULL) FROM xyz; Source: http://dev.mysql.com/doc/refman/5.0/en/control-flow-functions.html You can wrap this into a IF -Clause, like this: SELECT IF(mydate,DATE_FORMAT(mydate, '%d/%m/%Y'),NULL) FROM xyz; That said, if your variable mydate is not a date value, the query in your post should return (NULL) anyway. select case when

In my table, dates are stored like this: 2011-03-03T13:30:00 I'm trying to output dates like this: March 3, 2011 1:30 PM I'd much rather work it into the query rather than use php to format it, but I'm having some difficulty doing that. Trying various iterations of DATE_FORMAT, but it's not giving me what I want, maybe because of the way it's being stored? You basically have two different operations you may need to perform when handling dates: date to string and vice versa. The functions you can use are DATE_FORMAT() and STR_TO_DATE() . Full reference can be found in the manual . Usage example

Have String str "May 23 2011 12:20:00", want to convert it to date such this: Date date = (new SimpleDateFormat("MMM dd yyyy HH:mm:ss")).parse(str); It always gives me ParseException Unparsable date format: 'May 23 2011 12:20:00'. Looked for similar issues, seems everything right. What is wrong? You may need to additionally specify the Locale , when the default Locale of your VM is not an English one: Date date = (new SimpleDateFormat("MMM dd yyyy HH:mm:ss", Locale.US)).parse(str); Works for me.! Try specifying locale while constructing SimpleDateFormat object. Basil Bourque tl;dr

I have dates in a table that are stored as decimal years . An example is 2003.024658 which translates to January 9, 2003 . I would like to convert the decimal years to Oracle's date format. I've found someone who's done this in Excel: Decimal year to date formula? =DATE(INT(B1),1,MOD(B1,1)*(DATE(INT(B1)+1,1,1)-DATE(INT(B1),1,1))) However, I can't quite figure out how to convert the logic to Oracle PL/SQL. If you start from the assumption that the decimal portion was calculated according to the number of days in the given year (i.e. 365 or 366 depending on whether it was a leap year), you could

I have an application I'm building with CodeIgniter. I have records in a SQL Server DB which have datetime fields. I'm querying these records from dates entered into a textfield in the m/d/Y. This corresponds to the date format in the db. Unfortunately I'm in the UK! So I want to enter dates in like d/m/Y. So I need to capture this, format it into the appropriate format and then validate it. Here's the code in using to format: $datestring = "%m/%d/%Y"; if(isset ($_POST['from_date']) AND isset ($_POST['to_date'])){ $from = mdate($datestring, strtotime($_POST['from_date'])); $to = mdate(

I had made one highchart in that tooltip is shows date and time in format but it is showing wrong date and time. Please go through the code below. HTML Code <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script> <script src="http://code.highcharts.com/highcharts.js"></script> <script src="http://code.highcharts.com/modules/exporting.js"></script> <div id="container" style="min-width: 310px; height: 400px; margin: 0 auto"></div> Javascript Code var maxval="94"; $(function () { var chart; $(document).ready(function() { chart = new Highcharts.Chart({ credits: {