date-format | 易学教程

How can process a date that is in d/m/yyyy?

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问题 I have to process dates . If the format i specify is mm/dd/yyyy and the date is like 7/5/2013, it is throwing a format exception. Does the date has to be like 07/05/2013? If yes how can i change the date from 7/5/2013 to 07/05/2013 programatically ? and the date format is not specific. I can have dates in mm-dd-yyyy or yyyy-mm-dd and the dates can come like 7-5-2013. 回答1: Use the ParseExact method, and specify the format as M/d/yyyy (or d/M/yyyy , depending on what exactly you need): var date

Change date format in responsebody

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问题 I have a spring application with a requestmapping that returns a list of Accounts in json. The Account class has a Date property. This property is returned as a unix timestamp in the json output. Is there a way to change the dateformat to a predefined format instead of returning it as a unix timestamp? @RequestMapping(value = "/userAccounts.json", method = RequestMethod.GET) public @ResponseBody ArrayList<Account> userAccounts() { ArrayList<Account> accounts = accountService

Custom Parser for Tablesorter plugin for custom date format

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问题 I need to adapt the jQuery Tablesorter plugin to sort dates in a very simple format which will consist of the three letter month and the 4 digit date (e.g. May 2010, Jan 2011, Mar 2012, etc). I have'nt been able to wrap my head around how to do it. I tried adapting the parser found here: http://beausmith.com/blog/custom-date-sorting-for-jquery-tablesorter-plugin/. But I am lost with reg ex. For ease in helping, I will post his code below. // TableSort parser for date format: Jan 6, 1978 $

Java Date sorting method?

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问题 I have an String array of dates in the format ex:'2010-05-04 11:26:46 +0530'. How can I check whether a particular date in the array is > today? thanks 回答1: DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z"); df.parse(datearray[i]).after(new Date()) 来源： https://stackoverflow.com/questions/2786379/java-date-sorting-method

Parse short US date into yyyy-MM-dd, java

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I want to parse the date "3/27/11" which I think is equal to US short date. DateFormat df1 = new SimpleDateFormat("MM/dd/yy"); DateFormat df2 = new SimpleDateFormat("yyyy-MM-dd"); Date date = (Date) df1.parseObject("03/27/11"); System.out.println("New date: " + df2.format(date)); I found the code above in several java tutorials but it doesn't seem to work. For some how I get, Exception in thread "main" java.lang.AssertionError: Default directory must be absolute/non-UNC Here is what I want to achieve, input: 3/27/11 (03/27/11 should also be a valid input) output: 2011-03-27 Thanks in advance!

Converting multiple columns in an R dataframe to Date Format

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问题 I have a large datafile where all the dates have been loaded as charaters. I would like to change all the Dates columns to date format. Most of the dates have "%y%m%d" format, some have "%Y%m%d" format. There are 25 columns of dates, so changing each one individually is inefficient. I can do df$DATE1 <- as.Date(df$DATE1, format ="%y%m%d") df$DATE2 <- as.Date(df$DATE2, format ="%y%m%d") etc., but very bad coding. I tried the following code, but is is not working. This assumes all of the dates

Oracle SQL convert date format from DD-Mon-YY to YYYYMM

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问题 I have a to compare dates in 2 tables but the problem is that one table has the date in DD-Mon-YY format and the other in YYYYMM format. I need to make both of them YYYYMM for the comparison. I need to create something like this: SELECT * FROM offers WHERE offer_date = (SELECT to_date(create_date, 'YYYYMM') FROM customers where id = '12345678') AND offer_rate > 0 where create_date is something like 12-Mar-2006 and offer_date is something like 200605 Any ideas where I need to adapt this query?

PHP date_format(): How to format date from string value

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问题 I have a bit of PHP code: $exd = date_create('01 Dec, 2015'); $exd = date_format($exd, 'Y-m-d'); echo $exd; Which is used for formatting the date. The expected output would be 2015-12-01 but it returns 2016-12-01 . What am i missing? 回答1: Use createFromFormat method first, provide the input format: $exd = DateTime::createFromFormat('d M, Y', '01 Dec, 2015'); // arguments (<format of the input>, <the input itself>) $exd = date_format($exd, 'Y-m-d'); // then choose whatever format you like echo

How to get the system date time format?

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I have a batch file that does some operations based on the date. It extracts the day, month and year and then creates a file with these variables. The trouble is the date format is different on different machines (dd/mm/yyyy, mm/dd/yyyy, ddd dd/mm/yyyy etc.). Is there a way to extract the date format first and then create the variables based on the extracted format in a batch file. This should work on any machine from XP Pro and later. @echo off for /f "delims=" %%a in ('wmic OS Get localdatetime ^| find "."') do set "dt=%%a" set "YYYY=%dt:~0,4%" set "MM=%dt:~4,2%" set "DD=%dt:~6,2%" set "HH=

Get exact day from date string in Javascript

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问题 I have checked this SO post: Where can I find documentation on formatting a date in JavaScript? Also I have looked into http://home.clara.net/shotover/datetest.htm My string is: Mon Jun 24 2013 05:30:00 GMT+0530 (India Standard Time) And I want to convert it to dd-mm-yyyy format. I tried using: var dateString = 'Mon Jun 24 2013 05:30:00 GMT+0530 (India Standard Time)'; var myDate = new Date(dateString); var final_date = myDate.getDay()+"-"+(myDate.getMonth()+1)+"-"+myDate.getFullYear(); But