dataframe

问题 I have a dataset of the following type (first row is the header): content is always text merge is always a logical id1 id2 start_line end_line content merge A B 1 1 "aaaa" TRUE A B 4 4 "aa mm" TRUE A B 5 5 "boool" TRUE A B 6 6 "omw" TRUE C D 6 6 "hear!" TRUE C D 7 7 " me out!" TRUE C D 21 21 "hello" FALSE Problem: I need to merge following a very specific criteria: Rows that have merge = FALSE must remain as is Rows that have: same id1 , same id2 and consecutive start_line : Need to be

问题 I have a data frame as below 0-10 10-20 20-30 30-40 M 1 2.5 4 0.3 N 0.5 0.8 2.3 1 The 0-10, 10-20 intervals is my first row without any column headings. I want to plot two line graphs on the same graph depicting M and N values on y-axis and the intervals 0-10, 10-20 etc. as my X-axis. How do I go about doing that? If I make the intervals as my heading, then I am unable to plot these graphs using ggplot as I do not have a x variable for aes() 回答1: A bit hard without the data, but I've created

问题 I have a dataframe where the first row is the initial condition. df = pd.DataFrame({"Year": np.arange(4), "Pop": [0.4] + [np.nan]* 3}) and a function f(x,r) = r*x*(1-x) , where r = 2 is a constant and 0 <= x <= 1 . I want to produce the following dataframe by applying the function to column Pop row-by-row iteratively. I.e., df.Pop[i] = f(df.Pop[i-1], r=2) df = pd.DataFrame({"Year": np.arange(4), "Pop": [0.4, 0.48, 4992, 0.49999872]}) Question: Is it possible to do this in a vectorized way? I

问题 How to extract some of the specific text only from PDF files using python and store the output data into particular columns of Excel. Here is the sample input PDF file (File.pdf) Link to the full PDF file File.pdf We need to extract the value of Invoice Number, Due Date and Total Due from the whole PDF file. Script i have used so far: from io import StringIO from pdfminer.converter import TextConverter from pdfminer.layout import LAParams from pdfminer.pdfdocument import PDFDocument from

问题 I have a dataframe where the first row is the initial condition. df = pd.DataFrame({"Year": np.arange(4), "Pop": [0.4] + [np.nan]* 3}) and a function f(x,r) = r*x*(1-x) , where r = 2 is a constant and 0 <= x <= 1 . I want to produce the following dataframe by applying the function to column Pop row-by-row iteratively. I.e., df.Pop[i] = f(df.Pop[i-1], r=2) df = pd.DataFrame({"Year": np.arange(4), "Pop": [0.4, 0.48, 4992, 0.49999872]}) Question: Is it possible to do this in a vectorized way? I

问题 There are many examples on how to create empty dataframe/Dataset using Spark Scala/Python. But I would like to know how to create an empty dataframe/Dataset in Java Spark. I have to create an empty dataframe with just one column with header as Column_1 and type String. 回答1: Alternative-1 Create empty dataframe with the user defined schema // alternative - 1 StructType s = new StructType() .add(new StructField("Column_1", DataTypes.StringType, true, Metadata.empty())); Dataset<Row> csv = spark

问题 Could you please help me? I want to make a list based on information contained in an R data frame. I found a solution, but it is not general. For instance, let's start with this data frame: df <- data.frame(vertices = paste(letters[1:20]), modules = rep(1:4, 5)) I want to use df$modules to turn the data frame into a list. The items of the list should contain data from df$vertices . So I found this solution: list1 <- split(df, df$modules) list2 <- vector(mode = "list", length = length(unique

问题 There are many examples on how to create empty dataframe/Dataset using Spark Scala/Python. But I would like to know how to create an empty dataframe/Dataset in Java Spark. I have to create an empty dataframe with just one column with header as Column_1 and type String. 回答1: Alternative-1 Create empty dataframe with the user defined schema // alternative - 1 StructType s = new StructType() .add(new StructField("Column_1", DataTypes.StringType, true, Metadata.empty())); Dataset<Row> csv = spark

问题 Could you please help me? I want to make a list based on information contained in an R data frame. I found a solution, but it is not general. For instance, let's start with this data frame: df <- data.frame(vertices = paste(letters[1:20]), modules = rep(1:4, 5)) I want to use df$modules to turn the data frame into a list. The items of the list should contain data from df$vertices . So I found this solution: list1 <- split(df, df$modules) list2 <- vector(mode = "list", length = length(unique

问题 Here is the data frame sports=data_frame(question=c("<h5>This gives you more information about pro Football What position would you prefer to play in pro Football?</h5>", "</h5>This gives you more information about pro Soccer What position would you prefer to play in pro Soccer?</h5>", "</h5>This gives you more information about pro Hockey What position would you prefer to play in pro Hockey?</h5>"), `Expected Money`= c(list(c('First Year = 10', 'First 3 Years= 50')), list(c('First Year = 15'