dataframe

问题 Dynamically create string from pandas column I have three data frame like below one is df and another one is anomalies:- d = {'10028': [0], '1058': [25], '20120': [29], '20121': [22],'20122': [0], '20123': [0], '5043': [0], '5046': [0]} df1 = pd.DataFrame(data=d) Basically anomalies in a mirror copy of df just in anomalies the value will be 0 or 1 which indicates anomalies where value is 1 and non-anomaly where value is 0 d = {'10028': [0], '1058': [1], '20120': [1], '20121': [0],'20122': [0]

问题 Note: I am a complete beginner. I am using a pandas dataframe to import a csv file that I converted from the following table. I need to load the csv file into a QTreeView and have been unable to do so. The output format should be: I will have to retrieve the "Scale Type" at some point, so I would like to somehow tag it to that item, but I'm not sure if that is possible. I have tried converting my data into a pandas dataframe and loading; loading the data directly with a csv; and converting it

问题 How to export summary of cox_proportional hazard model from R to csv. I ran a test by function coxph. by survival package Now i want to export its summary to csv, how to do that. c <- coxph(Surv(x~y)) summary(c) 回答1: From the ?coxph examples, I'll use: library(survival) test1 <- list(time=c(4,3,1,1,2,2,3), status=c(1,1,1,0,1,1,0), x=c(0,2,1,1,1,0,0), sex=c(0,0,0,0,1,1,1)) mdl <- coxph(Surv(time, status) ~ x + strata(sex), test1) mdl_summ <- summary(mdl) mdl_summ # Call: # coxph(formula = Surv

问题 How to export summary of cox_proportional hazard model from R to csv. I ran a test by function coxph. by survival package Now i want to export its summary to csv, how to do that. c <- coxph(Surv(x~y)) summary(c) 回答1: From the ?coxph examples, I'll use: library(survival) test1 <- list(time=c(4,3,1,1,2,2,3), status=c(1,1,1,0,1,1,0), x=c(0,2,1,1,1,0,0), sex=c(0,0,0,0,1,1,1)) mdl <- coxph(Surv(time, status) ~ x + strata(sex), test1) mdl_summ <- summary(mdl) mdl_summ # Call: # coxph(formula = Surv

问题 How to export summary of cox_proportional hazard model from R to csv. I ran a test by function coxph. by survival package Now i want to export its summary to csv, how to do that. c <- coxph(Surv(x~y)) summary(c) 回答1: From the ?coxph examples, I'll use: library(survival) test1 <- list(time=c(4,3,1,1,2,2,3), status=c(1,1,1,0,1,1,0), x=c(0,2,1,1,1,0,0), sex=c(0,0,0,0,1,1,1)) mdl <- coxph(Surv(time, status) ~ x + strata(sex), test1) mdl_summ <- summary(mdl) mdl_summ # Call: # coxph(formula = Surv

问题 I'm trying to calculate the percentage of each crime of the following Dataframe: Violent Murder Larceny_Theft Vehicle_Theft Year 1960 288460 3095700 1855400 328200 1961 289390 3198600 1913000 336000 1962 301510 3450700 2089600 366800 1963 316970 3792500 2297800 408300 1964 364220 4200400 2514400 472800 So I should calculate first the total of crimes per year and then use that to calculate the percentage of each crime. I was trying the following: > perc = (crime *100) / crime.sum(axis=1) Any

问题 I'm trying to calculate the percentage of each crime of the following Dataframe: Violent Murder Larceny_Theft Vehicle_Theft Year 1960 288460 3095700 1855400 328200 1961 289390 3198600 1913000 336000 1962 301510 3450700 2089600 366800 1963 316970 3792500 2297800 408300 1964 364220 4200400 2514400 472800 So I should calculate first the total of crimes per year and then use that to calculate the percentage of each crime. I was trying the following: > perc = (crime *100) / crime.sum(axis=1) Any

问题 I've been struggling to convert two columns in a pandas. The frame contains many columns, and 2 columns with dates: 'datelog'(is a date) and 'Timeofday' (is a time). The column datelog is a string. The column Timeofday is a datetime.time() format. The dateframe display is as folows: datelog Timeofday 0 30-APR-15 14:15:43 1 30-APR-15 14:16:13 2 30-APR-15 14:16:43 3 30-APR-15 14:17:13 4 30-APR-15 14:17:43 5 30-APR-15 14:18:13 6 30-APR-15 14:18:43 7 30-APR-15 14:19:13 8 30-APR-15 14:19:43 9 30

问题 I've been struggling to convert two columns in a pandas. The frame contains many columns, and 2 columns with dates: 'datelog'(is a date) and 'Timeofday' (is a time). The column datelog is a string. The column Timeofday is a datetime.time() format. The dateframe display is as folows: datelog Timeofday 0 30-APR-15 14:15:43 1 30-APR-15 14:16:13 2 30-APR-15 14:16:43 3 30-APR-15 14:17:13 4 30-APR-15 14:17:43 5 30-APR-15 14:18:13 6 30-APR-15 14:18:43 7 30-APR-15 14:19:13 8 30-APR-15 14:19:43 9 30

问题 I think this is very easy but I have no idea how to do it (or how to search it). Okay so I got 378 observations for a lot of countries. It goes like this ISO3C Date Country Vaccines Tests Confirmed Recovered Death Hospitalized Ventilation ICU 1 AFG 2020-01-01 Afghanistan 0 0 0 0 0 0 0 0 2 AFG 2020-01-02 Afghanistan 0 0 0 0 0 0 0 0 3 AFG 2020-01-03 Afghanistan 0 0 0 0 0 0 0 0 4 AFG 2020-01-04 Afghanistan 0 0 0 0 0 0 0 0 5 AFG 2020-01-05 Afghanistan 0 0 0 0 0 0 0 0 So How do I set a counter