curve

问题 Ok pretty self explanatory. I\'m using google maps and I\'m trying to find out if a lat,long point is within a circle of radius say x (x is chosen by the user). Bounding box will not work for this. I have already tried using the following code: distlatLng = new google.maps.LatLng(dist.latlng[0],dist.latlng[1]); var latLngBounds = circle.getBounds(); if(latLngBounds.contains(distlatLng)){ dropPins(distlatLng,dist.f_addr); } This still results in markers being places outside the circle. I\'m

问题 Phone model:bb curve 8520 Phone version:4.6.1.314 Carrier :airtel india APN :airtelgprs.com No username and password I am using the following code: String url=\"http://<address>:<port>/path;deviceside=true\"; HttpConnection conn =(HttpConnection)Connector.open(url,Connector.READ_WRITE,true); int response=conn.getResponseode(); if(responsecode==HttpConnection.HTTP_OK) { //...code for handling the response... } This code is throwing a \"tunnel failed \" exception. I am unable to understand the

问题 I\'d like to calculate a point on a quadratic curve. To use it with the canvas element of HTML5. When I use the quadraticCurveTo() function in JavaScript, I have a source point, a target point and a control point. How can I calculate a point on the created quadratic curve at let\'s say t=0.5 with \"only\" knowing this three points? 回答1: Use the quadratic Bézier formula, found, for instance, on the Wikipedia page for Bézier Curves: In pseudo-code, that's t = 0.5; // given example value x = (1

问题 How can I find the point B(t) along a cubic Bezier curve that is closest to an arbitrary point P in the plane? 回答1: After lots of searching I found a paper that discusses a method for finding the closest point on a Bezier curve to a given point: Improved Algebraic Algorithm On Point Projection For Bezier Curves, by Xiao-Diao Chen, Yin Zhou, Zhenyu Shu, Hua Su, and Jean-Claude Paul. Furthermore, I found Wikipedia and MathWorld's descriptions of Sturm sequences useful in understanding the first