currency

Use keypad to enter in currency value in desired format

别来无恙 提交于 2019-12-02 02:17:10
I want to have a screen that starts off with "$0.00" (or other symbol based on locale) that I can enter values into and it will update one at a time. (type 1234, returns $0.01, $0.12, $1.23, $12.34). I know how to do this with the digits entered into a text field and with the click of a button change the formatting either in the text field or into a new label. What I want, though, is to do it without the extra button tap and use a label, not a textField. float moneyEarnedFloat = [revenueTextField.text floatValue]/100.0f; NSNumber *moneyEarned = [NSNumber numberWithFloat:moneyEarnedFloat];

money representation in R

故事扮演 提交于 2019-12-01 20:09:18
I would like to know how can I work with money with R. It means, do arithmetic, print well formatted numbers and etc. For example I have some values 1.222.333,37 1.223.444,88 I could translate it to numeric and round it, removing the cents, but there isn't a better pattern to work with? I did try the format method, something like: format(141103177058,digits=3,small.interval=3,decimal.mark='.',small.mark=',') but without success. any tip or ideas? Spencer Varadi The scales package has a function for this: dollar_format() install.packages("scales") library(scales) muchoBucks <- 15558.5985121

Python ROUND_HALF_UP not working as expected

一个人想着一个人 提交于 2019-12-01 19:46:30
I can't seem to understand the decimal docs to get 2.775 to round to 2.78 using the decimal class. import decimal decimal.getcontext().prec = 7 print(decimal.Decimal(2.775).quantize( decimal.Decimal('0.00'), rounding=decimal.ROUND_HALF_UP )) >> 2.77 # I'm expecting 2.78 That SHOULD round to 2.78, but I keep getting 2.77. EDIT: Testing on python 3.4 If you add a single line to your code thus: print (decimal.Decimal(2.775)) then you'll see why it's rounding down: 2.774999999999999911182158029987476766109466552734375 The value 2.775 , as a literal is stored as a double, which has limited

How do I add the new currency code to Java?

房东的猫 提交于 2019-12-01 18:33:41
The Chinese currency has the ISO 4217 code CNY. Since free global trading in that currency is restricted though, there's a second 'offshore' currency equivalent, called CNH. Wikipedia has a bit of summary of this all. CNH isn't in ISO 4217, but I'd like to be able to use it in my app without having to write my own Currency class. Presumably there's some kind of list somewhere inside the JVM install. How do I go about adding additional currency codes? EDIT: See this question for dealing with this in Java 7 Looks like support for this was added with Java 7 . For earlier versions, you could use

How do I add the new currency code to Java?

两盒软妹~` 提交于 2019-12-01 18:03:55
问题 The Chinese currency has the ISO 4217 code CNY. Since free global trading in that currency is restricted though, there's a second 'offshore' currency equivalent, called CNH. Wikipedia has a bit of summary of this all. CNH isn't in ISO 4217, but I'd like to be able to use it in my app without having to write my own Currency class. Presumably there's some kind of list somewhere inside the JVM install. How do I go about adding additional currency codes? EDIT: See this question for dealing with

Setting a DBGrid column format in Delphi

时间秒杀一切 提交于 2019-12-01 17:39:27
I am using a DBGrid component in Delphi. I wonder how I can set the format of a column. I have real values that I want to be displayed as currency in the grid. Someone knows how? Germán Estévez -Neftalí- You can set the DisplayFormat of the Field You can handle OnGetText event. This approach allows to do more complex operations with the value. If you don't add the fields to field Editor list you can get the formating by code as : TFloatField(MyQuery.fieldByName('MyField').DisplayFormat := '0.00'; if you don't want to show the zeros replace '0.00' with '#.##'; The first port of call is the

Setting a DBGrid column format in Delphi

最后都变了- 提交于 2019-12-01 17:29:19
问题 I am using a DBGrid component in Delphi. I wonder how I can set the format of a column. I have real values that I want to be displayed as currency in the grid. Someone knows how? 回答1: You can set the DisplayFormat of the Field You can handle OnGetText event. This approach allows to do more complex operations with the value. 回答2: If you don't add the fields to field Editor list you can get the formating by code as : TFloatField(MyQuery.fieldByName('MyField').DisplayFormat := '0.00'; if you don

How to override Symfony form MoneyType input as type=“number”?

∥☆過路亽.° 提交于 2019-12-01 17:03:00
The Symfony MoneyType Field renders as input type="text" which allows a user to type whatever they want into the field. How can I override this to render as input type="number" so that users can only enter numeric characters? $formBuilder->add("amount", MoneyType::class, [ 'currency' => 'USD' ]); Current output: <div><label for="form_amount" class="required">Amount</label>$ <input type="text" id="form_amount" name="form[amount]" required="required" /></div> What I am trying to achieve: <div><label for="form_amount" class="required">Amount</label>$ <input type="number" id="form_amount" name=

Unformat money when parsing in PHP

我的梦境 提交于 2019-12-01 15:34:41
Is there a way to get the float value of a string like this: 75,25 € , other than parsefloat(str_replace(',', '.', $var)) ? I want this to be dependent on the current site language, and sometimes the comma could be replaced by dot. Gordon You can use NumberFormatter::parseCurrency - Parse a currency number Example from Manual: $formatter = new NumberFormatter('de_DE', NumberFormatter::CURRENCY); var_dump($formatter->parseCurrency("75,25 €", $curr)); gives: float(75.25) Note that the intl extension is not enabled by default. Please refer to the Installation Instructions . mcuadros This is a bit

Convert basic script to Objective C (money formatting)

不打扰是莪最后的温柔 提交于 2019-12-01 13:41:09
I've got this basic like script that I need to convert to objective c, it turns big units of money into shortened versions (ie: 1.2m, etc), I've got most of the conversion done, but the biggest problem I'm having is right at the end. The original basic code is: ; Basic Code Function ShortCash$(BigNumber) out$="" ; First, grab the length of the number L=Len(BigNumber) Letter$="" ;Next, Do a sweep of the values, and cut them down. If l<13 out$=(BigNumber/1000000000) ; For each figure, out remainder should be divided so that it leaves a 2 digit decimal number.. remainder=(BigNumber Mod 1000000000