crud

Can a READ TABLE statement be created dynamically with an arbitrary number of key field specifications?

扶醉桌前 提交于 2019-12-11 02:57:38
问题 I have the name of a table DATA lv_tablename TYPE tabname VALUE 'xxxxx' , and a generic FIELD-SYMBOLS: <lt_table> TYPE ANY TABLE. which contains entries selected from that corresponding table. I've defined my line structure FIELD-SYMBOLS: <ls_line> TYPE ANY. which i'd use for reading from the table. Is there a way to create a READ statement on <lt_table> fully specifying the key fields? I am aware of the statement / addition READ TABLE xxxx WITH KEY (lv_field_name) = 'asdf'. , but this

symfony2 propel crud generator

核能气质少年 提交于 2019-12-11 01:57:49
问题 Hi not sure why I cannot find an answer for this already im sure im not the first person that wants to do this. Ive just started using symfony again after 4 years and Im trying to use symfony2 with propel. I have used propel for many yours and get on well with it so would like to continue using it. In symfony 1.x there used to be crud generators I see there still is in symfony2 but only for doctrine. Is there any support and/or plugin available for easy crud generation for propel in symfony2

I need a very simple PHP database front-end admin panel; a simple records editor for a specified table [closed]

≡放荡痞女 提交于 2019-12-11 00:39:54
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I am looking to add some dynamics to our corporate website. This is a secondary role so I'd rather not be spending a ton of time on it. At this point, all I need is a simple PHP script where a non-technical user can pull up and manage the records in a MySQL table. There's only one table of data to be managed; it

CRUD operations template in java

旧时模样 提交于 2019-12-10 23:42:57
问题 I'm designing a system where I must perform several CRUD operations among the System entities. Just for make sure I searched in forums to see how it's resolved by someone else. I found 4 "patterns" . All of them agree in the READ operations so I skip them. I'll define the patterns: Pattern 1 void add(E entity); void update(E entity); // Read operations... void delete(E entity); Pattern 2 E create(<ListOfEntityProperties>); void update(E entity); // Read operations... void delete(E entity);

spring hibernate did not get the value of parameter

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-10 22:32:48
问题 I try to make an API call with the post method via postman to my spring boot application. Here is the input: { "username": "name", "password": "1234", "age": 12, "salary": 5000, "role": 1 } Here is the code in the controller: @RequestMapping(value = "/signup", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON_VALUE) public ResponseEntity<?> saveUser(@RequestBody UserDto user) { try { System.out.println(user.getUsername()); // => name System.out.println(user.getPassword()); //

Difference between $http.get and method:'GET'

五迷三道 提交于 2019-12-10 19:21:41
问题 I'm using Spring Data REST and have a MySQL DB to manage my data. With AngularJS I programmed my first page and want to get data from my DB. To get my data I know about two different ways: $http.get('http://myURL') and $http({ method:'GET' url:'http://myURL' } But where's the difference between them? Thanks for help! 回答1: There is no difference, $http.get('http://myURL') is just a shortcut for $http({method:'GET, url:'http://myURL'} 回答2: First way of getting the response is the short form of

How to create a nested GridView to edit EF Code First relation?

大兔子大兔子 提交于 2019-12-10 17:25:10
问题 I've got a classic Parent-Child relation that I would like to CRUD by using asp:GridView controls. To CRUD the parent is easy, but the challenge is to nest a asp:GridView within a asp:GridView that is able to work on the child relation. To make the problem easier, I've constructed an example. Consider the following EF-code: public class Context : DbContext { public DbSet<Animal> Animals { get; set; } public DbSet<Tag> Tags { get; set; } } public class Animal { public int AnimalID { get; set;

How to get a DateTime input in a Play! CRUD form?

夙愿已清 提交于 2019-12-10 17:19:40
问题 By default a java.util.Date field is represented in a CRUD form as a simple "DATE" input. public class DatedModel extends Model { public Date creationDate; in the CRUD admin I see: creationDate [TEXTINPUT] yyyy-MM-dd format. Is there any way to have a DateTime input instead, on selected fields only (not all of them modifying the application.conf date.format )? Is there a way to affect which "widget" is used for a given field in the 'automated' CRUD admin? 回答1: Something like this in your

How to pass complex queries in REST?

徘徊边缘 提交于 2019-12-10 13:07:25
问题 If I understand correctly, in rest style, every query (that is, every action on every resource that does not modifies the resource's state) should be encoded in the query string, using a get method, with no body at all. Am I right? Well, I have several applications that communicate with the db thru an XML message that is handled by a Visual Basic 6 component. the message for a query is something like this <xml> <service>account</service> <resource>invoice</resource> <action>query</action>

Hibernate - Boilerplate code for transactions

纵饮孤独 提交于 2019-12-10 12:19:36
问题 I have written this service class for database CRUD operations. visible public class CompanyServiceImpl extends PersistentRemoteService implements CompanyService { private GileadHibernateUtil gileadHibernateUtil; public CompanyServiceImpl() { gileadHibernateUtil = new GileadHibernateUtil(); setBeanManager(gileadHibernateUtil.getPersistentBeanManager()); } @Override public void addCompany(Company newCompany) { Objects.requireNonNull(newCompany, "newCompany is null."); Session session =