crontab

I'm trying to get familiar with cron jobs, and I think I get the basic idea (scheduling, syntax, etc), But, I can't seem to get it right on my mac with Terminal - where exactly do I find the Crontab? How should I reference the paths to scripts? What I'm trying to do is hit a php script on a remote machine ( http://.. .) - Is that possible at all? To get started with launchd (instead of cron) you'll want to first create an empty .plist file, for example local.mytask.plist and put it somewhere. ~/Library/LaunchAgents is probably a good place. Open that in text editor and copy in the code below <

Lynx浏览器安装。安装命令：sudo apt-get install lynx。 打开终端输入：crontab -e 若初次执行会出现以下(选择编译器，一般选4(Vim)) Select an editor. To change later, run ‘select-editor’. 1. /bin/ed 2. /bin/nano <—- easiest 3. /usr/bin/vim.tiny 选择一个Ubuntu编辑器后，编辑/tmp/crontab.AuN7IQ/crontab 文件： 进入编辑界面后，输入定时执行的脚本文件如下： # m h dom mon dow command 在下面添加定时执行命令： */3 * * * * lynx -dump http://xxxxx.xx/cron.php //代表每三分钟执行http://xxxxx.xx/cron.php的脚本文件一次 最后重启cron：service cron restart ———————————————————————— 原文链接：https://blog.csdn.net/u013288190/article/details/82194620 资料:https://blog.csdn.net/fanrenxiang/article/details/80361582 总结：每次执行crontab -e在

I have an expect script which I need to run every 3 mins on my management node to collect tx/rx values for each port attached to DCX Brocade SAN Switch using the command #portperfshow# Each time I try to use crontab to execute the script every 3 mins, the script does not work! My expect script starts with #!/usr/bin/expect -f and I am calling the script using the following syntax under cron: 3 * * * * /usr/bin/expect -f /root/portsperfDCX1/collect-all.exp sanswitchhostname However, when I execute the script (not under cron) it works as expected: root# ./collect-all.exp sanswitchhostname works

I have a crontab that looks like: SHELL=/bin/bash PATH=/sbin:/bin:/usr/sbin:/usr/bin MAILTO=root HOME=/ 0-59 * * * * /var/www/html/private/fivemin/zdaemon.php >> /dev/null & Simple as possible, right? zdaemon.php which I am just testing with is: #!/usr/bin/php <? while(true){ sleep(1); } ?> Whenever it runs it hangs like: root 15532 0.0 0.1 57228 1076 ? Ss 19:09 0:00 crond root 16681 0.0 0.1 72196 1428 ? S 21:46 0:00 crond root 16682 0.0 0.0 0 0 ? Zs 21:46 0:00 [bash] <defunct> root 16683 0.0 0.5 54800 5740 ? S 21:46 0:00 /usr/bin/php /var/www/html/private/fivemin/zdaemon.php root 16687 0.0 0

使用crontab你可以在指定的时间执行一个shell脚本或者一系列Linux命令。例如系统管理员安排一个备份任务使其每天都运行 如何往 cron 中添加一个作业? # crontab –e 0 5 * * * /root/bin/backup.sh 这将会在每天早上5点运行 /root/bin/backup.sh Cron 各项的描述 以下是 crontab 文件的格式： {minute} {hour} {day-of-month} {month} {day-of-week} {full-path-to-shell-script} o minute: 区间为 0 – 59 o hour: 区间为0 – 23 o day-of-month: 区间为0 – 31 o month: 区间为1 – 12. 1 是1月. 12是12月. o Day-of-week: 区间为0 – 7. 周日可以是0或7. Crontab 示例 1. 在 12:01 a.m 运行，即每天凌晨过一分钟。这是一个恰当的进行备份的时间，因为此时系统负载不大。 1 0 * * * /root/bin/backup.sh 2. 每个工作日(Mon – Fri) 11:59 p.m 都进行备份作业。 59 11 * * 1,2,3,4,5 /root/bin/backup.sh 下面例子与上面的例子效果一样： 59

I am trying to figure out the possibilities I have to solve the following problem. a) I want to have a database table that uses "crontab syntax" to schedule tasks, the structure would be something like this: |-Id-|---Crontab Syntax---|---------Task----------| | 1 | 30 * * * * * | MyClass.TaskA(args[]) | | 2 | 0 1 * * 1-5 * | MyClass.TaskB(args[]) | | | | | The above table will be modified at any time by an external application. Tasks added or removed should instantly affect the scheduler. b) The scheduler itself should reside on a Java application server. It should constantly be synched with

Hi i want to take database backup at daily mid night using cron job... and the name of database backup should append with current date... the format of backup file should be mydata_yyyy_mm_dd.sql ... backup file should be placed in /root directory something like 0 0 * * * /path/to/mysqldump ... > /path/to/backup/mydata_$( date +"%Y_%m_%d" ).sql should work. Please read man date man 5 crontab Create a cron.sh file with this content: mysqldump -u root -p{PASSWORD} DBNAME 2>> "/filename_`date '+%Y-%m-%d'`.sql" And give the Read permission or full access permission for that cron.sh file. and add

I need a cron statement to run for few hours eg 1-8 then 10-15. In this case will the following statement work, 0 1-8,10-15 * * * If not can anyone help me? Thanks in advance, Gnik You cannot, you can use either multiple values OR a range 0 1,2,3,4,5,6,7,8,10,11,12,13,14,15 * * * Source : Time tags are separated by spaces. Do not use spaces within a tag, this will confuse cron. All five tags must be present. They are a logical AND of each other. There is another space between the last time tag and the first command. A time tag can be a wildcard "*", which means "all". It can be one value,

I have the following entry in crontab: 0 5 * * * /bin/bash -l -c 'export RAILS_ENV=my_env; cd /my_folder; ./script/my_script.rb 2>&1 > ./log/my_log.log' The result of this is that I am receiving the output of ./script/my_script.rb in ./log/my_log.log . This behavior is desired. What is curious is that I am also receiving the output in my local mail. I am wondering how the output of my script is being captured by mail. Since I am redirecting the output to a log file, I would expect that my cron job would have no output, and thus I would receive no mail when the cron job runs. Can anyone shed