create-table

问题 below code is my databasehandler class i got it from a tutorial. Beside that tutorial i saw this method in so many forums. However, even if i have create table it doesnt seems to be created. What is my wrong can so help me pls. public class DatabaseHandler extends SQLiteOpenHelper implements DatabaseHandlerInterface { // All Static variables // Database Version private static final int DATABASE_VERSION = 1; // Database Name private static final String DATABASE_NAME = "AACDroidDB"; // Contacts

问题 I have following table T1 : ID | time 10 | 1000 10 | 1002 10 | 1003 11 | 1002 11 | 1004 Now I want to create a table T2 from T1 in which for each ID, successive time-intervals are shown i.e. ID | time1 | time 2 10 | 1000 | 1002 10 | 1002 | 1003 10 | 1003 | NULL 11 | 1002 | 1004 11 | 1004 | NULL so time2 entry is basically the entry of time1 in next row. How can I do it in MySql ? 回答1: Have a try with this one: SELECT ID, `time` AS time1, (SELECT MIN(st.`time`) FROM T1 st WHERE st.ID = T1.ID

问题 Im writing sql query and i have issue which i cannot fix. I'm trying this: CREATE TABLE a AS WITH cteCandidates (Miejscowosc, Ulica, NrDomu, KodPocztowy) AS ( SELECT Miejscowosc, Ulica, NrDomu, KodPocztowy FROM Gimnazja INTERSECT SELECT Miejscowosc, Ulica, NrDomu, KodPocztowy FROM SzkolyPodstawowe ) Select e.Lp as 'Gimnazja', s.Lp as 'Szkoly Podstawowe' FROM Gimnazja AS e INNER JOIN cteCandidates AS c ON e.Miejscowosc = c.Miejscowosc AND e.Ulica = c.Ulica AND e.NrDomu = c.NrDomu AND e

问题 im new on mysql workbench, and i tried so many things to put my script working but i simply cant... Ive got these tables: CREATE TABLE Utilizador (email varchar(40) not null, nome varchar(50) not null, dataNascimento date, profissao varchar(50) not null, reputacao double(3,2) unsigned not null, constraint pk_Utilizador primary key(email)) This is the first table created! CREATE TABLE POI (email varchar(40) not null, designacaoPOI varchar(10) not null, coordenadaX int, coordenadaY int,

问题 If we don't mention any delimiter while creating a table, is there any default delimiter hive takes? create table logs (ts bigint, line string) partitioned by (dt String, country String); 回答1: The default delimiter '\001' if you havn't set when create a hivetable . you can change it to others delimiter . for example hive> CREATE TABLE IF NOT EXISTS student1 > (sno INT,sname STRING,age INT,sex STRING) > ROW FORMAT DELIMITED > FIELDS TERMINATED BY '\t' > STORED AS TEXTFILE; 来源： https:/

问题 I have a file with Json data which takes the below form: Ex: { "Name": "xxxx", "Address": [{ "Street": "aa", "City": "bbb" }, { "Street": "ccc", "City": "ddd", "Country": "eee" }] } The above Json is a valid Json. I want to create a hive table on top of data of above form using JsonSerde. 回答1: Create table with all possible fields defined. If field is not present in json, select will return NULL: CREATE EXTERNAL TABLE your_table ( Name string, Address array<struct<Street:string,City:string

问题 CREATE TABLE IF NOT EXISTS `demare`.`shop` ( `shop_id` INT NOT NULL AUTO_INCREMENT, `shop_image` VARCHAR(255) NOT NULL, `shop_price` FLOAT(6,2) NOT NULL, `cart_id` INT NOT NULL, PRIMARY KEY (`shop_id`), INDEX `cart_id_idx` (`cart_id` ASC), CONSTRAINT `cart_id` FOREIGN KEY (`cart_id`) REFERENCES `demare`.`shopping cart` (`cart_id`) ON DELETE CASCADE ON UPDATE NO ACTION) ENGINE = InnoDB; I have an error. My 'shop' table cannot be created as I have error: 121 Duplicate key on write or update. I

问题 Note: I do not have this problem when using Oracle SQL Developer:: - But it is not the Standard here. So i must find a way to do this in PL/SQL Developer When attempting to use PL/SQL developer (PL/SQL Developer - the program) to dynamically drop tables then create new ones using a create statement I consistently run into the error: PLS-00103: ENCOUNTERED THE SYMBOL "/" THE SYMBOL "/" WAS IGNORED PLSQL This is due to the "/" at the end of the dynamic sql. If I remove the "/" from the end I

问题 Here is my failing MySQL code: CREATE TABLE product ( id int NOT NULL AUTO_INCREMENT, 'item-name' VARCHAR(255) NOT NULL, 'item-description' TEXT, 'listing-id' VARCHAR(50), PRIMARY KEY (id) ) The error is: Error creating table: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'item-name' VARCHAR(255) NOT NULL, 'item-description' TEXT, 'listing-id'' at line 3 The documentation says to use quotes... What is

问题 I'm trying to create simple table with partitions. this is my command: CREATE TABLE measurement ( city_id int not null, logdate date not null, peaktemp int, unitsales int ) PARTITION BY RANGE (logdate); this is the error I got: SQL Error [42601]: ERROR: syntax error at or near "PARTITION" Unable to understand with is the problem.. I am using PostgreSQL 9.6.3 回答1: "Declarative table partitioning", that is partitioning as a first-class feature of the DBMS with its own syntax, was added in