crc

Is it possible to remove padding at the end from CRC checksum

与世无争的帅哥 提交于 2020-04-18 12:21:53
问题 For example, I calculated CRC checksum of a file of size 1024 KB and file includes 22 KB of padding of zeros at the end of the file. If given checksum of 1024 KB and size of the padding of zeros of given file Is it possible to calculate the checksum of the file without the passing. That is in above case getting the checksum of 1002 KB of the file. Assuming we don't have to recalculate the checksum again and reuse the checksum already calculated for the entire file with padding. 回答1: After a

13种加密与解密算法【四】

元气小坏坏 提交于 2020-04-04 20:30:39
【10、散列哈希之SHA1加密】 SHA1(英语:Secure Hash Algorithm 1,中文名:安全散列算法1)是一种密码散列函数,美国国家安全局设计,并由美国国家标准技术研究所(NIST)发布为联邦数据处理标准(FIPS)。 SHA-1可以生成一个被称为消息摘要的160位(20字节)散列值,散列值通常的呈现形式为40个十六进制数。 **【SHA-1和SHA-0】 SHA-1和SHA-0的算法只在压缩函数的消息转换部分差了一个比特的循环位移。 【散列之SHA1】 /** * SHA1 * @param inStr 需要摘要的内容 * @return */ public static String sha1Encode(String inStr) { MessageDigest sha = null; try { sha = MessageDigest.getInstance("SHA"); byte[] byteArray = inStr.getBytes("UTF-8"); byte[] md5Bytes = sha.digest(byteArray); StringBuffer hexValue = new StringBuffer(); for (int i = 0; i < md5Bytes.length; i++) { int val = ((int)

CRC-CCITT (0xFFFF) delphi实现

亡梦爱人 提交于 2020-04-04 18:08:07
由于要和java的服务沟通,最终确定要实现的是: width=16 poly=0x1021 init=0xffff refin=false refout=false xorout=0x0000 check=0x29b1 residue=0x0000 name="CRC-16/CCITT-FALSE" 网络找了很多,结果结果对不上 下载了工具,都不是想要的,最终找到校验在线网址: https://www.lammertbies.nl/comm/info/crc-calculation.html 实现代码: function CRC16_CCITT_0xFFFF(bytes: TBytes): Word; const polynomial = $1021; var crc: Word; I, J: Integer; b: Byte; bit, c15: Boolean; begin crc := $FFFF; // initial value for I := 0 to High(bytes) do begin b := bytes[I]; for J := 0 to 7 do begin bit := (((b shr (7-J)) and 1) = 1); c15 := (((crc shr 15) and 1) = 1); crc := crc shl 1; if (c15

How do I implement a CRC16 with a custom polynomial in Javascript?

时光总嘲笑我的痴心妄想 提交于 2020-02-16 06:37:23
问题 Background I need to implement a CRC16 with a custom polynomial in Javascript. Research After searching several NPM modules and this SO question ( as well as all the links the comments suggest ): Javascript CRC16 sample code or implementation https://github.com/donvercety/node-crc16 I am still not any closer to my goal. Problem My problem is that even though I have the code, I can't understand how to re-use a given CRC16 solution because I don't know where to find the polynomial definition in

How do I implement a CRC16 with a custom polynomial in Javascript?

被刻印的时光 ゝ 提交于 2020-02-16 06:35:13
问题 Background I need to implement a CRC16 with a custom polynomial in Javascript. Research After searching several NPM modules and this SO question ( as well as all the links the comments suggest ): Javascript CRC16 sample code or implementation https://github.com/donvercety/node-crc16 I am still not any closer to my goal. Problem My problem is that even though I have the code, I can't understand how to re-use a given CRC16 solution because I don't know where to find the polynomial definition in

Difference between CRC and hash method (MD5, SHA1)

倖福魔咒の 提交于 2020-02-14 06:19:08
问题 Both CRC and hash methods can be used to verify the integrity of the original data. Why do most systems uses hash method nowadays? 回答1: CRC was designed to prevent transmission errors, not malicious action. Therefore, it isn't collision resistant. In particular, the linear properties of CRC codes even allow an attacker to modify a message in such a way as to leave the check value unchanged 回答2: HASH methods (ONE WAY ENCRYPTION) are more complex (and powerful) than simple check codes (CRC).

循环校验码 CRC 原始报文为 “11001010101”,其生成多项式为:x^4^+x^3^+x+1.对其进行CRC编码后的结果为?

放肆的年华 提交于 2020-01-26 14:25:59
循环校验码 (CRC 是一种只能检错不能进行纠错的校验码) 他其实是利用了模2除法的计算方式 我用下面的例子简述一下使用方法。 原始报文为 “11001010101”,其生成多项式为:x 4 +x 3 +x+1.对其进行CRC编码后的结果为? 首先要先理解生成的多项式 x 4 +x 3 +x+1的含义,其中最高的次方代表二进制的位数,在本例中最高次方为4则生成的二进制数则有5位,x 4 代表最高位为1,其余以此类推将得到一串二进制码为 11011 所谓循环校验码的实现就是将原始报文除以这段二进制码,但是再除之前,需要对原始报文先进行补位,如何补位呢,这个也很好补,补上 生成的二进制数的位数-1个 0即可,所以报文将变成110010101010000(补上了4个0) 所以这个时候我们用 110010101010000 模二除以 11011 这里要切记,模二除法与普通的除法不同,模二的除法其实就是对数据进行异或处理。 什么是异或呢:异或运算是指: 参与运算的两个值,如果两个相应位相同,则结果为0,否则为1 所以进行异或运算得出结果为:0011 来源: CSDN 作者: nb_zsy 链接: https://blog.csdn.net/nb_zsy/article/details/104086327

CAN FD协议分析

≡放荡痞女 提交于 2020-01-19 03:57:20
在汽车领域,随着人们对数据传输带宽要求的增加,传统的CAN总线由于带宽的限制难以满足这种增加的需求。此外为了缩小CAN网络(max. 1MBit/s)与FlexRay(max.10MBit/s)网络的带宽差距,BOSCH公司推出了CAN FD 。 CAN FD(CAN with Flexible Data rate)继承了CAN总线的主要特性。CAN总线采用双线串行通讯协议,基于非破坏性仲裁技术,分布式实时控制,可靠的错误处理和检测机制使CAN总线有很高的安全性,但CAN总线带宽和数据场长度却受到制约。CAN FD总线弥补了CAN总线带宽和数据场长度的制约,CAN FD总线与CAN总线的区别主要在以下两个方面: ? 可变速率 CAN FD采用了两种位速率:从控制场中的BRS位到ACK场之前(含CRC分界符)为可变速率,其余部分为原CAN总线用的速率。两种速率各有一套位时间定义寄存器,它们除了采用不同的位时间单位TQ外,位时间各段的分配比例也可不同。 ? 新的数据场长度 CAN FD对数据场的长度作了很大的扩充,DLC最大支持64个字节,在DLC小于等于8时与原CAN总线是一样的,大于8时有一个非线性的增长,所以最大的数据场长度可达64字节。 CAN FD介绍 1.CAN FD 数据帧帧格式 CAN FD 数据帧在控制场新添加EDL位、BRS位、ESI位,采用了新的DLC编码方式

Is it possible to find the CRC32 of a prefix, given only the CRC32 of the whole data?

独自空忆成欢 提交于 2020-01-14 13:00:07
问题 I have to do a lookup in a table, and I have a string identifier and the CRC32 of the string. If there is a miss, I have to decrement the size and lookup for a prefix of the identifier. Therefore, I would need to calculate the checksum of the prefix and repeat the process for each prefix. My C code of this algorithm is something like this: find_prefix(char* string, uint16_t size, uint32_t crc, hash_table_t *hash_table){ do{ if(perform_lookup(string, size, crc, hash_table)==HIT){ return size;

How to calcuate IEEE 802.11 CRC-32 FCS?

纵然是瞬间 提交于 2020-01-14 12:32:16
问题 This is from IEEE Std 802.11-2012 Clause 8.2.4.8 FCS field: I cannot understand the last two paragraphs: What's the meaning by "the initial remainder of the division is preset to all ones", and why we need to do that? What's the meaning by "... the serial incoming bits of the calculation fields and FCS..." ? 回答1: Initializing the CRC to all ones avoids the problem of a string of zeros of any length giving a zero CRC. Read Ross Williams CRC tutorial. 来源: https://stackoverflow.com/questions