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Why I cannot cout string like this: string text ; text = WordList[i].substr(0,20) ; cout << "String is : " << text << endl ; When I do this, I get the following error: Error 2 error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::string' (or there is no acceptable conversion) c:\users\mollasadra\documents\visual studio 2008\projects\barnamec\barnamec\barnamec.cpp 67 barnamec** It is amazing, that even this is not working: string text ; text = "hello" ; cout << "String is : " << text << endl ; You need to include #include <string> #include <iostream> You

I want to do: int a = 255; cout << a; and have it show FF in the output, how would I do this? Use: #include <iostream> ... std::cout << std::hex << a; There are many other options to control the exact formatting of the output number , such as leading zeros and upper/lower case. Benoît std::hex is defined in <ios> which is included by <iostream> . But to use things like std::setprecision/std::setw/std::setfill /etc you have to include <iomanip> . To manipulate the stream to print in hexadecimal use the hex manipulator: cout << hex << a; By default the hexadecimal characters are output in

概述 本文利用了硬件行为描述、数据流描述、结构描述三种方法分别写了几个加法器 一位半加法器 即两个一位的二进制数相加，得到其正常相加的结果的最后一位。 仿真波形图 硬件行为描述 设计文件 12345678910111213141516171819202122 module bjqxw(a,b,sum,cout); input a,b; output sum,cout; reg sum,cout; always @(a or b) begin case({a,b}) 2'b00:begin sum=0;cout=0; end 2'b01:begin sum=1;cout=0; end 2'b10:begin sum=1;cout=0; end 2'b11:begin sum=0;cout=1; end endcase endendmodule 仿真结构图 仿真文件 12345678910 module bjqxwsimu; reg a,b; wire sum,cout; bjqxw sl(a,b,sum,cout); initial begin a=0;b=0; end always #10 {a,b}={a,b}+1;endmodule 结构描述 设计文件 123456 module add(a,b,sum,cout); input a,b; output sum,cout;

有人把类说成是占用固定大小内存块的别名，其定义时不占用空间 #include<iostream> #include<string> using namespace std; class mycoach { public: string name="陈培昌"; int age=22; private: string favorite = "和丁大锅在一起"; public: void introduce() { cout << "大家好，我是" + name << "爱好是:" + favorite << endl; } }; void main() { mycoach cpc; cout << "大家好，我是"+cpc.name<<endl; cpc.introduce(); getchar(); } 输出结果： 常见错误----为什么成员函数很重要 #include<iostream> #include<math.h> using namespace std; class mycircle { public: double radius; double mypie = 3.1415926; double s = radius*radius*mypie; }; int main() { mycircle circle; cout << "请输入半径:"; cin >> circle

Is there a way to align text when printing using std::cout ? I'm using tabs, but when the words are too big they won't be aligned anymore. Sales Report for September 15, 2010 Artist Title Price Genre Disc Sale Tax Cash Merle Blue 12.99 Country 4% 12.47 1.01 13.48 Richard Music 8.49 Classical 8% 7.81 0.66 8.47 Paula Shut 8.49 Classical 8% 7.81 0.72 8.49 The ISO C++ standard way to do it is to #include <iomanip> and use io manipulators like std::setw . However, that said, those io manipulators are a real pain to use even for text, and are just about unusable for formatting numbers (I assume you

After performing some tests I noticed that printf is much faster than cout . I know that it's implementation dependent, but on my Linux box printf is 8x faster. So my idea is to mix the two printing methods: I want to use cout for simple prints, and I plan to use printf for producing huge outputs (typically in a loop). I think it's safe to do as long as I don't forget to flush before switching to the other method: cout << "Hello" << endl; cout.flush(); for (int i=0; i<1000000; ++i) { printf("World!\n"); } fflush(stdout); cout << "last line" << endl; cout << flush; Is it OK like that? Update: