counter | 易学教程

How to count characters in a file and print them sorted alphanumerically

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(If you have a better title, do edit, I couldn't explain it properly! :) So this is my code: with open('cipher.txt') as f: f = f.read().replace(' ', '') new = [] let = [] for i in f: let.append(i) if i.count(i) > 1: i.count(i) == 1 else: new = sorted([i + ' ' + str(f.count(i)) for i in f]) for o in new: print(o) And this is cipher.txt : xli uymgo fvsar jsb I'm supposed to print out the letters used and how many times they are used, my code works, but I need it alphabetical, I tried putting them in a list list(a) and then sorting them, but i didn't quite get it, any ideas? Thanks in advance!

Reliability of atomic counters in DynamoDB

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问题 I was considering to use Amazon DynamoDB in my application, and I have a question regarding its atomic counters reliability. I'm building a distributed application that needs to concurrently , and consistently , increment/decrement a counter stored in a Dynamo's attribute. I was wondering how reliable the Dynamo's atomic counter is in an heavy concurrent environment, where the concurrency level is extremely high (let's say, for example, an average rate of 20k concurrent hits - to get the idea

Rename the less frequent categories by “OTHER” python

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In my dataframe I have some categorical columns with over 100 different categories. I want to rank the categories by the most frequent. I keep the first 9 most frequent categories and the less frequent categories rename them automatically by: OTHER Example: Here my df : print(df) Employee_number Jobrol 0 1 Sales Executive 1 2 Research Scientist 2 3 Laboratory Technician 3 4 Sales Executive 4 5 Research Scientist 5 6 Laboratory Technician 6 7 Sales Executive 7 8 Research Scientist 8 9 Laboratory Technician 9 10 Sales Executive 10 11 Research Scientist 11 12 Laboratory Technician 12 13 Sales

python查找数组中出现次数最多的元素

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方法1-np.argmax(np.bincount()) 看一个例子 array = [0,1,2,2,3,4,4,4,5,6] print(np.bincount(array)) print(np.argmax(np.bincount(array))) #[1 1 2 1 3 1 1] #4 这里用到了两个函数，np.argmax和np.bincount，第一个很常见，就是返回数组中最大值对应的下标，np.bincount可以通过上面的例子理解：首先找到数组最大值max，然后返回0～max的各个数字出现的次数，在上例中，0出现了1次，1出现了1次，2出现了2次...以此类推。为什么这两个函数合起来可以找到出现次数最多的元素呢？因为np.bincount返回的数组中的下标对应的就是原数组的元素值，如上例中np.argmax找到np.bincount返回的数组中的最大值3（原数组中4出现了3次），其对应的下标4正是原数组中的元素4，如此就可以找到数组中出现次数最多的元素。但是这种方法有一个缺陷，即bincount只能统计0~max出现的次数，所以这种方法仅适用于非负数组方法2-Counter().most_common(1)[0][0] 看一个例子 from collections import Counter array = [0,1,2,2,3,4,4,4,5,6]

Apache Cassandra delete from counter

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I'm developing a little web application for studying Apache Cassandra and Java EE 6. Cassandra version is 1.1.6. Have a problem driving me mad... I created a table with a counter (using cqlsh v. 3.0.0) CREATE TABLE test ( author varchar PRIMARY KEY, tot counter ) and put some values this way: update test set tot = tot +1 where author = 'myAuthor'; the column family is perfectly updated author | tot ----------+----- myAuthor | 1 BUT, if you try to delete this row and then update again (with the same key), then nothing happens! The table is no more updated and I can't figure why: it seems to me

PHP making a download counter without leaving the current page

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I tried to create a download counter with PHP. The script, I have created, works, but when I click the download link, the script sends me to a blank page. Is it possible to stay on the page while downloading and counting? Here's my code of my download.php file: <?php $Down=$_GET['Down']; ?> <html> <head> <meta http-equiv="refresh" content="0;url=<?php echo $Down; ?>"> </head> <body> <?php $fp = fopen("counter.txt", "r"); $count = fread($fp, 1024); fclose($fp); $count = $count + 1; $fp = fopen("counter.txt", "w"); fwrite($fp, $count); fclose($fp); ?> </body> </html> That's how the link in my

JS counter continuously updating

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How to implement a live and persistent number counter on a site So I was looking at this question (^) and I want to do the exact same thing except a little different. I need one of these that counts up 15.8 cents per second from the numb $138,276,343 Preferably I would like to have the commas like a normal dollar amount. Any way I could get this working? I'm stumped. Like the poster of the above question, I don't have much JS knowledge. This took me quite a long time to answer since I had to create my own format currency function. A live demo can be found here: http://jsfiddle.net/dm6LL/ The

RxJS - make counter with reset stateless?

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问题 Assuming I have the following markup: <button id="dec">-</button> <output id="out">0</output> <button id="inc">+</button> <button id="res">RESET</button> And the following Rx.js script: var total = 0 Rx.Observable.merge( // decrement Rx.Observable.fromEvent($('#dec'), 'click') .map(function() { return -1 }), // increment Rx.Observable.fromEvent($('#inc'), 'click') .map(function() { return +1 }), // reset Rx.Observable.fromEvent($('#res'), 'click') .map(function() { return -total }) ) // merge

HTML/Javascript Button Click Counter

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问题 I have done something similar to this before, and I know this is really close. I'm just trying to make it so that my button increments the javascript variable, and the function then displays the new value. <html> <head> <title>Space Clicker</title> </head> <body> <script type="text/javascript"> int clicks = 0; function click() { clicks += 1; document.getElementById("clicks").innerHTML = clicks; }; </script> <button type="button" onClick="click()">Click me</button> <p>Clicks: <a id="clicks">0<

A counter keeping track of multiple values inside an array

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问题 This seems sort of complex so I'll do my best to be as clear as possible.The particular function I'm looking for dynamically creates a money spent | money won chart for a game of gambling. I have a lottery of sorts that the user can bet on. There are 6 items the user can buy which each have 6 prizes: These can be put into objects or arrays. var prices = [5,10,28,50,56,280] . var possibleWins = [40,80,250,400,500,2500] I'm trying to create a chart that calculates how much money you would have