counter

Reliability of atomic counters in DynamoDB

╄→尐↘猪︶ㄣ 提交于 2019-11-30 10:53:48
I was considering to use Amazon DynamoDB in my application, and I have a question regarding its atomic counters reliability. I'm building a distributed application that needs to concurrently , and consistently , increment/decrement a counter stored in a Dynamo's attribute. I was wondering how reliable the Dynamo's atomic counter is in an heavy concurrent environment, where the concurrency level is extremely high (let's say, for example, an average rate of 20k concurrent hits - to get the idea, that would be almost 52 billions increments/decrements per month). The counter should be super

C# Thread safe fast(est) counter

≡放荡痞女 提交于 2019-11-30 10:32:16
问题 What is the way to obtain a thread safe counter in C# with best possible performance? This is as simple as it gets: public static long GetNextValue() { long result; lock (LOCK) { result = COUNTER++; } return result; } But are there faster alternatives? 回答1: This would be simpler: return Interlocked.Increment(ref COUNTER); MSDN Interlocked.Increment 回答2: As recommended by others, the Interlocked.Increment will have better performance than lock() . Just take a look at the IL and Assembly where

How to count characters in a file and print them sorted alphanumerically

末鹿安然 提交于 2019-11-30 09:49:14
问题 (If you have a better title, do edit, I couldn't explain it properly! :) So this is my code: with open('cipher.txt') as f: f = f.read().replace(' ', '') new = [] let = [] for i in f: let.append(i) if i.count(i) > 1: i.count(i) == 1 else: new = sorted([i + ' ' + str(f.count(i)) for i in f]) for o in new: print(o) And this is cipher.txt : xli uymgo fvsar jsb I'm supposed to print out the letters used and how many times they are used, my code works, but I need it alphabetical, I tried putting

javascript - time counter since start date and time

做~自己de王妃 提交于 2019-11-30 07:41:06
问题 I have a new business, where I just hired someone to work for me, I am trying to make it easy for her to track her time, so I created a clock in button, that creates a record in a database, I have it pop up a small window, that she can click to clockout when she is done working. I want it to show her on that popup window a counter that will show how long she has been working, so I want to create a javascript or jQuery that will start at a certain time and count from there. She is on the East

Is there a way to make collections.Counter (Python2.7) aware that its input list is sorted?

浪子不回头ぞ 提交于 2019-11-30 07:27:40
问题 The Problem I've been playing around with different ways (in Python 2.7) to extract a list of (word, frequency) tuples from a corpus, or list of strings, and comparing their efficiency. As far as I can tell, in the normal case with an unsorted list, the Counter method from the collections module is superior to anything I've come up with or found elsewhere, but it doesn't seem to take much advantage of the benefits of a pre-sorted list and I've come up with methods that beat it easily in this

RxJS - make counter with reset stateless?

前提是你 提交于 2019-11-30 07:02:49
Assuming I have the following markup: <button id="dec">-</button> <output id="out">0</output> <button id="inc">+</button> <button id="res">RESET</button> And the following Rx.js script: var total = 0 Rx.Observable.merge( // decrement Rx.Observable.fromEvent($('#dec'), 'click') .map(function() { return -1 }), // increment Rx.Observable.fromEvent($('#inc'), 'click') .map(function() { return +1 }), // reset Rx.Observable.fromEvent($('#res'), 'click') .map(function() { return -total }) ) // merge .forEach(function(delta) { total += delta $('#out').text(total) }) Everything works as expected.

How to get unique values with respective occurrence count from a list in Python?

我只是一个虾纸丫 提交于 2019-11-30 06:25:28
问题 I have a list which has repeating items and I want a list of the unique items with their frequency. For example, I have ['a', 'a', 'b', 'b', 'b'] , and I want [('a', 2), ('b', 3)] . Looking for a simple way to do this without looping twice. 回答1: If your items are grouped (i.e. similar items come together in a bunch), the most efficient method to use is itertools.groupby : >>> [(g[0], len(list(g[1]))) for g in itertools.groupby(['a', 'a', 'b', 'b', 'b'])] [('a', 2), ('b', 3)] 回答2: With Python

collections模块—— Counter详讲

ぃ、小莉子 提交于 2019-11-30 06:25:11
Counter目的是用来跟踪值出现的次数。它是一个无序的容器类型,以字典的键值对形式存储,其中元素作为key,其计数作为value。计数值可以是任意的Interger(包括0和负数)。Counter类和其他语言的bags或multisets很相似。 创建 下面的代码说明了Counter类创建的四种方法: Counter类的创建 来源: https://www.cnblogs.com/lz1996/p/11568051.html

Best way to count file downloads on a website

ε祈祈猫儿з 提交于 2019-11-30 05:59:26
问题 It's surprising how difficult it is to find a simple, concise answer to this question: I have a file, foo.zip, on my website What can I do to find out how many people have accessed this file? I could use Tomcat calls if necessary Update: If you suggest writing a script, can you point me to a decent one? 回答1: Or you could parse the log file if you don't need the data in realtime. grep foo.zip /path/to/access.log | grep 200 | wc -l In reply to comment: The log file also contains bytes

How to get count dict of items but maintain the order in which they appear?

試著忘記壹切 提交于 2019-11-30 05:49:29
问题 For example, I need to count how many times a word appears in a list, not sorted by frequency but with the order in which the words appear, i.e. insertion order. from collections import Counter words = ['oranges', 'apples', 'apples', 'bananas', 'kiwis', 'kiwis', 'apples'] c = Counter(words) print(c) So instead of: {'apples': 3, 'kiwis': 2, 'bananas': 1, 'oranges': 1} I'd rather get: {'oranges': 1, 'apples': 3, 'bananas': 1, 'kiwis': 2} And I don't really need this Counter method, any way that