coordinates

Get screen coordinates of DOM element

橙三吉。 提交于 2019-11-29 13:11:11
问题 Can I somehow get precise screen coordinates (relative to top left corner of the screen) of a DOM object. Through NPAPI\FireBreath or JavaScript. (Need this for plugin, that I'm writing with FireBreath) 回答1: you move cursor to somewhere of the page ,and make a click event.(find the window,then GetWindowRect ,caculate a sutable position) then you can catch the event,record clientX and clientY. By this ,you build a bridge between two different coordinate system. 回答2: P.S.: I know I made this

Drawing a Line - Maximum Point

白昼怎懂夜的黑 提交于 2019-11-29 13:06:01
I drew a line that is at an angle based on a slider. I am trying to make the line's end Y coordinate a certain number (let's say 300), even if it is at an angle. Any ideas on how to do this? Here is the work on my line so far: double angle = intAngle; angle = angle * Math.PI / 180; double length = 300; graphics.setColor(Color.RED); double startX = 300; double startY = 100; double endX = startX + length * Math.cos(angle); double endY = startY + length * Math.sin(angle); double end2X; double end2Y; double dblAngle; double angle2; int intAngle2; double start2X = endX; double start2Y = endY;

calculate the V from A = USVt in objective-C with SVD from LAPACK in xcode

泪湿孤枕 提交于 2019-11-29 12:57:12
My goal is to transfer a coordinate in perspective from a known rectangle (for example a 800 by 600 screen) to a quadrangle that is skewed/rotated. To do so i found this, which was extremely helpful: Transforming captured co-ordinates into screen co-ordinates I guess there are more solutions to the problem. 1 by making triangles out of your quadrangle and apply some mathematical function which i could not solve yet. OR using the H-matrix which comes out of the formula A=USVt. which seemed nice because once you have the correct H-matrix you can transfer any coordinate pretty easy as explained

Could someone give me an example of how to extract coordinates for a 'word' using PDFBox

放肆的年华 提交于 2019-11-29 12:54:54
Could someone give me an example of how to extract coordinates for a 'word' with PDFBox I am using this link to extract positions of individual characters: https://www.tutorialkart.com/pdfbox/how-to-extract-coordinates-or-position-of-characters-in-pdf/ I am using this link to extract words: https://www.tutorialkart.com/pdfbox/extract-words-from-pdf-document/ I am stuck getting coordinates for whole words. You can extract the coordinates of words by collecting all the TextPosition objects building a word and combining their bounding boxes. Implementing this along the lines of the two tutorials

how to get latitude/longitude from one geo address using Qt c++ on windows?

核能气质少年 提交于 2019-11-29 12:53:38
Its is possible get the coordinates(latitude and longitude), of a geo location using just the geo address (country, state, city, street, etc...), on Qt c++? I know the libraries QGeoCoordinates, QGeoLocation and QGeoAddress, but i don´t know if is possible get coordinates from an address through them. Every help is welcome. I needed some time to master this but finally I got it working. At first I tried the classes mentioned by you: QGeoAddress , QGeoLocation , QGeoCoordinate : // standard C++ header: #include <iostream> // Qt header: #include <QGeoAddress> #include <QGeoCoordinate> #include

C# Foreach XML Node

◇◆丶佛笑我妖孽 提交于 2019-11-29 12:38:41
问题 I'm saving 2-dimensional coordinates on an XML file with a structure similar to: <?xml version="1.0" encoding="utf-8" ?> <grid> <coordinate time="78"> <initial>540:672</initial> <final>540:672</final> </coordinate> </grid> I can open the XML file and read it via the XmlTextReader, but how do I loop through the coordinates specifically to retrieve both the time attribute and data between the initial and final nodes in some format similar to: string initial = "540:672"; string final = "540:672"

How to find the coordinate that is closest to the point of origin?

被刻印的时光 ゝ 提交于 2019-11-29 12:24:54
I know there are many many questions about sorting javascript arrays by multiple values, but none of the answers solved my problem. I have an array of coordinates like: x | y -------- 10 20 12 18 20 30 5 40 100 2 How can I get the coordinate that is closest to the point of origin? Calculate the distance of each point using Math.sqrt( Math.pow(x, 2) + Math.pow(y, 2) ); Take the result that's the lowest var points = [ {x: 10, y: 20}, {x: 12, y: 18}, {x: 20, y: 30}, {x: 5, y: 40}, {x: 100, y: 2} ]; function d(point) { return Math.pow(point.x, 2) + Math.pow(point.y, 2); } var closest = points

Creating 2D coordinates map in Python

百般思念 提交于 2019-11-29 12:22:30
问题 I'm not looking for solution, I'm looking for a better solution or just a different way to do this by using some other kind of list comprehension or something else. I need to generate a list of tuples of 2 integers to get map coordinates like [(1, 1), (1, 2), ..., (x, y)] So I have the following: width, height = 10, 5 Solution 1 coordinates = [(x, y) for x in xrange(width) for y in xrange(height)] Solution 2 coordinates = [] for x in xrange(width): for y in xrange(height): coordinates.append(

WPF how to show an Image.Source (BitmapSource) pixel position?

99封情书 提交于 2019-11-29 10:30:42
问题 Let's suppose I've got an image which shows its source in a scaled way, how could i use a MouseMove event to show in a label or textblock the pixel position in which the cursor is? (I need the pixel coordinates not the coordinates of the image relative to its size) Thanks in advance. 回答1: You can find out the actual pixel height and width from the ImageSource. ImageSource imageSource = image.Source; BitmapImage bitmapImage = (BitmapImage) imageSource ; Now since you got the image displayed in

Android sensor: getRotationMatrix() returns wrong values, why?

风流意气都作罢 提交于 2019-11-29 10:28:42
问题 It's past several days since I started using this function and have not yet succeeded in obtaining valid results. What i want is basically convert acceleration vector from device's coordinates system, to real world coordinates . I' know that is possible because i have acceleration in relative coordinates and i know the orientation of the device in real world system. Reading Android developers seems that using getRotationMatrix() i get R = rotation matrix. So if i want A (acceleration vector