coordinates

How to calculate angle between two Geographical/GPS coordinates?

帅比萌擦擦* 提交于 2019-11-30 08:36:22
问题 I have two GPS Coordinates e.g. (Lat1, Long1) and (Lat2,Long2) Could anybody please help me find the angle between those two points. Values should be 0-360 degrees. 回答1: Taken from this previous SO post: float dy = lat2 - lat1; float dx = cosf(M_PI/180*lat1)*(long2 - long1); float angle = atan2f(dy, dx); 回答2: I suppose you mean the bearing to and not the angle between the locations: If (lat1,long1) is stored in a Location object loc1 and (lat2,long2) is stored in loc2 you get the bearing from

WPF how to show an Image.Source (BitmapSource) pixel position?

梦想的初衷 提交于 2019-11-30 07:46:41
Let's suppose I've got an image which shows its source in a scaled way, how could i use a MouseMove event to show in a label or textblock the pixel position in which the cursor is? (I need the pixel coordinates not the coordinates of the image relative to its size) Thanks in advance. You can find out the actual pixel height and width from the ImageSource. ImageSource imageSource = image.Source; BitmapImage bitmapImage = (BitmapImage) imageSource ; Now since you got the image displayed in Image control. You can easily map the mouse position to the Pixel scale. pixelMousePositionX = e

Android sensor: getRotationMatrix() returns wrong values, why?

人走茶凉 提交于 2019-11-30 07:41:23
It's past several days since I started using this function and have not yet succeeded in obtaining valid results. What i want is basically convert acceleration vector from device's coordinates system, to real world coordinates . I' know that is possible because i have acceleration in relative coordinates and i know the orientation of the device in real world system. Reading Android developers seems that using getRotationMatrix() i get R = rotation matrix. So if i want A (acceleration vector in world system) from A' (acceleration vector in phone system) i must do simply: A=R*A' But i cant'n

How to map a point onto a warped grid

此生再无相见时 提交于 2019-11-30 07:27:18
问题 Say you have a collection of points with coordinates on a Cartesian coordinate system. You want to plot another point, and you know its coordinates in the same Cartesian coordinate system. However, the plot you're drawing on is distorted from the original. Imagine taking the original plane, printing it on a rubber sheet, and stretching it in some places and pinching it in others, in an asymmetrical way (no overlapping or anything complex). (source) You know the stretched and unstretched

pixel coordinates on diamond

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-30 07:03:54
I got an image with a couple of diamond put side by side like on the image below The only coordinates I know on the image are the top corners (green text). When I click on the image I get the coordinates of that point, but I'm not able to get which diamond I'm on. For example I click on the red dot, how do I know that x:260, y:179 = the top diamond ? And the blue belongs to the left ? etc... Thank you very much for your help. EDIT: I finally used Canvas, but I think SVG would have worked as well for what I needed to do. I see two possible approaches: direct check whether a point is inside a

OpenGL Coordinates from Bezier Curves

元气小坏坏 提交于 2019-11-30 06:39:28
问题 Basically, I need to get all the coordinates drawn from a Bezier curve implementation in OpenGL. Specifically, I need the coordinates to move a sphere object (baseball) in my scene along a curved trajectory path. This is what I use to draw my curve: GL2 gl = drawable.getGL().getGL2(); float ctrlpoints[][] = new float[][]{ {0.0f, 0.0f, 60f}, {0.0f, 3.0f, 45.0f}, {0.0f, 2.0f, 15.0f}, {0.0f, 1.0f, 0f}}; FloatBuffer ctrlpointBuf = FloatBuffer.allocate(ctrlpoints[0].length * ctrlpoints.length);

calculate and print the average value of strings in a column

我怕爱的太早我们不能终老 提交于 2019-11-30 06:00:56
问题 I got a .txt file with 2 columns of values. They are 2D coordinates, so the first column represent the x value and the second one is the z value. Unfortunately there are some lines with the same x value but a different z value. I'd like to calculate the average of the z values in order to associate a single z to a single x. A sample of what i have is: 435.212 108.894 435.212 108.897 435.212 108.9 435.212 108.903 As you can see the x value 435.212 is associated with 4 different z value. What i

WPF: Converting between screen coordinates and WPF coordinates

北战南征 提交于 2019-11-30 05:07:23
I understand that WPF coordinates are different from "real" screen coodinates (pixel coordinates) if the computer is not using the default DPI setting. In my program I want to (1) figure out which monitor a WPF window is on and (2) open another window in the bottom-left corner of the same monitor. I heard there is no equivalent of Screen for WPF so I use the WinForms version, as follows, which works fine at the default 96 DPI: public void ChooseInitialPosition(Window w) // w is some other window { var scr = System.Windows.Forms.Screen.FromRectangle( new System.Drawing.Rectangle((int)w.Left,

How to get cells (<td>) x and y coordinate in table using jQuery?

為{幸葍}努か 提交于 2019-11-30 04:01:49
I'm looking for a good way to get cells X-Y position in a table. (do not confuse it with css-position, I am looking for X and Y coordinate in Cartesian coordinate system). As we know, we can get particular cell in a table using ex: $('#grid')[0].rows[5].cells[7] . But, what if I want to get the value 5x7 when I click on particular cell, i.e: $('#grid td').click(function(){ alert("My position in table is: " + myPosition.X + "x" + myPosition.Y); }); I guess, the easiest way is to add innerHTML, ID or CSS class to every cell ( <td class="p-5x7"> etc.) when creating table in back end, then parse

Translating between cartesian and screen coordinates

萝らか妹 提交于 2019-11-30 03:41:45
For my game I need functions to translate between two coordinate systems. Well it's mainly math question but what I need is the C++ code to do it and a bit of explanation how to solve my issue. Screen coordiantes: a) top left corner is 0,0 b) no minus values c) right += x (the more is x value, the more on the right is point) d) bottom +=y Cartesian 2D coordinates: a) middle point is (0, 0) b) minus values do exist c) right += x d) bottom -= y (the less is y, the more at the bottom is point) I need an easy way to translate from one system to another and vice versa. To do that, (I think) I need