coordinate-transformation

Trying to rotate and transform SVG path - do I need trigonometry calculations?

六月ゝ 毕业季﹏ 提交于 2019-12-04 13:45:15
I'm trying to manipulate with mouse SVG path which represents symbol of electronics resistor. This symbol requires manipulation with end of the "leads" (if you can picture real resistor); therefore I am trying to achieve draging 1st point arround (2nd is still there) and to all points of path to behave proportionally in when drag the 1st point on new coordinates. Try to group, try with trigonometry functions...so code is like: `<g id="r" > <!-- R - group for symbol of electronics resistor --> <path d="M 200 20 v80 h30 v150 h-60 v-150 h30 m 0 150 v80 " fill="none" stroke="blue" stroke-width="5"

Stretching Issue with Custom View Matrix

ぃ、小莉子 提交于 2019-12-04 05:08:32
问题 I'm currently working on my own 2D Maths library for my project to improve my understanding of the underlying matrix math. In the past I've use libraries such as GLM but I felt like it might be worth looking into as a learning experience. Most of this has been straightforward and the majority of my Maths classes integrate and work well with OpenGL, however my view matrix appears to be stretching my quad at the edges of the window. Note this isn't an issue of perspective, not only am I using

Custom y-axis scale and secondary y-axis labels in ggplot2 3.1.0

a 夏天 提交于 2019-12-04 00:26:28
Edit 2 The current developmental version of the ggplot2-package does solve the bug mentioned in my question below. Install the dev version using devtools::install_github("tidyverse/ggplot2") Edit It seems as the faulty behaviour of sec_axis in ggplot2 3.1.0 is a bug. This has been recognized by the devs and they are working on a fix (see thread on GitHub). Goal I have a graphic where the y-axis ranges from 0 to 1. I'd like to add a secondary y-axis that ranges from 0 to 0.5 (so exactly half the values of the primary y-axis). So far no problem. What complicates the matter is that I have a

Mac OS X: Convert between NSView coordinates and global screen coordinates

半世苍凉 提交于 2019-12-03 22:55:50
I have the following situation in my multi-monitor setup: In this example I want to position a window exactly at the coordinates depicted with the yellow arrow. All I do have however, are the coordinates of an NSView that is a subview of the contentView of an NSWindow that spans the entire (bigger,upper) secondary monitor. Here's how the global coordinate space is defined: {0,0} is the coordinate of the upper left corner of my laptop screen. (green) {-296, -1080} is the coordinate of the upper left corner of my second screen (black) {0, 800} is the coordinate of the lower left corner (no arrow

Html5 Canvas Transformation Algorithm - Finding object coordinates after applying transformation

馋奶兔 提交于 2019-12-03 22:22:57
On html5 canvas I am drawing objects (rectangle, circle, etc...), these objects have transformation properties like scale, skew, rotation etc... These objects can be nested. Problem occurs when I after applying transformations, I want to find exact x, y coordinate of given object, but its going over my head. To all experts who is into interactive computer graphics; please help me solve this problem. Thanks in advance. All affine transformations in 2D can be expressed as a matrix of the form: [ a c dx ] T = [ b d dy ] [ 0 0 1 ] This could be expressed with the method context.transform(a, b, c,

Transform from relative to world space in Processing

匆匆过客 提交于 2019-12-03 22:07:23
What is a good way of transforming a local relative point, into the world (screen) space in Processing? For example, take the Flocking example that comes with the Processing PDE. How would I implement a relativeToWorld method and a worldToRelative method in the Boid class. These methods would take into consideration, all the transforms done in the render method. I was thinking I would want to transform PVector objects, so the method signatures might look something like: PVector relativeToWorld(PVector relative) { // Take a relative PVector and return a world PVector. } PVector worldToRelative

convert wgs 84 to lat/long

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-03 20:47:14
Hi I am having a little trouble figuring out how to convert between types of coordinates. I have a list of coordinate sets with the following description "Coordinates are always in the WGS84 system. All coordinates a represented as integer values x and y where the coordinate value is multiplied with 1,000,000." An example: 559262 6319512 Well, I need to convert these to long/lat (and back) so i can use these in google maps (android). But this is not as easy as it seams. I have been searching around and did find some code to do this, but it does not seam to work properly. Anyone who can provide

how to scale the element by keeping the fixed position in svg

我怕爱的太早我们不能终老 提交于 2019-12-03 13:56:13
问题 i want to scale the below element in fixed position. <path id="container_svg_rectsymbol1" fill="red" stroke-width="1" stroke="Gray" d="M 73.1111111111111 -71.75 L 83.1111111111111 -71.75 L 83.1111111111111 -61.75 L 73.1111111111111 -61.75 L 73.1111111111111 -71.75" transform="scale(1)"/> when am start scaling it moves from one location to another location. i don't want to move the object i just want to enlarge the size of object. i have referred following link. http://commons.oreilly.com/wiki

Python pyproj convert ecef to lla

心已入冬 提交于 2019-12-03 13:00:08
问题 I want to convert x/y/z-ECEF positions to lla (lat/lon/alt) using WGS84 in python with pyproj but it seems like the conversion fails. Example code is here: import pyproj # Example position data, should be somewhere in Germany x = 652954.1006 y = 4774619.7919 z = -2217647.7937 ecef = pyproj.Proj(proj='geocent', ellps='WGS84', datum='WGS84') lla = pyproj.Proj(proj='latlong', ellps='WGS84', datum='WGS84') lon, lat, alt = pyproj.transform(ecef, lla, x, y, z, radians=True) print lat, lon, alt Can

Determining a homogeneous affine transformation matrix from six points in 3D using Python

旧城冷巷雨未停 提交于 2019-12-03 08:18:18
I am given the locations of three points: p1 = [1.0, 1.0, 1.0] p2 = [1.0, 2.0, 1.0] p3 = [1.0, 1.0, 2.0] and their transformed counterparts: p1_prime = [2.414213562373094, 5.732050807568877, 0.7320508075688767] p2_prime = [2.7677669529663684, 6.665063509461097, 0.6650635094610956] p3_prime = [2.7677669529663675, 5.665063509461096, 1.6650635094610962] The affine transformation matrix is of the form trans_mat = np.array([[…, …, …, …], […, …, …, …], […, …, …, …], […, …, …, …]]) such that with import numpy as np def transform_pt(point, trans_mat): a = np.array([point[0], point[1], point[2], 1]) ap