coordinate-systems

I am working with a hexagonal grid. I have chosen to use this coordinate system because it is quite elegant. This question talks about generating the coordinates themselves, and is quite useful. My issue now is in converting these coordinates to and from actual pixel coordinates. I am looking for a simple way to find the center of a hexagon with coordinates x,y,z. Assume (0,0) in pixel coordinates is at (0,0,0) in hex coords, and that each hexagon has an edge of length s. It seems to me like x,y, and z should each move my coordinate a certain distance along an axis, but they are interrelated

I have a very simple SpriteKit scene that is not behaving like I would expect. It is a universal app and the code that I am using to draw a single red square in the scene is as follows: let redSquare = SKSpriteNode(color: UIColor .redColor(), size: CGSizeMake(100.0, 100.0)) redSquare.anchorPoint = CGPointMake(0.0, 0.0) redSquare.position = CGPointMake(1.0, 1.0) addChild(redSquare) This code is in the GameScene didMoveToView method of the default app that xCode creates for you when you select SpriteKit game. When run on the iPad it behaves as expected drawing the red square 1 point off the

I have a geometry with its vertices in cartesian coordinates. These cartesian coordinates are the ECEF(Earth centred earth fixed) coordinates. This geometry is actually present on an ellipsoidal model of the earth using wgs84 corrdinates.The cartesian coordinates were actually obtained by converting the set of latitudes and longitudes along which the geomtries lie but i no longer have access to them. What i have is an axis aligned bounding box with xmax, ymax, zmax and xmin,ymin,zmin obtained by parsing the cartesian coordinates (There is no obviously no cartesian point of the geometry at xmax

Hi guys I need to convert coordinates in the following form: N42-53.9° W072-16.2° INto something thats kinda like the following: -90.7311 0.346944 A php function would be greatly appreciated - or just a formula would also be nice enough :) I found an online JS calculator and a PHP solution : <?php function DMStoDEC($deg,$min,$sec) { // Converts DMS ( Degrees / minutes / seconds ) // to decimal format longitude / latitude return $deg+((($min*60)+($sec))/3600); } function DECtoDMS($dec) { // Converts decimal longitude / latitude to DMS // ( Degrees / minutes / seconds ) // This is the piece of

I'm plotting a bunch of UTM coordinates using a matplotlib.pyplot.scatter. I also have a background air photo that I know matches the extent of the figure exactly. When I plot my data and set the axis I can display the scatter correctly. If I plot the air photo using imshow it uses the pixel number as the axis location. I need to shift the image (numpy array) to it's correct UTM position. Any ideas? I'm fairly new to matplotlib and numpy. For example: I know that the top left corner of the image (imshow coordinate: 0,0) has the UTM coordinate (269658.4, 538318.2). How do I tell imshow the same