convert

Convert Object to JSON string

匿名 (未验证) 提交于 2019-12-03 07:50:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: jQuery.parseJSON('{"name":"John"}') converts string representation to object but I want the reverse. Object is to be converted to JSON string I got a link http://www.devcurry.com/2010/03/convert-javascript-object-to-json.html but it need to have json2.js do jQuery has a native method to do this? 回答1: jQuery does only make some regexp checking before calling the native browser method window.JSON.parse() . If that is not available, it uses eval() or more exactly new Function() to create a Javascript object. The opposite of JSON.parse() is JSON

python Convert Encoding:LookupError: unknown encoding: ansi

匿名 (未验证) 提交于 2019-12-03 07:50:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Because of my encode of cdv file is "utf-8",so when I open it with excel it will cause distortion,and when I convert it to then standard encode "ANSI",I get the error: code: import chardet def convertEncoding(from_encode,to_encode,old_filepath,target_file): f1=file(old_filepath) content2=[] while True: line=f1.readline() content2.append(line.decode(from_encode).encode(to_encode)) if len(line) ==0: break f1.close() f2=file(target_file,'w') f2.writelines(content2) f2.close() convertFile = open('4321.csv','r') data = convertFile.read() print

How do you convert a document in UML 1.3 - XMI 1.1 format to UML 2.1 XMI?

匿名 (未验证) 提交于 2019-12-03 07:47:04
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to convert a file exported from PowerDesigner in the UML 1.3 - XMI 1.1 format to the UML 2.1 XMI Interchange Model from Rational Software Architect. How can I do this? 回答1: It can be worth to give a try to the XMI file converter its web based using Php. 回答2: If RSA won't import XMI 1.1 then you'll need to find another tool that will. Enterprise Architect by Sparx Systems can import XMI 1.1 and can write XMI 2.1. You can get a free 30 day trial from their website at http://www.sparxsystems.com . Be warned though that there are

Convert GB2312 to UTF-8

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a text file that contains localized language strings that is currently encoded in GB2312 (simplified Chinese), but all of my other language files are in UTF-8. I am finding it very difficult to work with this file, as none of my text editors will work properly with it and keep corrupting it. Are there any tools to convert this to UTF-8, and are there any downsides to doing this? Would it be better to just keep it as GB2312 and use a different editor (if so, can you recommend one)? Update: I'm using Windows XP (English install). Update

How to convert Salesforce rich text editor to a “full mode” editor?

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: With the spring '12 coming over these days, the old "hack" to convert the rich editor will not work any more. What can be done to retain full CKEditor functionality after spring 12? 回答1: New CKEditor is object rather than URL based and a new approach is needed. In case anyone needs it, the following script will replace factory editor layout with a full version allowing additional formating options (fonts, colors, etc). Note, I set the height to 600px, adjust for your own needs. Also, as before, this can only work in your own VF pages, you

How to convert a stream into a generator without leaking resolve from a promise

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a stream and I need to convert it to a generator, so an uploader can consume the generic generator. This means turning: stream.on('data', chunk => ...); to: generator = streamGenerator(stream); chunk = await generator.next() ... better yet: chunk = yield streamGenerator; Overall my best attempt requires leaking the resolve from a promise and I'd like to avoid that: function streamToIterable(chunkSize, stream) { let collector = []; let value = []; let done = false; let _resolve; let promise = new Promise(resolve => _resolve = resolve);

How to convert a CIDR prefix to a dotted-quad netmask in Python?

匿名 (未验证) 提交于 2019-12-03 07:36:14
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: How can I convert a CIDR prefix to a dotted-quad netmask in Python? For example, if the prefix is 12 I need to return 255.240.0.0 . 回答1: You can do it like this: def cidr(prefix): return socket.inet_ntoa(struct.pack(">I", (0xffffffff << (32 - prefix)) & 0xffffffff)) 回答2: Here is a solution on the lighter side (no module dependencies): netmask = '.'.join([str((0xffffffff << (32 - len) >> i) & 0xff) for i in [24, 16, 8, 0]]) 文章来源: How to convert a CIDR prefix to a dotted-quad netmask in Python?

How to convert jenkins job configuration config.xml to YAML format in python to be used jenkins-job-builder?

匿名 (未验证) 提交于 2019-12-03 03:10:03
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: jenkins-job-builder is a nice tool to help me to maintain jobs in YAML files. see example in configuration chapter. Now I had lots of old jenkins jobs, it will be nice to have a python script xml2yaml to convert the existing jenkins job config.xml to YAML file format. Do you any suggestions to had a quick solution in python ? I don't need it to be used in jenkins-job-builder directly, just can be converted it into YAML for reference. For the convert, some part can be ignored like namespace. config.xml segment looks like: <project>

Convert two types into a single type with Serde

匿名 (未验证) 提交于 2019-12-03 03:10:03
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm writing for a program that hooks into a web service which sends back JSON. When a certain property isn't there it provides a empty object, with all its fields as empty strings instead of excluding the value. When the property exists, some of the properties are u64 . How can I have it so Serde handles this case? Rust Structs #[derive(Clone, Debug, Deserialize)] struct WebResponse { foo : Vec < Foo >, } #[derive(Clone, Debug, Deserialize)] struct Foo { points : Points , } #[derive(Clone, Debug, Deserialize)] struct Points { x :

Convert an org.apache.spark.mllib.linalg.Vector RDD to a DataFrame in Spark using Scala

匿名 (未验证) 提交于 2019-12-03 03:10:03
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a org.apache.spark.mllib.linalg.Vector RDD that [Int Int Int] . I am trying to convert this into a dataframe using this code import sqlContext.implicits._ import org.apache.spark.sql.types.StructType import org.apache.spark.sql.types.StructField import org.apache.spark.sql.types.DataTypes import org.apache.spark.sql.types.ArrayData vectrdd belongs to the type org.apache.spark.mllib.linalg.Vector val vectarr = vectrdd.toArray() case class RFM(Recency: Integer, Frequency: Integer, Monetary: Integer) val df = vectarr.map { case Array(p0,