convert

How to convert an HttpServletRequest to String?

匿名 (未验证) 提交于 2019-12-03 08:44:33
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: How can I convert an HttpServletRequest to String ? I need to unmarshall the HttpServletRequest but when I try to, my program throws an exception. javax.xml.bind.UnmarshalException - with linked exception: [java.io.IOException: Stream closed] at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:197) at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:168) at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl

C# Could not Cast or Convert System.String to Class object

匿名 (未验证) 提交于 2019-12-03 08:44:33
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to deserialize a JSON string received from a Web API try { string r = await App.client.GetUser(); App.Authentication = JsonConvert.DeserializeObject<ApiResult>(r); await DisplayAlert("TEST", App.Authentication.ToString(), "OK"); Application.Current.MainPage = new Schedule(); } catch (Exception p) { await DisplayAlert("Getting Authentication failed", p.ToString(), "TEST"); } However it gives the error: Could not Cast or Convert System.String to App1.ApiResult App.Authentication = JsonConvert.DeserializeObject<ApiResult>(r); App

How do I convert a “Keys” enum value to an “int” character in C#?

匿名 (未验证) 提交于 2019-12-03 08:44:33
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This seems like something that should be easy, but I am having a tough time figuring out what needs to happen here. In the "KeyDown" eventhandler, if the "e.KeyValue" is a number, I want to treat it as a number and store it as an int. So, if I hit "8" on the number pad, I don't want "Numpad8" I want the int value 8 that I can add or subtract or whatever. So, how do I convert from the KeyValue to an int? 回答1: I'd go with this solution: int value = -1; if (e.KeyValue >= ((int) Keys.NumPad0) && e.KeyValue <= ((int) Keys.NumPad9)) { // numpad

TypeError: Image data can not convert to float

匿名 (未验证) 提交于 2019-12-03 08:42:37
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to create an 16 bit image. So i have written a code. import skimage import random from random import randint xrow=raw_input("Enter the number of rows to be present in image.=>") row=int(xrow) ycolumn=raw_input("Enter the number of columns to be present in image.=>") column=int(ycolumn) A={} for x in xrange(1,row): for y in xrange(1,column): a=randint(0,65535) A[x,y]=a imshow(A) But whenever i run this code, i get an error displaying "TypeError: Image data can not convert to float".Is there any solution for this. I apologies for the

How to convert generator or iterator to list recursively

匿名 (未验证) 提交于 2019-12-03 08:42:37
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to convert generator or iterator to list recursively. I wrote a code in below, but it looks naive and ugly, and may be dropped case in doctest. Q1. Help me good version. Q2. How to specify object is immutable or not? import itertools def isiterable(datum): return hasattr(datum, '__iter__') def issubscriptable(datum): return hasattr(datum, "__getitem__") def eagerlize(obj): """ Convert generator or iterator to list recursively. return a eagalized object of given obj. This works but, whether it return a new object, break given one. test

Convert from ASCII code to string in MATLAB

匿名 (未验证) 提交于 2019-12-03 08:42:37
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: If I have a string in matlab, I can convert it to a vector of ASCII codes using double : >> my_string = 'asd'; >> double(my_string) ans = 97 115 100 How can I go back the other way? i.e., if I have an ASCII code in a MATLAB vector, how can I create the corresponding string? e.g ascii_codes = [97 115 100]; should be converted to... my_string = 'asd' 回答1: How about char ( documentation )? Eg char(ascii_codes) ? 回答2: A great alternative to the char function, in my opinion, is the native2unicode function. It handles many different encoding

Convert a JSON NSData to NSDictionary

匿名 (未验证) 提交于 2019-12-03 08:41:19
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm using an API service of a web service and it is written in their description that they send JSON data wich also matches in my opinion with the response I get from it. Here a part of it which I got from the NSURLConnection-Delegate (connection didReceiveData: (NSData *) data) and converted in a NSString using: NSLog(@"response: %@", [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]); Here the snippet: {"scans": { "Engine1“: { "detected": false, "version": "1.3.0.4959", "result": null, "update": "20140521" }, "Engine2“: {

How to convert string to object in Angularjs [duplicate]

匿名 (未验证) 提交于 2019-12-03 08:41:19
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: Parse JSON in JavaScript? [duplicate] 16 answers I have a string like : $scope.text = '"{\"firstName\":\"John\",\"age\":454 }"'; and I want to convert to js object: $scope.tmp = {"firstName":"John","age":454 }; Note: JSON.parse() doesn't work!! It's my sample in codepen 回答1: You can do it with angular.fromJson() in your sample, it would have been $scope.tmp = angular.fromJson($scope.text); The difference between JSON.Parse() and angular.fromJson , is that angular will check to make sure a string is

XCode Convert to ARC, Create universal binary fails with error of “can&#039;t figure out the architecture type of”

匿名 (未验证) 提交于 2019-12-03 08:41:19
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm attempting to convert an iOS (pure Objective-C) project to ARC. The conversion fails at the octest target CreateUniversalBinary stage with the following error. The project and target architecture build settings look correct to me so I am struggling to understand why this is failing: /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/lipo: can't figure out the architecture type of: /Users/andybowskill/Library/Developer/Xcode/DerivedData/Make-Up_Kit-axtbxqtkmnlfmlcafkoetwqmeufc/Build/Intermediates/Make

PySpark dataframe convert unusual string format to Timestamp

匿名 (未验证) 提交于 2019-12-03 08:39:56
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using PySpark through Spark 1.5.0. I have an unusual String format in rows of a column for datetime values. It looks like this: Row[(daytetime='2016_08_21 11_31_08')] Is there a way to convert this unorthodox yyyy_mm_dd hh_mm_dd format into a Timestamp? Something that can eventually come along the lines of df = df.withColumn("date_time",df.daytetime.astype('Timestamp')) I had thought that Spark SQL functions like regexp_replace could work, but of course I need to replace _ with - in the date half and _ with : in the time part. I was