continue

Is there a difference between `continue` and `pass` in a for loop in python?

不打扰是莪最后的温柔 提交于 2019-11-26 23:30:22
Is there any significant difference between the two python keywords continue and pass like in the examples for element in some_list: if not element: pass and for element in some_list: if not element: continue I should be aware of? Sven Marnach Yes, they do completely different things. pass simply does nothing, while continue goes on with the next loop iteration. In your example, the difference would become apparent if you added another statement after the if : After executing pass , this further statement would be executed. After continue , it wouldn't. >>> a = [0, 1, 2] >>> for element in a:

Why are “continue” statements bad in JavaScript? [closed]

血红的双手。 提交于 2019-11-26 22:51:59
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 3 months ago . In the book Javascript: The Good Parts by Douglas Crockford, this is all the author has to say about the continue Statement: The continue statement jumps to the top of the loop. I have never seen a piece of code that was not improved by refactoring it to remove the continue

hibernate 反射框架(自用)

痞子三分冷 提交于 2019-11-26 21:49:21
hibernate 只需要操作对象就可以对数据库的数据进行“增删改查”。用了短时间后,感觉依旧存在很大的冗余。正因为这个,我的反射框架就出现了。因为自用,下面只贴出代码,不做解释。有兴趣的可以来看看一起研究一下,如有问题可私聊探讨。 反射基类 SQLSuper /** * 给对象做反射并且定于返回HQL语句方法的抽象类 * @author vincent Mao * */ public abstract class SQLSuper { /** * */ protected StringBuffer SQL; public StringBuffer getSQL() { return SQL; } public void setSQL(StringBuffer sQL) { SQL = sQL; } /** * 根据传入的实体对象and条件集合and排序对象返回HQL语句 * @param obj 经过重新封装的实体类 * @param condition 条件集合 * @param orderBy 排序对象 * @return HQL */ public abstract String getSQL(Object obj , List condition,OrderBy orderBy); /** * 返回所有类的名字 * @param tables * @return List

Nested jQuery.each() - continue/break

微笑、不失礼 提交于 2019-11-26 19:56:38
问题 Consider the following code: var sentences = [ 'Lorem ipsum dolor sit amet, consectetur adipiscing elit.', 'Vivamus aliquet nisl quis velit ornare tempor.', 'Cras sit amet neque ante, eu ultrices est.', 'Integer id lectus id nunc venenatis gravida nec eget dolor.', 'Suspendisse imperdiet turpis ut justo ultricies a aliquet tortor ultrices.' ]; var words = ['ipsum', 'amet', 'elit']; $(sentences).each(function() { var s = this; alert(s); $(words).each(function(i) { if (s.indexOf(this) > -1) {

How do I do a “break” or “continue” when in a functional loop within Kotlin?

▼魔方 西西 提交于 2019-11-26 19:41:08
问题 In Kotlin, I cannot do a break or continue within a function loop and my lambda -- like I can from a normal for loop. For example, this does not work: (1..5).forEach { continue@forEach // not allowed, nor break@forEach } There are old documentation that mentions this being available but it appears it was never implemented. What is the best way to get the same behavior when I want to continue or break from within the lambda? Note: this question is intentionally written and answered by the

Example use of “continue” statement in Python?

自作多情 提交于 2019-11-26 18:36:57
The definition of the continue statement is: The continue statement continues with the next iteration of the loop. I can't find any good examples of code. Could someone suggest some simple cases where continue is necessary? Snehal Parmar Here's a simple example: for letter in 'Django': if letter == 'D': continue printf("Current Letter: {letter}") Output will be: Current Letter: j Current Letter: a Current Letter: n Current Letter: g Current Letter: o It continues to the next iteration of the loop. I like to use continue in loops where there are a lot of contitions to be fulfilled before you

Please explain the usage of Labeled Statements

白昼怎懂夜的黑 提交于 2019-11-26 17:29:07
问题 Is breaking and continuing the only uses of labeled statements in Java? When have you used Labeled Statements in your programs? Sorry the code snippet has been deleted. I am splitting the question 回答1: JLS 14.7 Labeled statements (edited for clarity) Statements may have label prefixes ( Identifier : Statement ). The Identifier is declared to be the label of the immediately contained Statement . Unlike C and C++, the Java programming language has no goto statement; identifier statement labels

Difference between break and continue statement

北战南征 提交于 2019-11-26 15:40:35
Can anyone tell me the difference between break and continue statements? Xn0vv3r break leaves a loop, continue jumps to the next iteration. Jay See Branching Statements for more details and code samples: break The break statement has two forms: labeled and unlabeled. You saw the unlabeled form in the previous discussion of the switch statement. You can also use an unlabeled break to terminate a for, while, or do-while loop [...] An unlabeled break statement terminates the innermost switch, for, while, or do-while statement, but a labeled break terminates an outer statement. continue The

环境小硕的转行之路-6-第二次作业:有管理员模式的购物车

天涯浪子 提交于 2019-11-26 12:22:56
前几天由于过敏躺尸了两周,感觉都快废了。想要再次跨考计算机的计划遭到了家人的激烈反对。最后不了了之,对本行业越来越失望,希望通过这三年的自学成功跳行。 这次作业多学了好多东西才做出来 深感码力不足,if-else循环用的太多了。即便刚学了函数,还是不知道使用函数精简代码的套路。希望后续课程有作补充。 作业要求 一、购物模式: 1.顾客输入薪水后打印商品列表 2.顾客可以根据商品列表的下标购买商品 3.若薪水不足支付购买的商品会报错 4.顾客退出的时候打印购买的商品列表并显示余额退出 二、管理员模式 1.在输入薪水的时候输入:administrator即可进入管理员模式 2.可根据商品的编号修改商品名称、价格 3.可添加新的商品 4.最后把修改后的商品数据写入商品文本中 前期准备工作 在源码同一文件夹下创建一商品文本内容如下: 源代码 1 #author : negu 2 # -*- coding: utf-8 -*- 3 def list_loop(list):#展示商品列表的函数 4 for index,i in enumerate(list):#把每项的下标取出来 5 if index == 0: 6 continue 7 print(index,i) 8 view_list = ['blank']#商品列表,第一项占位,让商品序号从1开始。 9 with open(

Skip multiple iterations in loop

戏子无情 提交于 2019-11-26 09:09:03
问题 I have a list in a loop and I want to skip 3 elements after look has been reached. In this answer a couple of suggestions were made but I fail to make good use of them: song = [\'always\', \'look\', \'on\', \'the\', \'bright\', \'side\', \'of\', \'life\'] for sing in song: if sing == \'look\': print sing continue continue continue continue print \'a\' + sing print sing Four times continue is nonsense of course and using four times next() doesn\'t work. The output should look like: always look